- A. 2.508 × 10^4 K
- B. 5.016 × 10^4 K
- C. 8.360 × 10^4 K
- D. 1.254 × 10^4 K
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Log in to view solution →- A. 26.8%
- B. 6.25%
- C. 20%
- D. 12.5%
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Log in to view solution →- A. 13.2 cm
- B. 12.5 cm
- C. 8 cm
- D. 16 cm
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Log in to view solution →- A. 7.14 A
- B. 14.76 A
- C. 5.98 A
- D. 11.32 A
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Log in to view solution →- A. 0.79 W
- B. 2.74 W
- C. 0.43 W
- D. 1.13 W
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Log in to view solution →- A. 0.79 W
- B. 2.74 W
- C. 0.43 W
- D. 1.13 W
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Log in to view solution →- A. 40 Ω
- B. 250 Ω
- C. 25 Ω
- D. 500 Ω
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Log in to view solution →- A. 40 Ω
- B. 250 Ω
- C. 25 Ω
- D. 500 Ω
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Log in to view solution →- A. the current source
- B. the lattice structure of the material of the rod
- C. the magnetic field
- D. the induced electric field due to the changing magnetic field
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Log in to view solution →- A. the current source
- B. the lattice structure of the material of the rod
- C. the magnetic field
- D. the induced electric field due to the changing magnetic field
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Log in to view solution →- A. affects only reverse resistance
- B. does not affect resistance of p-n junction
- C. affects only forward resistance
- D. affects the overall V – I characteristics of p-n junction
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Log in to view solution →- A. Reflected light is polarised with its electric vector parallel to the plane of incidence
- B. i = sin^-1(1/μ)
- C. Reflected light is polarised with its electric vector perpendicular to the plane of incidence
- D. i = tan^-1(1/μ)
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Log in to view solution →- A. small focal length and large diameter
- B. large focal length and large diameter
- C. large focal length and small diameter
- D. small focal length and small diameter
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Log in to view solution →- A. 20
- B. 30
- C. 10
- D. 15
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Log in to view solution →- A. 1 : 1
- B. 2 : -1
- C. 1 : -1
- D. 1 : -2
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Log in to view solution →- A. 1 : 2
- B. 4 : 1
- C. 1 : 4
- D. 2 : 1
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Log in to view solution →- A. 30 cm away from the mirror
- B. 30 cm towards the mirror
- C. 36 cm away from the mirror
- D. 36 cm towards the mirror
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Log in to view solution →- A. 60°
- B. 30°
- C. 45°
- D. zero
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Log in to view solution →- A. -z direction
- B. -y direction
- C. +z direction
- D. -x direction
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Log in to view solution →- A. 0·138 H
- B. 1·389 H
- C. 138·88 H
- D. 13·89 H
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Log in to view solution →- A. 10
- B. 20
- C. 11
- D. 9
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Log in to view solution →- A. Violet – Yellow – Orange – Silver
- B. Yellow – Green – Violet – Gold
- C. Yellow – Violet – Orange – Silver
- D. Green – Orange – Violet – Gold
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Log in to view solution →- A. 330 m/s
- B. 350 m/s
- C. 339 m/s
- D. 300 m/s
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Log in to view solution →- A. independent of the distance between the plates.
- B. proportional to the square root of the distance between the plates.
- C. linearly proportional to the distance between the plates.
- D. inversely proportional to the distance between the plates.
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Log in to view solution →- A. smaller
- B. 10 times greater
- C. 5 times greater
- D. equal
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Log in to view solution →- A. 2π s
- B. 2 s
- C. π s
- D. 1 s
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Log in to view solution →- A. 2π s
- B. 2 s
- C. π s
- D. 1 s
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Log in to view solution →- A. 4/3
- B. 81/256
- C. 3/4
- D. 256/81
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Log in to view solution →- A. 4/3
- B. 81/256
- C. 3/4
- D. 256/81
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Log in to view solution →- A. 9 F
- B. 4 F
- C. 6 F
- D. F
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Log in to view solution →- A. 9 F
- B. 4 F
- C. 6 F
- D. F
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Log in to view solution →- A. r^3
- B. r^5
- C. r^2
- D. r^4
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Log in to view solution →- A. 104.3 J
- B. 42.2 J
- C. 208.7 J
- D. 84.5 J
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Log in to view solution →- A. - 8i - 4j - 7k
- B. - 7i - 8j - 4k
- C. - 4i - j - 8k
- D. - 7i - 4j - 8k
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Log in to view solution →- A. 0.521 cm
- B. 0.053 cm
- C. 0.525 cm
- D. 0.529 cm
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Log in to view solution →- A. a = g/cos θ
- B. a = g cos θ
- C. a = g/sin θ
- D. a = g tan θ
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Log in to view solution →- A. 2 m/s, 4 m/s
- B. 1 m/s, 3.5 m/s
- C. 1 m/s, 3 m/s
- D. 1.5 m/s, 3 m/s
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Log in to view solution →- A. 0.5
- B. 0.8
- C. 0.25
- D. 0.4
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Log in to view solution →- A. 2/3 D
- B. 5/7 D
- C. D
- D. 4/5 D
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Log in to view solution →- A. W_C > W_B > W_A
- B. W_B > W_A > W_C
- C. W_A > W_B > W_C
- D. W_A > W_C > W_B
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Log in to view solution →- A. Rolling friction is smaller than sliding friction.
- B. Frictional force opposes the relative motion.
- C. Limiting value of static friction is directly proportional to normal reaction.
- D. Coefficient of sliding friction has dimensions of length.
Correct answer & explanation hidden
Log in to view solution →- A. Rolling friction is smaller than sliding friction.
- B. Frictional force opposes the relative motion.
- C. Limiting value of static friction is directly proportional to normal reaction.
- D. Coefficient of sliding friction has dimensions of length.
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Log in to view solution →- A. 7 : 10
- B. 10 : 7
- C. 5 : 7
- D. 2 : 5
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Log in to view solution →- A. 7 : 10
- B. 10 : 7
- C. 5 : 7
- D. 2 : 5
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Log in to view solution →- A. Angular velocity
- B. Rotational kinetic energy
- C. Moment of inertia
- D. Angular momentum
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Log in to view solution →- A. Angular velocity
- B. Rotational kinetic energy
- C. Moment of inertia
- D. Angular momentum
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Log in to view solution →- A. Raindrops will fall faster.
- B. Time period of a simple pendulum on the Earth would decrease.
- C. Walking on the ground would become more difficult.
- D. ‘g’ on the Earth will not change.
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Log in to view solution →- A. NH3
- B. O2
- C. H2
- D. CO2
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Log in to view solution →- A. 1·08 × 10^–10 mol^2 L^–2
- B. 1·08 × 10^–14 mol^2 L^–2
- C. 1·08 × 10^–12 mol^2 L^–2
- D. 1·08 × 10^–8 mol^2 L^–2
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Log in to view solution →- A. The magnitude of the charge on the ion alone
- B. Both magnitude and sign of the charge on the ion
- C. Size of the ion alone
- D. The sign of charge on the ion alone
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Log in to view solution →- A. Fe
- B. Mg
- C. Zn
- D. Cu
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Log in to view solution →- A. B < Al < In < Ga < Tl
- B. B < Ga < Al < Tl < In
- C. B < Al < Ga < In < Tl
- D. B < Ga < Al < In < Tl
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Log in to view solution →- A. one
- B. four
- C. two
- D. three
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Log in to view solution →- A. HNO3, NO, N2, NH4Cl
- B. HNO3, NH4Cl, NO, N2
- C. HNO3, NO, NH4Cl, N2
- D. NH4Cl, N2, NO, HNO3
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Log in to view solution →- A. All form monobasic oxyacids.
- B. All but fluorine show positive oxidation states.
- C. All are oxidizing agents.
- D. Chlorine has the highest electron-gain enthalpy.
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Log in to view solution →- A. Ga
- B. B
- C. Al
- D. In
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Log in to view solution →- A. Ga
- B. B
- C. Al
- D. In
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Log in to view solution →- A. They contain covalent bonds between various linear polymer chains.
- B. Examples are bakelite and melamine.
- C. They are formed from bi- and tri-functional monomers.
- D. They contain strong covalent bonds in their polymer chains.
Correct answer & explanation hidden
Log in to view solution →- A. They contain covalent bonds between various linear polymer chains.
- B. Examples are bakelite and melamine.
- C. They are formed from bi- and tri-functional monomers.
- D. They contain strong covalent bonds in their polymer chains.
Correct answer & explanation hidden
Log in to view solution →- A. In spite of substituents nitro group always goes to only m-position.
- B. In absence of substituents nitro group always goes to m-position.
- C. In electrophilic substitution reactions amino group is meta directive.
- D. In acidic (strong) medium aniline is present as anilinium ion.
Correct answer & explanation hidden
Log in to view solution →- A. In spite of substituents nitro group always goes to only m-position.
- B. In absence of substituents nitro group always goes to m-position.
- C. In electrophilic substitution reactions amino group is meta directive.
- D. In acidic (strong) medium aniline is present as anilinium ion.
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Log in to view solution →- A. MgO
- B. BaO
- C. BeO
- D. CaO
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Log in to view solution →- A. MgO
- B. BaO
- C. BeO
- D. CaO
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Log in to view solution →- A. Amylopectin have 1→4 α-linkage and 1→6 α-linkage
- B. Amylopectin have 1→4 α-linkage and 1→6 β-linkage
- C. Amylose have 1→4 α-linkage and 1→6 β-linkage
- D. Amylose is made up of glucose and galactose
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Log in to view solution →- A. 1.4
- B. 2.8
- C. 3.0
- D. 4.4
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Log in to view solution →- A. formation of intramolecular H-bonding
- B. more extensive association of carboxylic acid via van der Waals force of attraction
- C. formation of carboxylate ion
- D. formation of intermolecular H-bonding
Correct answer & explanation hidden
Log in to view solution →- A. HC≡C–C≡CH
- B. CH2=CH–CH=CH2
- C. CH2=CH–C≡CH
- D. CH3–CH=CH–CH3
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Log in to view solution →- A. –NH2 < –OR < –F
- B. –NH2 > –OR > –F
- C. –NR2 < –OR < –F
- D. –NR2 > –OR > –F
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Log in to view solution →- A. Geometrical isomerism
- B. Ionization isomerism
- C. Coordination isomerism
- D. Linkage isomerism
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Log in to view solution →- A. tetranuclear
- B. trinuclear
- C. mononuclear
- D. dinuclear
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Log in to view solution →- A. square planar geometry and diamagnetic
- B. square planar geometry and paramagnetic
- C. tetrahedral geometry and diamagnetic
- D. tetrahedral geometry and paramagnetic
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Log in to view solution →- A. the rate of a first-order reaction does not depend on reactant concentrations; the rate of a second-order reaction does depend on reactant concentrations
- B. a first-order reaction can be catalyzed; a second-order reaction cannot be catalyzed
- C. the half-life of a first-order reaction does not depend on [A]0; the half-life of a second-order reaction does depend on [A]0
- D. the rate of a first-order reaction does depend on reactant concentrations; the rate of a second-order reaction does not depend on reactant concentrations
Correct answer & explanation hidden
Log in to view solution →- A. the rate of a first-order reaction does not depend on reactant concentrations; the rate of a second-order reaction does depend on reactant concentrations
- B. a first-order reaction can be catalyzed; a second-order reaction cannot be catalyzed
- C. the half-life of a first-order reaction does not depend on [A]0; the half-life of a second-order reaction does depend on [A]0
- D. the rate of a first-order reaction does depend on reactant concentrations; the rate of a second-order reaction does not depend on reactant concentrations
Correct answer & explanation hidden
Log in to view solution →- A. BeH2 < CaH2 < BaH2
- B. BeH2 < BaH2 < CaH2
- C. CaH2 < BeH2 < BaH2
- D. BaH2 < BeH2 < CaH2
Correct answer & explanation hidden
Log in to view solution →- A. 18 mL of water
- B. 0.00224 L of water vapours at 1 atm and 273 K
- C. 0.18 g of water
- D. 10–3 mol of water
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Log in to view solution →- A. 18 mL of water
- B. 0.00224 L of water vapours at 1 atm and 273 K
- C. 0.18 g of water
- D. 10^-3 mol of water
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Log in to view solution →- A. 200 kJ mol^-1
- B. 800 kJ mol^-1
- C. 100 kJ mol^-1
- D. 400 kJ mol^-1
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Log in to view solution →- A. is halved
- B. is tripled
- C. is doubled
- D. remains unchanged
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Log in to view solution →- A. 16 5 2
- B. 2 16 5
- C. 2 5 16
- D. 5 16 2
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Log in to view solution →- A. Low temperature and high pressure
- B. High temperature and high pressure
- C. Low temperature and low pressure
- D. High temperature and low pressure
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Log in to view solution →- A. density of the gas molecules
- B. electric field present between the gas molecules
- C. volume of the gas molecules
- D. forces of attraction between the gas molecules
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Log in to view solution →- A. Mg2X3
- B. Mg2X
- C. MgX2
- D. Mg3X2
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Log in to view solution →- A. 2^(3/2) / 3
- B. 2^4 / 3^3
- C. 2^3 / 3^4
- D. 2 / 1
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Log in to view solution →- A. NO
- B. CN+
- C. CN–
- D. CN
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Log in to view solution →- A. Total orbital angular momentum of electron in ‘s’ orbital is equal to zero.
- B. The electronic configuration of N atom is
- C. An orbital is designated by three quantum numbers while an electron in an atom is designated by four quantum numbers.
- D. The value of m for 2pz is zero.
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Log in to view solution →- A. N2O5
- B. N2O
- C. NO2
- D. NO
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Log in to view solution →- A. CH ≡ CH
- B. CH3 – CH3
- C. CH2 = CH2
- D. CH4
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Log in to view solution →- A. CH≡CH
- B. CH3 – CH3
- C. CH2 = CH2
- D. CH4
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Log in to view solution →- A. C2H5OH, C2H6, C2H5Cl
- B. C2H5Cl, C2H6, C2H5OH
- C. C2H5OH, C2H5Cl, C2H5ONa
- D. C2H5OH, C2H5ONa, C2H5Cl
Correct answer & explanation hidden
Log in to view solution →- A. C2H5OH, C2H6, C2H5Cl
- B. C2H5Cl, C2H6, C2H5OH
- C. C2H5OH, C2H5Cl, C2H5ONa
- D. C2H5OH, C2H5ONa, C2H5Cl
Correct answer & explanation hidden
Log in to view solution →- A. m-bromotoluene
- B. 3-bromo-2,4,6-trichlorotoluene
- C. o-bromotoluene
- D. p-bromotoluene
Correct answer & explanation hidden
Log in to view solution →- A. Aniline
- B. Benzoic acid
- C. Acetanilide
- D. Glycine
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Log in to view solution →- A. Aniline
- B. Benzoic acid
- C. Acetanilide
- D. Glycine
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Log in to view solution →- A. Ovules are not enclosed by ovary wall in gymnosperms.
- B. Horsetails are gymnosperms.
- C. Selaginella is heterosporous, while Salvinia is homosporous.
- D. Stems are usually unbranched in both Cycas and Cedrus.
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Log in to view solution →- A. Halophytes
- B. Carnivorous plants
- C. Free-floating hydrophytes
- D. Submerged hydrophytes
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Log in to view solution →- A. Stem
- B. Tap root
- C. Adventitious root
- D. Rhizome
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Log in to view solution →- A. Grasses
- B. Conifers
- C. Deciduous angiosperms
- D. Cycads
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Log in to view solution →- A. Epidermis
- B. Cortex
- C. Pericycle
- D. Endodermis
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Log in to view solution →- A. Apical meristems
- B. Phellogen
- C. Vascular cambium
- D. Axillary meristems
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Log in to view solution →- A. Cell wall is present in members of Fungi and Plantae.
- B. Pseudopodia are locomotory and feeding structures in Sporozoans.
- C. Mushrooms belong to Basidiomycetes.
- D. Mitochondria are the powerhouse of the cell in all kingdoms except Monera.
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Log in to view solution →- A. Fungus
- B. Plant
- C. Bacterium
- D. Virus
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Log in to view solution →- A. Alec Jeffreys – Streptococcus pneumoniae
- B. Matthew Meselson and F. Stahl – Pisum sativum
- C. Alfred Hershey and Martha Chase – TMV
- D. Francois Jacob and Jacques Monod – Lac operon
Correct answer & explanation hidden
Log in to view solution →- A. Franklin Stahl coined the term ‘‘linkage’’.
- B. Spliceosomes take part in translation.
- C. Punnett square was developed by a British scientist.
- D. Transduction was discovered by S. Altman.
Correct answer & explanation hidden
Log in to view solution →- A. Starch synthesis in pea : Multiple alleles
- B. XO type sex determination : Grasshopper
- C. ABO blood grouping : Co-dominance
- D. T.H. Morgan : Linkage
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Log in to view solution →- A. Meiotic divisions
- B. Parthenocarpy
- C. Mitotic divisions
- D. Parthenogenesis
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Log in to view solution →- A. Bamboo species
- B. Mango
- C. Jackfruit
- D. Papaya
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Log in to view solution →- A. Pollenkitt
- B. Oil content
- C. Cellulosic intine
- D. Sporopollenin
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Log in to view solution →- A. Retrovirus
- B. phage
- C. Ti plasmid
- D. pBR 322
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Log in to view solution →- A. Extension, Denaturation, Annealing
- B. Denaturation, Extension, Annealing
- C. Annealing, Extension, Denaturation
- D. Denaturation, Annealing, Extension
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Log in to view solution →- A. Indian Council of Medical Research (ICMR)
- B. Research Committee on Genetic Manipulation (RCGM)
- C. Council for Scientific and Industrial Research (CSIR)
- D. Genetic Engineering Appraisal Committee (GEAC)
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Log in to view solution →- A. Indian Council of Medical Research (ICMR)
- B. Research Committee on Genetic Manipulation (RCGM)
- C. Council for Scientific and Industrial Research (CSIR)
- D. Genetic Engineering Appraisal Committee (GEAC)
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Log in to view solution →- A. Bio-infringement
- B. Biodegradation
- C. Biopiracy
- D. Bioexploitation
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Log in to view solution →- A. Bio-infringement
- B. Biodegradation
- C. Biopiracy
- D. Bioexploitation
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Log in to view solution →- A. Co-667
- B. Lerma Rojo
- C. Sharbati Sonora
- D. Basmati
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Log in to view solution →- A. Co-667
- B. Lerma Rojo
- C. Sharbati Sonora
- D. Basmati
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Log in to view solution →- A. Ribozyme – Nucleic acid
- B. T.H. Morgan – Transduction
- C. F2 × Recessive parent – Dihybrid cross
- D. G. Mendel – Transformation
Correct answer & explanation hidden
Log in to view solution →- A. all the biological factors in the organism’s environment
- B. the range of temperature that the organism needs to live
- C. the physical space where an organism lives
- D. the functional role played by the organism where it lives
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Log in to view solution →- A. CO
- B. SO2
- C. CO2
- D. O3
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Log in to view solution →- A. 5th June
- B. 16th September
- C. 21st April
- D. 22nd April
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Log in to view solution →- A. Death rate
- B. Number of individuals leaving the habitat
- C. Birth rate
- D. Number of individuals entering a habitat
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Log in to view solution →- A. Carbon
- B. Fe
- C. Cl
- D. Oxygen
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Log in to view solution →- A. Inverted pyramid of biomass
- B. Upright pyramid of numbers
- C. Pyramid of energy
- D. Upright pyramid of biomass
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Log in to view solution →- A. Fatty acid breakdown
- B. Respiration in bacteria
- C. Formation of secretory vesicles
- D. Activation of amino acid
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Log in to view solution →- A. ATP
- B. NADPH
- C. NADH
- D. Oxygen
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Log in to view solution →- A. Saccharomyces
- B. Nostoc
- C. Mycobacterium
- D. Oscillatoria
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Log in to view solution →- A. Temperature
- B. O2 concentration
- C. Light
- D. CO2 concentration
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Log in to view solution →- A. Larger nucleoli are present in dividing cells.
- B. It takes part in spindle formation.
- C. It is a membrane-bound structure.
- D. It is a site for active ribosomal RNA synthesis.
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Log in to view solution →- A. Pachytene
- B. Diakinesis
- C. Diplotene
- D. Zygotene
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Log in to view solution →- A. hydroxyl and methyl
- B. carbonyl and phosphate
- C. carbonyl and methyl
- D. carbonyl and hydroxyl
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Log in to view solution →- A. Dumb-bell shaped
- B. Rectangular
- C. Kidney shaped
- D. Barrel shaped
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Log in to view solution →- A. Hydrilla
- B. Banana
- C. Yucca
- D. Viola
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Log in to view solution →- A. – 120C
- B. – 196C
- C. – 80C
- D. – 160C
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Log in to view solution →- A. Fusion of two male gametes of a pollen tube with two different eggs
- B. Fusion of two male gametes with one egg
- C. Fusion of one male gamete with two polar nuclei
- D. Syngamy and triple fusion
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Log in to view solution →- A. Fusion of two male gametes of a pollen tube with two different eggs
- B. Fusion of two male gametes with one egg
- C. Fusion of one male gamete with two polar nuclei
- D. Syngamy and triple fusion
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Log in to view solution →- A. Green sulphur bacteria
- B. Cycas
- C. Nostoc
- D. Chara
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Log in to view solution →- A. Green sulphur bacteria
- B. Cycas
- C. Nostoc
- D. Chara
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Log in to view solution →- A. Magnesium
- B. Potassium
- C. Sodium
- D. Calcium
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Log in to view solution →- A. Magnesium
- B. Potassium
- C. Sodium
- D. Calcium
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Log in to view solution →- A. It functions as an enzyme.
- B. It is a nucleotide source for ATP synthesis.
- C. It functions as an electron carrier.
- D. It is the final electron acceptor for anaerobic respiration.
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Log in to view solution →- A. It functions as an enzyme.
- B. It is a nucleotide source for ATP synthesis.
- C. It functions as an electron carrier.
- D. It is the final electron acceptor for anaerobic respiration.
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Log in to view solution →- A. Ferric
- B. Free element
- C. Ferrous
- D. Both ferric and ferrous
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Log in to view solution →- A. Ferric
- B. Free element
- C. Ferrous
- D. Both ferric and ferrous
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Log in to view solution →- A. Mustard
- B. Mango
- C. Cycas
- D. Pinus
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Log in to view solution →- A. Mustard
- B. Mango
- C. Cycas
- D. Pinus
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Log in to view solution →- A. Neurospora
- B. Agaricus
- C. Alternaria
- D. Saccharomyces
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Log in to view solution →- A. Neurospora
- B. Agaricus
- C. Alternaria
- D. Saccharomyces
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Log in to view solution →- A. Uniflagellate gametes – Polysiphonia
- B. Gemma cups – Marchantia
- C. Biflagellate zoospores – Brown algae
- D. Unicellular organism – Chlorella
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Log in to view solution →- A. 1) i iv iii ii
- B. 2) ii iv iii i
- C. 3) iii ii i iv
- D. 4) iii iv i ii
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Log in to view solution →- A. Epinephrine
- B. Estradiol
- C. Ecdysone
- D. Estriol
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Log in to view solution →- A. Medulla oblongata : controls respiration and cardiovascular reflexes.
- B. Hypothalamus : production of releasing hormones and regulation of temperature, hunger and thirst.
- C. Limbic system : consists of fibre tracts that interconnect different regions of brain; controls movement.
- D. Corpus callosum : band of fibers connecting left and right cerebral hemispheres.
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Log in to view solution →- A. ligaments attached to the ciliary body
- B. smooth muscles attached to the iris
- C. ligaments attached to the iris
- D. smooth muscles attached to the ciliary body
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Log in to view solution →- A. Aldosterone and Prolactin
- B. Estrogen and Parathyroid hormone
- C. Progesterone and Aldosterone
- D. Parathyroid hormone and Prolactin
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Log in to view solution →- A. Forelimbs of man, bat and cheetah
- B. Brain of bat, man and cheetah
- C. Heart of bat, man and cheetah
- D. Eye of octopus, bat and man
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Log in to view solution →- A. Psoriasis
- B. Alzheimer’s disease
- C. Rheumatoid arthritis
- D. Vitiligo
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Log in to view solution →- A. b, c and e
- B. b, d and e
- C. a, b and c
- D. a, c and e
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Log in to view solution →- A. Elephantiasis
- B. Ringworm disease
- C. Ascariasis
- D. Amoebiasis
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Log in to view solution →- A. Homology
- B. Convergent evolution
- C. Analogy
- D. Adaptive radiation
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Log in to view solution →- A. Homology
- B. Convergent evolution
- C. Analogy
- D. Adaptive radiation
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Log in to view solution →- A. Vitamin D
- B. Vitamin B12
- C. Vitamin A
- D. Vitamin E
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Log in to view solution →- A. Vitamin D
- B. Vitamin B12
- C. Vitamin A
- D. Vitamin E
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Log in to view solution →- A. Commensalism
- B. Parasitism
- C. Mutualism
- D. Amensalism
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Log in to view solution →- A. Commensalism
- B. Parasitism
- C. Mutualism
- D. Amensalism
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Log in to view solution →- A. Wildlife safari parks
- B. Botanical gardens
- C. Sacred groves
- D. Seed banks
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Log in to view solution →- A. Wildlife safari parks
- B. Botanical gardens
- C. Sacred groves
- D. Seed banks
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Log in to view solution →- A. (1) ii i iii iv
- B. (2) iii iv i ii
- C. (3) i iii iv ii
- D. (4) i ii iv iii
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Log in to view solution →- A. pre-reproductive individuals are more than the reproductive individuals.
- B. reproductive and pre-reproductive individuals are equal in number.
- C. reproductive individuals are less than the post-reproductive individuals.
- D. pre-reproductive individuals are less than the reproductive individuals.
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Log in to view solution →- A. Flowers
- B. Roots
- C. Latex
- D. Leaves
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Log in to view solution →- A. hCG, hPL, progestogens, prolactin
- B. hCG, hPL, progestogens, estrogens
- C. hCG, hPL, estrogens, relaxin, oxytocin
- D. hCG, progestogens, estrogens, glucocorticoids
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Log in to view solution →- A. blocks estrogen receptors in the uterus, preventing eggs from getting implanted.
- B. is an IUD.
- C. increases the concentration of estrogen and prevents ovulation in females.
- D. is a post-coital contraceptive.
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Log in to view solution →- A. ectoderm and mesoderm
- B. mesoderm and trophoblast
- C. endoderm and mesoderm
- D. ectoderm and endoderm
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Log in to view solution →- A. In spermiogenesis spermatids are formed, while in spermiation spermatozoa are formed.
- B. In spermiogenesis spermatozoa from sertoli cells are released into the cavity of seminiferous tubules, while in spermiation spermatozoa are formed.
- C. In spermiogenesis spermatozoa are formed, while in spermiation spermatids are formed.
- D. In spermiogenesis spermatozoa are formed, while in spermiation spermatozoa are released from sertoli cells into the cavity of seminiferous tubules.
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Log in to view solution →- A. Inflammation of bronchioles; Decreased respiratory surface
- B. Increased respiratory surface; Inflammation of bronchioles
- C. Increased number of bronchioles; Increased respiratory surface
- D. Decreased respiratory surface; Inflammation of bronchioles
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Log in to view solution →- A. (1) iii i ii
- B. (2) i ii iii
- C. (3) i iii ii
- D. (4) ii i iii
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Log in to view solution →- A. (1) iii ii i iv
- B. (2) i iv ii iii
- C. (3) iii i iv ii
- D. (4) iv iii ii i
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Log in to view solution →- A. (1) iii ii i iv
- B. (2) i iv ii iii
- C. (3) iii i iv ii
- D. (4) iv iii ii i
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Log in to view solution →- A. (1) iii ii iv i
- B. (2) ii iii i iv
- C. (3) i ii iii iv
- D. (4) iv i ii iii
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Log in to view solution →- A. (1) iii ii iv i
- B. (2) ii iii i iv
- C. (3) i ii iii iv
- D. (4) iv i ii iii
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Log in to view solution →- A. (1) iv v ii iii
- B. (2) v iv i ii
- C. (3) iv i ii iii
- D. (4) v iv i iii
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Log in to view solution →- A. Protein folding
- B. Cleavage of signal peptide
- C. Protein glycosylation
- D. Phospholipid synthesis
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Log in to view solution →- A. Enzymes of TCA cycle are present in mitochondrial matrix.
- B. Glycolysis operates as long as it is supplied with NAD that can pick up hydrogen atoms.
- C. Glycolysis occurs in cytosol.
- D. Oxidative phosphorylation takes place in outer mitochondrial membrane.
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