- A. It is a nucleotide source for ATP synthesis.
- B. It functions as an electron carrier.
- C. It functions as an enzyme.
- D. It is the final electron acceptor for anaerobic respiration.
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Log in to view solution →- A. Cycas
- B. Nostoc
- C. Green sulphur bacteria
- D. Chara
Correct answer & explanation hidden
Log in to view solution →- A. Fusion of two male gametes with one egg
- B. Fusion of one male gamete with two polar nuclei
- C. Fusion of two male gametes of a pollen tube with two different eggs
- D. Syngamy and triple fusion
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Log in to view solution →- A. Free element
- B. Ferrous
- C. Ferric
- D. Both ferric and ferrous
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Log in to view solution →- A. Potassium
- B. Sodium
- C. Magnesium
- D. Calcium
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Log in to view solution →- A. Banana
- B. Yucca
- C. Hydrilla
- D. Viola
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Log in to view solution →- A. –196°C
- B. –80°C
- C. –120°C
- D. –160°C
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Log in to view solution →- A. Upright pyramid of numbers
- B. Pyramid of energy
- C. Inverted pyramid of biomass
- D. Upright pyramid of biomass
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Log in to view solution →- A. Number of individuals leaving the habitat
- B. Birth rate
- C. Death rate
- D. Number of individuals entering a habitat
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Log in to view solution →- A. Number of individuals leaving the habitat
- B. Birth rate
- C. Death rate
- D. Number of individuals entering a habitat
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Log in to view solution →- A. 16th September
- B. 21st April
- C. 5th June
- D. 22nd April
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Log in to view solution →- A. 16th September
- B. 21st April
- C. 5th June
- D. 22nd April
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Log in to view solution →- A. Fe
- B. Cl
- C. Carbon
- D. Oxygen
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Log in to view solution →- A. Fe
- B. Cl
- C. Carbon
- D. Oxygen
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Log in to view solution →- A. The range of temperature that the organism needs to live
- B. The physical space where an organism lives
- C. All the biological factors in the organism's environment
- D. The functional role played by the organism where it lives
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Log in to view solution →- A. the range of temperature that the organism needs to live
- B. the physical space where an organism lives
- C. all the biological factors in the organism's environment
- D. the functional role played by the organism where it lives
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Log in to view solution →- A. SO₂
- B. CO₂
- C. CO
- D. O₃
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Log in to view solution →- A. SO₂
- B. CO₂
- C. CO
- D. O₃
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Log in to view solution →- A. Horsetails are gymnosperms.
- B. Selaginella is heterosporous, while Salvinia is homosporous.
- C. Ovules are not enclosed by ovary wall in gymnosperms.
- D. Stems are usually unbranched in both Cycas and Cedrus.
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Log in to view solution →- A. Carnivorous plants
- B. Free-floating hydrophytes
- C. Halophytes
- D. Submerged hydrophytes
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Log in to view solution →- A. Tap root
- B. Adventitious root
- C. Stem
- D. Rhizome
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Log in to view solution →- A. Phellogen
- B. Vascular cambium
- C. Apical meristems
- D. Axillary meristems
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Log in to view solution →- A. Pseudopodia are locomotory and feeding structures in Sporozoans.
- B. Mushrooms belong to Basidiomycetes.
- C. Cell wall is present in members of Fungi and Plantae.
- D. Mitochondria are the powerhouse of the cell in all kingdoms except Monera.
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Log in to view solution →- A. Cortex
- B. Pericycle
- C. Epidermis
- D. Endodermis
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Log in to view solution →- A. Conifers
- B. Deciduous angiosperms
- C. Grasses
- D. Cycads
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Log in to view solution →- A. Lerma Rojo
- B. Sharbati Sonora
- C. Co-667
- D. Basmati
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Log in to view solution →- A. λ phage
- B. Ti plasmid
- C. Retrovirus
- D. pBR 322
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Log in to view solution →- A. Biodegradation
- B. Biopiracy
- C. Bio-infringement
- D. Bioexploitation
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Log in to view solution →- A. T.H. Morgan – Transduction
- B. F₂ × Recessive parent – Dihybrid cross
- C. Ribozyme – Nucleic acid
- D. G. Mendel – Transformation
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Log in to view solution →- A. Denaturation, Extension, Annealing
- B. Annealing, Extension, Denaturation
- C. Extension, Denaturation, Annealing
- D. Denaturation, Annealing, Extension
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Log in to view solution →- A. Research Committee on Genetic Manipulation (RCGM)
- B. Council for Scientific and Industrial Research (CSIR)
- C. Indian Council of Medical Research (ICMR)
- D. Genetic Engineering Appraisal Committee (GEAC)
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Log in to view solution →- A. Diakinesis
- B. Diplotene
- C. Pachytene
- D. Zygotene
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Log in to view solution →- A. Respiration in bacteria
- B. Formation of secretory vesicles
- C. Fatty acid breakdown
- D. Activation of amino acid
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Log in to view solution →- A. O₂ concentration
- B. Light
- C. Temperature
- D. CO₂ concentration
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Log in to view solution →- A. O₂ concentration
- B. Light
- C. Temperature
- D. CO₂ concentration
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Log in to view solution →- A. Rectangular
- B. Kidney shaped
- C. Dumb-bell shaped
- D. Barrel shaped
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Log in to view solution →- A. Rectangular
- B. Kidney shaped
- C. Dumb-bell shaped
- D. Barrel shaped
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Log in to view solution →- A. carbonyl and phosphate
- B. carbonyl and methyl
- C. hydroxyl and methyl
- D. carbonyl and hydroxyl
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Log in to view solution →- A. carbonyl and phosphate
- B. carbonyl and methyl
- C. hydroxyl and methyl
- D. carbonyl and hydroxyl
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Log in to view solution →- A. NADPH
- B. NADH
- C. ATP
- D. Oxygen
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Log in to view solution →- A. NADPH
- B. NADH
- C. ATP
- D. Oxygen
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Log in to view solution →- A. It takes part in spindle formation.
- B. It is a membrane-bound structure.
- C. Larger nucleoli are present in dividing cells.
- D. It is a site for active ribosomal RNA synthesis.
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Log in to view solution →- A. It takes part in spindle formation.
- B. It is a membrane-bound structure.
- C. Larger nucleoli are present in dividing cells.
- D. It is a site for active ribosomal RNA synthesis.
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Log in to view solution →- A. Nostoc
- B. Mycobacterium
- C. Saccharomyces
- D. Oscillatoria
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Log in to view solution →- A. Nostoc
- B. Mycobacterium
- C. Saccharomyces
- D. Oscillatoria
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Log in to view solution →- A. Mango
- B. Cycas
- C. Mustard
- D. Pinus
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Log in to view solution →- A. Mango
- B. Cycas
- C. Mustard
- D. Pinus
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Log in to view solution →- A. Agaricus
- B. Alternaria
- C. Neurospora
- D. Saccharomyces
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Log in to view solution →- A. Agaricus
- B. Alternaria
- C. Neurospora
- D. Saccharomyces
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Log in to view solution →- A. Gemma cups – Marchantia
- B. Biflagellate zoospores – Brown algae
- C. Uniflagellate gametes – Polysiphonia
- D. Unicellular organism – Chlorella
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Log in to view solution →- A. a-ii, b-iv, c-iii, d-i
- B. a-iii, b-ii, c-i, d-iv
- C. a-i, b-iv, c-iii, d-ii
- D. a-iii, b-iv, c-i, d-ii
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Log in to view solution →- A. Mango
- B. Jackfruit
- C. Bamboo species
- D. Papaya
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Log in to view solution →- A. XO type sex determination – Grasshopper
- B. ABO blood grouping – Co-dominance
- C. Starch synthesis in pea – Multiple alleles
- D. T.H. Morgan – Linkage
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Log in to view solution →- A. Parthenocarpy
- B. Mitotic divisions
- C. Meiotic divisions
- D. Parthenogenesis
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Log in to view solution →- A. Oil content
- B. Cellulosic intine
- C. Pollenkitt
- D. Sporopollenin
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Log in to view solution →- A. Spliceosomes take part in translation.
- B. Punnett square was developed by a British scientist.
- C. Franklin Stahl coined the term 'linkage'.
- D. Transduction was discovered by S. Altman.
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Log in to view solution →- A. Plant
- B. Bacterium
- C. Fungus
- D. Virus
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Log in to view solution →- A. Matthew Meselson and F. Stahl – Pisum sativum
- B. Alfred Hershey and Martha Chase – TMV
- C. Alec Jeffreys – Streptococcus pneumoniae
- D. Francois Jacob and Jacques Monod – Lac operon
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Log in to view solution →- A. a-i, b-iv, c-ii, d-iii
- B. a-iii, b-i, c-iv, d-ii
- C. a-iii, b-ii, c-i, d-iv
- D. a-iv, b-iii, c-ii, d-i
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Log in to view solution →- A. Increased respiratory surface; Inflammation of bronchioles
- B. Increased number of bronchioles; Increased respiratory surface
- C. Inflammation of bronchioles; Decreased respiratory surface
- D. Decreased respiratory surface; Inflammation of bronchioles
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Log in to view solution →- A. a-i, b-ii, c-iii
- B. a-i, b-iii, c-ii
- C. a-iii, b-i, c-ii
- D. a-ii, b-i, c-iii
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Log in to view solution →- A. i ii iii
- B. i iii ii
- C. iii i ii
- D. ii i iii
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Log in to view solution →- A. an enhancer
- B. structural genes
- C. an operator
- D. a promoter
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Log in to view solution →- A. an enhancer
- B. structural genes
- C. an operator
- D. a promoter
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Log in to view solution →- A. ACCUAUGCGAU
- B. UGGTUTCGCAT
- C. AGGUAUCGCAU
- D. UCCAUAGCGUA
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Log in to view solution →- A. ACCUAUGCGAU
- B. UGGTUTCGCAT
- C. AGGUAUCGCAU
- D. UCCAUAGCGUA
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Log in to view solution →- A. Phenotypic variations
- B. Saltation
- C. Multiple step mutations
- D. Minor mutations
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Log in to view solution →- A. ii iii i
- B. i iii ii
- C. iii ii i
- D. iii i ii
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Log in to view solution →- A. Only grandchildren
- B. Only sons
- C. Only daughters
- D. Both sons and daughters
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Log in to view solution →- A. using pseudopodia for capturing prey
- B. having a contractile vacuole for removing excess water
- C. using flagella for locomotion
- D. having two types of nuclei
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Log in to view solution →- A. Aves
- B. Reptilia
- C. Amphibia
- D. Osteichthyes
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Log in to view solution →- A. Cyanobacteria
- B. Diatoms
- C. Dinoflagellates
- D. Euglenoids
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Log in to view solution →- A. Forewings with darker tegmina
- B. Presence of caudal styles
- C. Presence of a boat shaped sternum on the 9th abdominal segment
- D. Presence of anal cerci
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Log in to view solution →- A. Moth
- B. Tunicate
- C. Earthworm
- D. Starfish
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Log in to view solution →- A. Camelus
- B. Chelone
- C. Macropus
- D. Psittacula
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Log in to view solution →- A. smooth muscles attached to the iris
- B. ligaments attached to the iris
- C. ligaments attached to the ciliary body
- D. smooth muscles attached to the ciliary body
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Log in to view solution →- A. Hypothalamus : production of releasing hormones and regulation of temperature, hunger and thirst.
- B. Limbic system : consists of fibre tracts that interconnect different regions of brain; controls movement.
- C. Medulla oblongata : controls respiration and cardiovascular reflexes.
- D. Corpus callosum : band of fibers connecting left and right cerebral hemispheres.
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Log in to view solution →- A. Estrogen and Parathyroid hormone
- B. Progesterone and Aldosterone
- C. Aldosterone and Prolactin
- D. Parathyroid hormone and Prolactin
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Log in to view solution →- A. Estradiol
- B. Ecdysone
- C. Epinephrine
- D. Estriol
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Log in to view solution →- A. ii iii i iv
- B. i ii iii iv
- C. iii ii iv i
- D. iv i ii iii
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Log in to view solution →- A. ii iii i iv
- B. i ii iii iv
- C. iii ii iv i
- D. iv i ii iii
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Log in to view solution →- A. 1/3
- B. 2/3
- C. 2/5
- D. 2/7
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Log in to view solution →- A. 12.5 cm
- B. 8 cm
- C. 13.2 cm
- D. 16 cm
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Log in to view solution →- A. 6.25%
- B. 20%
- C. 26.8%
- D. 12.5%
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Log in to view solution →- A. 5.016 × 10⁴ K
- B. 8.360 × 10⁴ K
- C. 2.508 × 10⁴ K
- D. 1.254 × 10⁴ K
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Log in to view solution →- A. i = sin⁻¹(1/μ)
- B. Reflected light is polarised with its electric vector perpendicular to the plane of incidence
- C. Reflected light is polarised with its electric vector parallel to the plane of incidence
- D. i = tan⁻¹(1/μ)
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Log in to view solution →- A. i = sin⁻¹(1/μ)
- B. Reflected light is polarised with its electric vector perpendicular to the plane of incidence
- C. Reflected light is polarised with its electric vector parallel to the plane of incidence
- D. i = tan⁻¹(1/μ)
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Log in to view solution →- A. 2.1 mm
- B. 1.9 mm
- C. 1.8 mm
- D. 1.7 mm
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Log in to view solution →- A. large focal length and large diameter
- B. large focal length and small diameter
- C. small focal length and large diameter
- D. small focal length and small diameter
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Log in to view solution →- A. K_B < K_A < K_C
- B. K_A > K_B > K_C
- C. K_A < K_B < K_C
- D. K_B > K_A > K_C
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Log in to view solution →- A. 10 : 7
- B. 5 : 7
- C. 7 : 10
- D. 2 : 5
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Log in to view solution →- A. Time period of a simple pendulum on the Earth would decrease.
- B. Walking on the ground would become more difficult.
- C. Raindrops will fall faster.
- D. 'g' on the Earth will not change.
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Log in to view solution →- A. Rotational kinetic energy
- B. Moment of inertia
- C. Angular velocity
- D. Angular momentum
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Log in to view solution →- A. 14.76 A
- B. 5.98 A
- C. 7.14 A
- D. 11.32 A
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Log in to view solution →- A. 2.74 W
- B. 0.43 W
- C. 0.79 W
- D. 1.13 W
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Log in to view solution →- A. the lattice structure of the material of the rod
- B. the magnetic field
- C. the current source
- D. the induced electric field due to the changing magnetic field
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Log in to view solution →- A. 250 Ω
- B. 25 Ω
- C. 40 Ω
- D. 500 Ω
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Log in to view solution →- A. 250 Ω
- B. 25 Ω
- C. 40 Ω
- D. 500 Ω
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Log in to view solution →- A. I_B = 20 μA, I_C = 5 mA, β = 250
- B. I_B = 25 μA, I_C = 5 mA, β = 200
- C. I_B = 40 μA, I_C = 10 mA, β = 250
- D. I_B = 40 μA, I_C = 5 mA, β = 125
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Log in to view solution →- A. does not affect resistance of p-n junction
- B. affects only forward resistance
- C. affects only reverse resistance
- D. affects the overall V–I characteristics of p-n junction
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Log in to view solution →- A. does not affect resistance of p-n junction
- B. affects only forward resistance
- C. affects only reverse resistance
- D. affects the overall V–I characteristics of p-n junction
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Log in to view solution →- A. B·A̅ + A·B̅
- B. A·B̅ + A̅·B
- C. B·A̅
- D. B·A
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Log in to view solution →- A. Yellow – Green – Violet – Gold
- B. Yellow – Violet – Orange – Silver
- C. Violet – Yellow – Orange – Silver
- D. Green – Orange – Violet – Gold
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Log in to view solution →- A. 20
- B. 11
- C. 10
- D. 9
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Log in to view solution →- A. (5/4)D
- B. D
- C. (3/2)D
- D. (5/4)D
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Log in to view solution →- A. W_B > W_A > W_C
- B. W_A > W_B > W_C
- C. W_C > W_B > W_A
- D. W_A > W_C > W_B
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Log in to view solution →- A. Frictional force opposes the relative motion.
- B. Limiting value of static friction is directly proportional to normal reaction.
- C. Rolling friction is smaller than sliding friction.
- D. Coefficient of sliding friction has dimensions of length.
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Log in to view solution →- A. 0.8
- B. 0.25
- C. 0.5
- D. 0.4
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Log in to view solution →- A. 350 m/s
- B. 339 m/s
- C. 330 m/s
- D. 300 m/s
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Log in to view solution →- A. proportional to the square root of the distance between the plates.
- B. linearly proportional to the distance between the plates.
- C. independent of the distance between the plates.
- D. inversely proportional to the distance between the plates.
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Log in to view solution →- A. proportional to the square root of the distance between the plates.
- B. linearly proportional to the distance between the plates.
- C. independent of the distance between the plates.
- D. inversely proportional to the distance between the plates.
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Log in to view solution →- A. 2π s
- B. π s
- C. 2 s
- D. 1 s
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Log in to view solution →- A. 2 s
- B. π s
- C. 2π s
- D. 1 s
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Log in to view solution →- A. 10 times greater
- B. 5 times greater
- C. smaller
- D. equal
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Log in to view solution →- A. λ₀ t
- B. λ₀ (1 + eE₀t / mV₀)
- C. λ₀ / (1 + eE₀t / mV₀)
- D. λ₀
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Log in to view solution →- A. 30
- B. 10
- C. 20
- D. 15
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Log in to view solution →- A. 4 : 1
- B. 1 : 4
- C. 1 : 2
- D. 2 : 1
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Log in to view solution →- A. 2 : –1
- B. 1 : –1
- C. 1 : 1
- D. 1 : –2
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Log in to view solution →- A. –y direction
- B. +z direction
- C. –z direction
- D. –x direction
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Log in to view solution →- A. 30°
- B. 45°
- C. 60°
- D. zero
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Log in to view solution →- A. 1.389 H
- B. 138.88 H
- C. 0.138 H
- D. 13.89 H
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Log in to view solution →- A. 30 cm towards the mirror
- B. 36 cm away from the mirror
- C. 30 cm away from the mirror
- D. 36 cm towards the mirror
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Log in to view solution →- A. 1 m/s, 3.5 m/s
- B. 1 m/s, 3 m/s
- C. 2 m/s, 4 m/s
- D. 1.5 m/s, 3 m/s
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Log in to view solution →- A. a = g cos θ
- B. a = g / sin θ
- C. a = g / cos θ
- D. a = g tan θ
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Log in to view solution →- A. a = g cos θ
- B. a = g / sin θ
- C. a = g / cos θ
- D. a = g tan θ
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Log in to view solution →- A. 0.053 cm
- B. 0.525 cm
- C. 0.521 cm
- D. 0.529 cm
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Log in to view solution →- A. 0·053 cm
- B. 0·525 cm
- C. 0·521 cm
- D. 0·529 cm
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Log in to view solution →- A. –7î – 8ĵ – 4k̂
- B. –4î – ĵ – 8k̂
- C. –8î – 4ĵ – 7k̂
- D. –7î – 4ĵ – 8k̂
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Log in to view solution →- A. 81/256
- B. 3/4
- C. 4/3
- D. 256/81
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Log in to view solution →- A. 4 F
- B. 6 F
- C. 9 F
- D. F
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Log in to view solution →- A. 42·2 J
- B. 208·7 J
- C. 104·3 J
- D. 84·5 J
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Log in to view solution →- A. r⁵
- B. r²
- C. r³
- D. r⁴
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Log in to view solution →- A. d
- B. a
- C. b
- D. c
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Log in to view solution →- A. 1·08 × 10⁻¹⁴ mol² L⁻²
- B. 1·08 × 10⁻¹² mol² L⁻²
- C. 1·08 × 10⁻¹⁰ mol² L⁻²
- D. 1·08 × 10⁻⁸ mol² L⁻²
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Log in to view solution →- A. O₂
- B. H₂
- C. NH₃
- D. CO₂
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Log in to view solution →- A. Dichloromethyl anion (CHCl₂⁻)
- B. Formyl cation (CHO⁺)
- C. Dichloromethyl cation (CHCl₂⁺)
- D. Dichlorocarbene (:CCl₂)
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Log in to view solution →- A. More extensive association of carboxylic acid via van der Waals force of attraction
- B. Formation of carboxylate ion
- C. Formation of intramolecular H-bonding
- D. Formation of intermolecular H-bonding
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Log in to view solution →- A. More extensive association of carboxylic acid via van der Waals force of attraction
- B. Formation of carboxylate ion
- C. Formation of intramolecular H-bonding
- D. Formation of intermolecular H-bonding
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Log in to view solution →- A. Mg₂X
- B. MgX₂
- C. Mg₂X₃
- D. Mg₃X₂
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Log in to view solution →- A. Mg₂X
- B. MgX₂
- C. Mg₂X₃
- D. Mg₃X₂
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Log in to view solution →- A. 2√4 / 3√3
- B. 2√3 / 3√4
- C. √2 / √3
- D. √2 / √1
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Log in to view solution →- A. The electronic configuration of N atom shows half-filled 2p subshell
- B. An orbital is designated by three quantum numbers while an electron in an atom is designated by four quantum numbers
- C. Total orbital angular momentum of electron in 's' orbital is equal to zero
- D. The value of mₗ for d_z² is zero
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Log in to view solution →- A. CN⁺
- B. CN⁻
- C. NO
- D. CN
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Log in to view solution →- A. Four
- B. Two
- C. One
- D. Three
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Log in to view solution →- A. B < Ga < Al < Tl < In
- B. B < Al < Ga < In < Tl
- C. B < Al < In < Ga < Tl
- D. B < Ga < Al < In < Tl
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Log in to view solution →- A. HNO₃, NH₄Cl, NO, N₂
- B. HNO₃, NO, NH₄Cl, N₂
- C. HNO₃, NO, N₂, NH₄Cl
- D. NH₄Cl, N₂, NO, HNO₃
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Log in to view solution →- A. B
- B. Al
- C. Ga
- D. In
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Log in to view solution →- A. All but fluorine show positive oxidation states
- B. All are oxidizing agents
- C. All form monobasic oxyacids
- D. Chlorine has the highest electron-gain enthalpy
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Log in to view solution →- A. Mg
- B. Zn
- C. Fe
- D. Cu
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Log in to view solution →- A. 2 | 16 | 5
- B. 2 | 5 | 16
- C. 16 | 5 | 2
- D. 5 | 16 | 2
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Log in to view solution →- A. High temperature and high pressure
- B. Low temperature and low pressure
- C. Low temperature and high pressure
- D. High temperature and low pressure
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Log in to view solution →- A. Electric field present between the gas molecules
- B. Volume of the gas molecules
- C. Density of the gas molecules
- D. Forces of attraction between the gas molecules
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Log in to view solution →- A. Is tripled
- B. Is doubled
- C. Is halved
- D. Remains unchanged
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Log in to view solution →- A. 800 kJ mol⁻¹
- B. 100 kJ mol⁻¹
- C. 200 kJ mol⁻¹
- D. 400 kJ mol⁻¹
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Log in to view solution →- A. 800 kJ mol⁻¹
- B. 100 kJ mol⁻¹
- C. 200 kJ mol⁻¹
- D. 400 kJ mol⁻¹
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Log in to view solution →- A. a-iv, b-i, c-ii, d-iii
- B. a-i, b-ii, c-iii, d-iv
- C. a-iv, b-v, c-ii, d-i
- D. a-iii, b-v, c-i, d-ii
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Log in to view solution →- A. a-iv, b-i, c-ii, d-iii
- B. a-i, b-ii, c-iii, d-iv
- C. a-iv, b-v, c-ii, d-i
- D. a-iii, b-v, c-i, d-ii
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Log in to view solution →- A. MnO₄⁻
- B. Cr₂O₇²⁻
- C. CrO₄²⁻
- D. MnO₄²⁻
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Log in to view solution →- A. MnO₄⁻
- B. Cr₂O₇²⁻
- C. CrO₄²⁻
- D. MnO₄²⁻
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Log in to view solution →- A. Ionization isomerism
- B. Coordination isomerism
- C. Geometrical isomerism
- D. Linkage isomerism
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Log in to view solution →- A. Ionization isomerism
- B. Coordination isomerism
- C. Geometrical isomerism
- D. Linkage isomerism
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Log in to view solution →- A. Square planar geometry and paramagnetic
- B. Tetrahedral geometry and diamagnetic
- C. Square planar geometry and diamagnetic
- D. Tetrahedral geometry and paramagnetic
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Log in to view solution →- A. Trinuclear
- B. Mononuclear
- C. Tetranuclear
- D. Dinuclear
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Log in to view solution →- A. A first-order reaction can be catalyzed; a second-order reaction cannot be catalyzed
- B. The half-life of a first-order reaction does not depend on [A]₀; the half-life of a second-order reaction does depend on [A]₀
- C. The rate of a first-order reaction does not depend on reactant concentrations; the rate of a second-order reaction does depend on reactant concentrations
- D. The rate of a first-order reaction does depend on reactant concentrations; the rate of a second-order reaction does not depend on reactant concentrations
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Log in to view solution →- A. BeH₂ < BaH₂ < CaH₂
- B. CaH₂ < BeH₂ < BaH₂
- C. BeH₂ < CaH₂ < BaH₂
- D. BaH₂ < BeH₂ < CaH₂
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Log in to view solution →- A. 0.00224 L of water vapours at 1 atm and 273 K
- B. 0.18 g of water
- C. 18 mL of water
- D. 10⁻³ mol of water
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Log in to view solution →- A. CH₂=CH–CH=CH₂
- B. CH₂=CH–C≡CH
- C. HC≡C–C≡CH
- D. CH₃–CH=CH–CH₃
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Log in to view solution →- A. –NH₂ > –OR > –F
- B. –NR₂ < –OR < –F
- C. –NH₂ < –OR < –F
- D. –NR₂ > –OR > –F
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Log in to view solution →- A. Benzoic acid
- B. Acetanilide
- C. Aniline
- D. Glycine
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Log in to view solution →- A. C₂H₅Cl, C₂H₆, C₂H₅OH
- B. C₂H₅OH, C₂H₅Cl, C₂H₅ONa
- C. C₂H₅OH, C₂H₆, C₂H₅Cl
- D. C₂H₅OH, C₂H₅ONa, C₂H₅Cl
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Log in to view solution →- A. CH₃–CH₃
- B. CH₂=CH₂
- C. CH≡CH
- D. CH₄
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Log in to view solution →- A. N₂O
- B. NO₂
- C. N₂O₅
- D. NO
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Log in to view solution →- A. N₂O
- B. NO₂
- C. N₂O₅
- D. NO
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Log in to view solution →- A. Examples are bakelite and melamine.
- B. They are formed from bi- and tri-functional monomers.
- C. They contain covalent bonds between various linear polymer chains.
- D. They contain strong covalent bonds in their polymer chains.
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Log in to view solution →- A. Examples are bakelite and melamine.
- B. They are formed from bi- and tri-functional monomers.
- C. They contain covalent bonds between various linear polymer chains.
- D. They contain strong covalent bonds in their polymer chains.
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Log in to view solution →- A. BaO
- B. BeO
- C. MgO
- D. CaO
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Log in to view solution →- A. BaO
- B. BeO
- C. MgO
- D. CaO
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Log in to view solution →- A. In absence of substituents nitro group always goes to m-position.
- B. In electrophilic substitution reactions amino group is meta directive.
- C. In spite of substituents nitro group always goes to only m-position.
- D. In acidic (strong) medium aniline is present as anilinium ion.
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Log in to view solution →- A. 2.8
- B. 3.0
- C. 1.4
- D. 4.4
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Log in to view solution →- A. Amylopectin has α(1→4) linkage and α(1→6) linkage.
- B. Amylose has α(1→4) linkage and α(1→6) linkage.
- C. Amylopectin has α(1→4) linkage and α(1→6) linkage.
- D. Amylose is made up of glucose and galactose.
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