- A. Geometrical isomerism
- B. Linkage isomerism
- C. Ionization isomerism
- D. Coordination isomerism
Correct answer & explanation hidden
Log in to view solution →- A. CrO4^2-
- B. MnO4^2-
- C. MnO4^-
- D. Cr2O7^2-
Correct answer & explanation hidden
Log in to view solution →- A. (1) iv v ii i
- B. (2) iii v i ii
- C. (3) iv i ii iii
- D. (4) i ii iii iv
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Log in to view solution →- A. Tetranuclear
- B. Dinuclear
- C. Trinuclear
- D. Mononuclear
Correct answer & explanation hidden
Log in to view solution →- A. Square planar geometry and diamagnetic
- B. Tetrahedral geometry and paramagnetic
- C. Square planar geometry and paramagnetic
- D. Tetrahedral geometry and diamagnetic
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Log in to view solution →- A. HNO3, NO, N2, NH4Cl
- B. NH4Cl, N2, NO, HNO3
- C. HNO3, NH4Cl, NO, N2
- D. HNO3, NO, NH4Cl, N2
Correct answer & explanation hidden
Log in to view solution →- A. HNO3, NO, N2, NH4Cl
- B. NH4Cl, N2, NO, HNO3
- C. HNO3, NH4Cl, NO, N2
- D. HNO3, NO, NH4Cl, N2
Correct answer & explanation hidden
Log in to view solution →- A. Ga
- B. In
- C. B
- D. Al
Correct answer & explanation hidden
Log in to view solution →- A. Ga
- B. In
- C. B
- D. Al
Correct answer & explanation hidden
Log in to view solution →- A. Fe
- B. Cu
- C. Mg
- D. Zn
Correct answer & explanation hidden
Log in to view solution →- A. 7 : 10
- B. 2 : 5
- C. 10 : 7
- D. 5 : 7
Correct answer & explanation hidden
Log in to view solution →- A. B < Al < In < Ga < Tl
- B. B < Ga < Al < In < Tl
- C. B < Ga < Al < Tl < In
- D. B < Al < Ga < In < Tl
Correct answer & explanation hidden
Log in to view solution →- A. All form monobasic oxyacids
- B. Chlorine has the highest electron-gain enthalpy
- C. All but fluorine show positive oxidation states
- D. All are oxidizing agents
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Log in to view solution →- A. One
- B. Three
- C. Four
- D. Two
Correct answer & explanation hidden
Log in to view solution →- A. Dichloromethyl cation (CHCl2+)
- B. Dichlorocarbene (:CCl2)
- C. Dichloromethyl anion (CHCl2-)
- D. Formyl cation (CHO+)
Correct answer & explanation hidden
Log in to view solution →- A. Formation of intramolecular H-bonding
- B. Formation of intermolecular H-bonding
- C. More extensive association of carboxylic acid via van der Waals force of attraction
- D. Formation of carboxylate ion
Correct answer & explanation hidden
Log in to view solution →- A. CH3CH2OH and I2
- B. CH3CH(CH3)OH and I2
- C. C6H5CH(OH)CH3 and I2
- D. CH2=CH-CH2OH and I2
Correct answer & explanation hidden
Log in to view solution →- A. N2O5
- B. NO
- C. N2O
- D. NO2
Correct answer & explanation hidden
Log in to view solution →- A. C2H5OH, C2H6, C2H5Cl
- B. C2H5OH, C2H5ONa, C2H5Cl
- C. C2H5Cl, C2H6, C2H5OH
- D. C2H5OH, C2H5Cl, C2H5ONa
Correct answer & explanation hidden
Log in to view solution →- A. C2H5OH, C2H6, C2H5Cl
- B. C2H5OH, C2H5ONa, C2H5Cl
- C. C2H5Cl, C2H6, C2H5OH
- D. C2H5OH, C2H5Cl, C2H5ONa
Correct answer & explanation hidden
Log in to view solution →- A. m-bromotoluene
- B. p-bromotoluene
- C. 3-bromo-2,4,6-trichlorotoluene
- D. o-bromotoluene
Correct answer & explanation hidden
Log in to view solution →- A. m-bromotoluene
- B. p-bromotoluene
- C. 3-bromo-2,4,6-trichlorotoluene
- D. o-bromotoluene
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Log in to view solution →- A. CH ≡ CH
- B. CH4
- C. CH3 – CH3
- D. CH2 = CH2
Correct answer & explanation hidden
Log in to view solution →- A. HC ≡ C – C ≡ CH
- B. CH3 – CH = CH – CH3
- C. CH2 = CH – CH = CH2
- D. CH2 = CH – C ≡ CH
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Log in to view solution →- A. 1.4
- B. 4.4
- C. 2.8
- D. 3.0
Correct answer & explanation hidden
Log in to view solution →- A. Amylopectin have 1 -> 4 alpha-linkage and 1 -> 6 alpha-linkage
- B. Amylose is made up of glucose and galactose
- C. Amylopectin have 1 -> 4 alpha-linkage and 1 -> 6 beta-linkage
- D. Amylose have 1 -> 4 alpha-linkage and 1 -> 6 beta-linkage
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Log in to view solution →- A. Aniline
- B. Glycine
- C. Benzoic acid
- D. Acetanilide
Correct answer & explanation hidden
Log in to view solution →- A. They contain covalent bonds between various linear polymer chains.
- B. They contain strong covalents bonds in their polymer chains.
- C. Examples are bakelite and melamine.
- D. They are formed from bi- and tri-functional monomers.
Correct answer & explanation hidden
Log in to view solution →- A. Inspite of substituents nitro group always goes to only m-position.
- B. In acidic (strong) medium aniline is present as anilinium ion.
- C. In absence of substituents nitro group always goes to m-position.
- D. In electrophilic substitution reactions amino group is meta directive.
Correct answer & explanation hidden
Log in to view solution →- A. CH3CH2CH2CHO, CH3CH2OH
- B. CH3COCH3, CH3OH
- C. CH3CH(OH)CH3, CH3CH2OH
- D. CH3CH2CH2CHO, COOH
Correct answer & explanation hidden
Log in to view solution →- A. MgO
- B. CaO
- C. BaO
- D. BeO
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Log in to view solution →- A. b
- B. c
- C. d
- D. a
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Log in to view solution →- A. The magnitude of the charge on the ion alone
- B. The sign of charge on the ion alone
- C. Both magnitude and sign of the charge on the ion
- D. Size of the ion alone
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Log in to view solution →- A. NH3
- B. CO2
- C. O2
- D. H2
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Log in to view solution →- A. 1.08 × 10^–10 mol^2 L^–2
- B. 1.08 × 10^–8 mol^2 L^–2
- C. 1.08 × 10^–14 mol^2 L^–2
- D. 1.08 × 10^–12 mol^2 L^–2
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Log in to view solution →- A. 16, 5, 2
- B. 5, 16, 2
- C. 2, 16, 5
- D. 2, 5, 16
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Log in to view solution →- A. 16 5 2
- B. 5 16 2
- C. 2 16 5
- D. 2 5 16
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Log in to view solution →- A. Low temperature and high pressure
- B. High temperature and low pressure
- C. High temperature and high pressure
- D. Low temperature and low pressure
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Log in to view solution →- A. Is halved
- B. Remains unchanged
- C. Is tripled
- D. Is doubled
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Log in to view solution →- A. 200 kJ mol–1
- B. 400 kJ mol–1
- C. 800 kJ mol–1
- D. 100 kJ mol–1
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Log in to view solution →- A. Density of the gas molecules
- B. Forces of attraction between the gas molecules
- C. Electric field present between the gas molecules
- D. Volume of the gas molecules
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Log in to view solution →- A. 18 mL of water
- B. 10–3 mol of water
- C. 0.00224 L of water vapours at 1 atm and 273 K
- D. 0.18 g of water
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Log in to view solution →- A. The rate of a first-order reaction does not depend on reactant concentrations; the rate of a second-order reaction does depend on reactant concentrations
- B. The rate of a first-order reaction does depend on reactant concentrations; the rate of a second-order reaction does not depend on reactant concentrations
- C. A first-order reaction can be catalyzed; a second-order reaction cannot be catalyzed
- D. The half-life of a first-order reaction does not depend on [A]0; the half-life of a second-order reaction does depend on [A]0
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Log in to view solution →- A. BeH2 < CaH2 < BaH2
- B. BaH2 < BeH2 < CaH2
- C. BeH2 < BaH2 < CaH2
- D. CaH2 < BeH2 < BaH2
Correct answer & explanation hidden
Log in to view solution →- A. BrO3-
- B. HBrO
- C. Br2
- D. BrO4-
Correct answer & explanation hidden
Log in to view solution →- A. NO
- B. CN
- C. CN+
- D. CN-
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Log in to view solution →- A. Total orbital angular momentum of electron in 's' orbital is equal to zero
- B. The value of m for dz2 is zero
- C. The electronic configuration of N atom is 1s2 2s2 2px1 2py1 2pz1
- D. An orbital is designated by three quantum numbers while an electron in an atom is designated by four quantum numbers
Correct answer & explanation hidden
Log in to view solution →- A. 3/2
- B. 1/2
- C. 3sqrt(3)/4sqrt(2)
- D. 4sqrt(3)/3sqrt(2)
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Log in to view solution →- A. Mg2X3
- B. Mg3X2
- C. Mg2X
- D. MgX2
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Log in to view solution →- A. Chief cells
- B. Parietal cells
- C. Goblet cells
- D. Mucous cells
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Log in to view solution →- A. a(iii), b(ii), c(i)
- B. a(ii), b(iii), c(i)
- C. a(i), b(iii), c(ii)
- D. a(i), b(ii), c(iii)
Correct answer & explanation hidden
Log in to view solution →- A. Binds to troponin to remove the masking of active sites on actin for myosin.
- B. Prevents the formation of bonds between the myosin cross bridges and the actin filament.
- C. Detaches the myosin head from the actin filament.
- D. Activates the myosin ATPase by binding to it.
Correct answer & explanation hidden
Log in to view solution →- A. Binds to troponin to remove the masking of active sites on actin for myosin.
- B. Prevents the formation of bonds between the myosin cross bridges and the actin filament.
- C. Detaches the myosin head from the actin filament.
- D. Activates the myosin ATPase by binding to it.
Correct answer & explanation hidden
Log in to view solution →- A. Anthracis
- B. Emphysema
- C. Botulism
- D. Silicosis
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Log in to view solution →- A. Epinephrine
- B. Estriol
- C. Estradiol
- D. Ecdysone
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Log in to view solution →- A. Medulla oblongata : controls respiration and cardiovascular reflexes.
- B. Corpus callosum : band of fibers connecting left and right cerebral hemispheres.
- C. Hypothalamus : production of releasing hormones and regulation of temperature, hunger and thirst.
- D. Limbic system : consists of fibre tracts that interconnect different regions of brain; controls movement.
Correct answer & explanation hidden
Log in to view solution →- A. ligaments attached to the ciliary body
- B. smooth muscles attached to the ciliary body
- C. smooth muscles attached to the iris
- D. ligaments attached to the iris
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Log in to view solution →- A. Aldosterone and Prolactin
- B. Parathyroid hormone and Prolactin
- C. Estrogen and Parathyroid hormone
- D. Progesterone and Aldosterone
Correct answer & explanation hidden
Log in to view solution →- A. hCG, hPL, progestogens, prolactin
- B. hCG, progestogens, estrogens, glucocorticoids
- C. hCG, hPL, progestogens, estrogens
- D. hCG, hPL, estrogens, relaxin, oxytocin
Correct answer & explanation hidden
Log in to view solution →- A. blocks estrogen receptors in the uterus, preventing eggs from getting implanted.
- B. is a post-coital contraceptive.
- C. is an IUD.
- D. increases the concentration of estrogen and prevents ovulation in females.
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Log in to view solution →- A. blocks estrogen receptors in the uterus, preventing eggs from getting implanted.
- B. is a post-coital contraceptive.
- C. is an IUD.
- D. increases the concentration of estrogen and prevents ovulation in females.
Correct answer & explanation hidden
Log in to view solution →- A. ectoderm and mesoderm
- B. ectoderm and endoderm
- C. mesoderm and trophoblast
- D. endoderm and mesoderm
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Log in to view solution →- A. In spermiogenesis spermatids are formed, while in spermiation spermatozoa are formed.
- B. In spermiogenesis spermatozoa are formed, while in spermiation spermatozoa are released from sertoli cells into the cavity of seminiferous tubules.
- C. In spermiogenesis spermatozoa from sertoli cells are released into the cavity of seminiferous tubules, while in spermiation spermatozoa are formed.
- D. In spermiogenesis spermatozoa are formed, while in spermiation spermatids are formed.
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Log in to view solution →- A. an operator
- B. a promoter
- C. an enhancer
- D. structural genes
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Log in to view solution →- A. Only daughters
- B. Both sons and daughters
- C. Only grandchildren
- D. Only sons
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Log in to view solution →- A. Multiple step mutations
- B. Minor mutations
- C. Phenotypic variations
- D. Saltation
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Log in to view solution →- A. AGGUAUCGCAU
- B. UCCAUAGCGUA
- C. ACCUAUGCGAU
- D. UGGTUT CGCAT
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Log in to view solution →- A. a-iii, b-ii, c-i
- B. a-iii, b-i, c-ii
- C. a-ii, b-iii, c-i
- D. a-i, b-iii, c-ii
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Log in to view solution →- A. Elephantiasis
- B. Amoebiasis
- C. Ringworm disease
- D. Ascariasis
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Log in to view solution →- A. Elephantiasis
- B. Amoebiasis
- C. Ringworm disease
- D. Ascariasis
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Log in to view solution →- A. Vitamin D
- B. Vitamin E
- C. Vitamin B12
- D. Vitamin A
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Log in to view solution →- A. Vitamin D
- B. Vitamin E
- C. Vitamin B12
- D. Vitamin A
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Log in to view solution →- A. Psoriasis
- B. Vitiligo
- C. Alzheimer's disease
- D. Rheumatoid arthritis
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Log in to view solution →- A. Psoriasis
- B. Vitiligo
- C. Alzheimer's disease
- D. Rheumatoid arthritis
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Log in to view solution →- A. Forelimbs of man, bat and cheetah
- B. Eye of octopus, bat and man
- C. Brain of bat, man and cheetah
- D. Heart of bat, man and cheetah
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Log in to view solution →- A. Homology
- B. Adaptive radiation
- C. Convergent evolution
- D. Analogy
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Log in to view solution →- A. b, c and e
- B. a, c and e
- C. b, d and e
- D. a, b and c
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Log in to view solution →- A. Inflammation of bronchioles; Decreased respiratory surface
- B. Decreased respiratory surface; Inflammation of bronchioles
- C. Increased respiratory surface; Inflammation of bronchioles
- D. Increased number of bronchioles; Increased respiratory surface
Correct answer & explanation hidden
Log in to view solution →- A. a-iii, b-i, c-ii
- B. a-ii, b-i, c-iii
- C. a-i, b-ii, c-iii
- D. a-i, b-iii, c-ii
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Log in to view solution →- A. a-iii, b-ii, c-i, d-iv
- B. a-iv, b-iii, c-ii, d-i
- C. a-i, b-iv, c-ii, d-iii
- D. a-iii, b-i, c-iv, d-ii
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Log in to view solution →- A. (1) iii ii i iv
- B. (2) iv iii ii i
- C. (3) i iv ii iii
- D. (4) iii i iv ii
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Log in to view solution →- A. Commensalism
- B. Amensalism
- C. Parasitism
- D. Mutualism
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Log in to view solution →- A. Commensalism
- B. Amensalism
- C. Parasitism
- D. Mutualism
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Log in to view solution →- A. Wildlife safari parks
- B. Seed banks
- C. Botanical gardens
- D. Sacred groves
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Log in to view solution →- A. (1) ii i iii iv
- B. (2) i ii iv iii
- C. (3) iii iv i ii
- D. (4) i iii iv ii
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Log in to view solution →- A. pre-reproductive individuals are more than the reproductive individuals.
- B. pre-reproductive individuals are less than the reproductive individuals.
- C. reproductive and pre-reproductive individuals are equal in number.
- D. reproductive individuals are less than the post-reproductive individuals.
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Log in to view solution →- A. Flowers
- B. Leaves
- C. Roots
- D. Latex
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Log in to view solution →- A. (1) iii ii iv i
- B. (2) iv i ii iii
- C. (3) ii iii i iv
- D. (4) i ii iii iv
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Log in to view solution →- A. (1) iv v ii iii
- B. (2) v iv i iii
- C. (3) v iv i ii
- D. (4) iv i ii iii
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Log in to view solution →- A. a-iv, b-v, c-ii, d-iii
- B. a-v, b-iv, c-i, d-iii
- C. a-v, b-iv, c-i, d-ii
- D. a-iv, b-i, c-ii, d-iii
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Log in to view solution →- A. Proteins and lipids
- B. Free ribosomes and RER
- C. Nucleic acids and SER
- D. DNA and RNA
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Log in to view solution →- A. Proteins and lipids
- B. Free ribosomes and RER
- C. Nucleic acids and SER
- D. DNA and RNA
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Log in to view solution →- A. Enzymes of TCA cycle are present in mitochondrial matrix
- B. Oxidative phosphorylation takes place in outer mitochondrial membrane
- C. Glycolysis operates as long as it is supplied with NAD that can pick up hydrogen atoms
- D. Glycolysis occurs in cytosol
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Log in to view solution →- A. Thecodont, Diphyodont, Homodont
- B. Pleurodont, Diphyodont, Heterodont
- C. Pleurodont, Monophyodont, Homodont
- D. Thecodont, Diphyodont, Heterodont
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Log in to view solution →- A. Lampbrush chromosomes – Diplotene bivalents
- B. Polytene chromosomes – Oocytes of amphibians
- C. Submetacentric chromosomes – L-shaped chromosomes
- D. Allosomes – Sex chromosomes
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Log in to view solution →- A. Protein folding
- B. Phospholipid synthesis
- C. Cleavage of signal peptide
- D. Protein glycosylation
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Log in to view solution →- A. Polysome
- B. Nucleosome
- C. Plastidome
- D. Polyhedral bodies
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Log in to view solution →- A. Earthworm
- B. Starfish
- C. Moth
- D. Tunicate
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Log in to view solution →- A. Macropus
- B. Psittacula
- C. Camelus
- D. Chelone
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Log in to view solution →- A. Presence of a boat shaped sternum on the 9th abdominal segment
- B. Presence of anal cerci
- C. Forewings with darker tegmina
- D. Presence of caudal styles
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Log in to view solution →- A. Presence of a boat shaped sternum on the 9th abdominal segment
- B. Presence of anal cerci
- C. Forewings with darker tegmina
- D. Presence of caudal styles
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Log in to view solution →- A. Amphibia
- B. Osteichthyes
- C. Aves
- D. Reptilia
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Log in to view solution →- A. Amphibia
- B. Osteichthyes
- C. Aves
- D. Reptilia
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Log in to view solution →- A. using flagella for locomotion
- B. having two types of nuclei
- C. using pseudopodia for capturing prey
- D. having a contractile vacuole for removing excess water
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Log in to view solution →- A. Dinoflagellates
- B. Euglenoids
- C. Cyanobacteria
- D. Diatoms
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Log in to view solution →- A. Fatty acid breakdown
- B. Activation of amino acid
- C. Respiration in bacteria
- D. Formation of secretory vesicles
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Log in to view solution →- A. Dumb-bell shaped
- B. Barrel shaped
- C. Rectangular
- D. Kidney shaped
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Log in to view solution →- A. Pachytene
- B. Zygotene
- C. Diakinesis
- D. Diplotene
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Log in to view solution →- A. Hydroxyl and methyl
- B. Carbonyl and hydroxyl
- C. Carbonyl and phosphate
- D. Carbonyl and methyl
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Log in to view solution →- A. Saccharomyces
- B. Oscillatoria
- C. Nostoc
- D. Mycobacterium
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Log in to view solution →- A. Temperature
- B. CO2 concentration
- C. O2 concentration
- D. Light
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Log in to view solution →- A. Larger nucleoli are present in dividing cells
- B. It is a site for active ribosomal RNA synthesis
- C. It takes part in spindle formation
- D. It is a membrane-bound structure
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Log in to view solution →- A. ATP
- B. Oxygen
- C. NADPH
- D. NADH
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Log in to view solution →- A. Magnesium
- B. Calcium
- C. Potassium
- D. Sodium
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Log in to view solution →- A. Magnesium
- B. Calcium
- C. Potassium
- D. Sodium
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Log in to view solution →- A. Hydrilla
- B. Viola
- C. Banana
- D. Yucca
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Log in to view solution →- A. Hydrilla
- B. Viola
- C. Banana
- D. Yucca
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Log in to view solution →- A. -120°C
- B. -160°C
- C. -196°C
- D. -80°C
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Log in to view solution →- A. -120°C
- B. -160°C
- C. -196°C
- D. -80°C
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Log in to view solution →- A. Green sulphur bacteria
- B. Chara
- C. Cycas
- D. Nostoc
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Log in to view solution →- A. Green sulphur bacteria
- B. Chara
- C. Cycas
- D. Nostoc
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Log in to view solution →- A. Fusion of two male gametes of a pollen tube with two different eggs
- B. Syngamy and triple fusion
- C. Fusion of two male gametes with one egg
- D. Fusion of one male gamete with two polar nuclei
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Log in to view solution →- A. It functions as an enzyme.
- B. It is the final electron acceptor for anaerobic respiration.
- C. It is a nucleotide source for ATP synthesis.
- D. It functions as an electron carrier.
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Log in to view solution →- A. Ferric
- B. Both ferric and ferrous
- C. Free element
- D. Ferrous
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Log in to view solution →- A. Franklin Stahl coined the term 'linkage'
- B. Transduction was discovered by S. Altman
- C. Spliceosomes take part in translation
- D. Punnett square was developed by a British scientist
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Log in to view solution →- A. Alec Jeffreys - Streptococcus pneumoniae
- B. Francois Jacob and Jacques Monod - Lac operon
- C. Matthew Meselson and F. Stahl - Pisum sativum
- D. Alfred Hershey and Martha Chase - TMV
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Log in to view solution →- A. Fungus
- B. Virus
- C. Plant
- D. Bacterium
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Log in to view solution →- A. Meiotic divisions
- B. Parthenogenesis
- C. Parthenocarpy
- D. Mitotic divisions
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Log in to view solution →- A. 0.79 W
- B. 1.13 W
- C. 2.74 W
- D. 0.43 W
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Log in to view solution →- A. 7.14 A
- B. 11.32 A
- C. 14.76 A
- D. 5.98 A
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Log in to view solution →- A. 40 Ω
- B. 500 Ω
- C. 250 Ω
- D. 25 Ω
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Log in to view solution →- A. The current source
- B. The induced electric field due to the changing magnetic field
- C. The lattice structure of the material of the rod
- D. The magnetic field
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Log in to view solution →- A. The current source
- B. The induced electric field due to the changing magnetic field
- C. The lattice structure of the material of the rod
- D. The magnetic field
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Log in to view solution →- A. Reflected light is polarised with its electric vector parallel to the plane of incidence
- B. tan i = 1/μ
- C. sin i = 1/μ
- D. Reflected light is polarised with its electric vector perpendicular to the plane of incidence
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Log in to view solution →- A. 1.8 mm
- B. 1.7 mm
- C. 2.1 mm
- D. 1.9 mm
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Log in to view solution →- A. Small focal length and large diameter
- B. Small focal length and small diameter
- C. Large focal length and large diameter
- D. Large focal length and small diameter
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Log in to view solution →- A. 30 cm away from the mirror
- B. 36 cm towards the mirror
- C. 30 cm towards the mirror
- D. 36 cm away from the mirror
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Log in to view solution →- A. -z direction
- B. -x direction
- C. -y direction
- D. +z direction
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Log in to view solution →- A. 0.138 H
- B. 13.89 H
- C. 1.389 H
- D. 138.88 H
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Log in to view solution →- A. 60°
- B. Zero
- C. 30°
- D. 45°
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Log in to view solution →- A. 60°
- B. Zero
- C. 30°
- D. 45°
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Log in to view solution →- A. 0.5
- B. 0.4
- C. 0.8
- D. 0.25
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Log in to view solution →- A. 3D/2
- B. 5D/4
- C. 7D/5
- D. D
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Log in to view solution →- A. Wc > Wb > Wa
- B. Wa > Wc > Wb
- C. Wb > Wa > Wc
- D. Wa > Wb > Wc
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Log in to view solution →- A. Rolling friction is smaller than sliding friction.
- B. Coefficient of sliding friction has dimensions of length.
- C. Frictional force opposes the relative motion.
- D. Limiting value of static friction is directly proportional to normal reaction.
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Log in to view solution →- A. 2 m/s, 4 m/s
- B. 1.5 m/s, 3 m/s
- C. 1 m/s, 3.5 m/s
- D. 1 m/s, 3 m/s
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Log in to view solution →- A. a = g cosec θ
- B. a = g tan θ
- C. a = g cos θ
- D. a = g sin θ
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Log in to view solution →- A. -8i - 4j - 7k
- B. -7i - 4j - 8k
- C. -7i - 8j - 4k
- D. -4i - j - 8k
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Log in to view solution →- A. 0.521 cm
- B. 0.529 cm
- C. 0.053 cm
- D. 0.525 cm
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Log in to view solution →- A. 0.521 cm
- B. 0.529 cm
- C. 0.053 cm
- D. 0.525 cm
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Log in to view solution →- A. Graph showing I constant with respect to n
- B. Graph showing I increasing linearly with n
- C. Graph showing I decreasing with n
- D. Graph showing I proportional to square root of n
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Log in to view solution →- A. Violet – Yellow – Orange – Silver
- B. Green – Orange – Violet – Gold
- C. Yellow – Green – Violet – Gold
- D. Yellow – Violet – Orange – Silver
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Log in to view solution →- A. 10
- B. 9
- C. 20
- D. 11
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Log in to view solution →- A. IB = 40 μA, IC = 10 mA, β = 250
- B. IB = 40 μA, IC = 5 mA, β = 125
- C. IB = 20 μA, IC = 5 mA, β = 250
- D. IB = 25 μA, IC = 5 mA, β = 200
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Log in to view solution →- A. A·B
- B. A+B
- C. A·B + A·B
- D. A·B + A·B
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Log in to view solution →- A. Affects only reverse resistance
- B. Affects the overall V-I characteristics of p-n junction
- C. Does not affect resistance of p-n junction
- D. Affects only forward resistance
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Log in to view solution →- A. λ0 / (1 + eE0t / mV0)
- B. λ0
- C. λ0 t
- D. λ0 (1 + eE0t / mV0)
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Log in to view solution →- A. 1 : 1
- B. 1 : -2
- C. 2 : -1
- D. 1 : -1
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Log in to view solution →- A. 1 : 1
- B. 1 : -2
- C. 2 : -1
- D. 1 : -1
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Log in to view solution →- A. 20
- B. 15
- C. 30
- D. 10
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Log in to view solution →- A. 20
- B. 15
- C. 30
- D. 10
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Log in to view solution →- A. 1 : 2
- B. 2 : 1
- C. 4 : 1
- D. 1 : 4
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Log in to view solution →- A. 330 m/s
- B. 300 m/s
- C. 350 m/s
- D. 339 m/s
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Log in to view solution →- A. Independent of the distance between the plates
- B. Inversely proportional to the distance between the plates
- C. Proportional to the square root of the distance between the plates
- D. Linearly proportional to the distance between the plates
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Log in to view solution →- A. Smaller
- B. Equal
- C. 10 times greater
- D. 5 times greater
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Log in to view solution →- A. 2π s
- B. 1 s
- C. 2 s
- D. π s
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Log in to view solution →- A. 2/5
- B. 2/7
- C. 1/3
- D. 2/3
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Log in to view solution →- A. 13.2 cm
- B. 16 cm
- C. 12.5 cm
- D. 8 cm
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Log in to view solution →- A. 13.2 cm
- B. 16 cm
- C. 12.5 cm
- D. 8 cm
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Log in to view solution →- A. 2.508 × 10⁴ K
- B. 1.254 × 10⁴ K
- C. 5.016 × 10⁴ K
- D. 8.360 × 10⁴ K
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Log in to view solution →- A. 26.8%
- B. 12.5%
- C. 6.25%
- D. 20%
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Log in to view solution →- A. 3/4
- B. 81/256
- C. 256/81
- D. 4/3
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Log in to view solution →- A. 9 F
- B. F
- C. 4 F
- D. 6 F
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Log in to view solution →- A. r³
- B. r⁴
- C. r⁵
- D. r²
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Log in to view solution →- A. 104.3 J
- B. 84.5 J
- C. 42.2 J
- D. 208.7 J
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Log in to view solution →- A. Angular velocity
- B. Angular momentum
- C. Rotational kinetic energy
- D. Moment of inertia
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Log in to view solution →- A. 7 : 10
- B. 2 : 5
- C. 10 : 7
- D. 5 : 7
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Log in to view solution →- A. K_A < K_B < K_C
- B. K_B > K_A > K_C
- C. K_B < K_A < K_C
- D. K_A > K_B > K_C
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Log in to view solution →- A. KA < KB < KC
- B. KB > KA > KC
- C. KB < KA < KC
- D. KA > KB > KC
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Log in to view solution →- A. Raindrops will fall faster
- B. ‘g’ on the Earth will not change
- C. Time period of a simple pendulum on the Earth would decrease
- D. Walking on the ground would become more difficult
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