- A. 9
- B. 20
- C. 11
- D. 10
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Log in to view solution →- A. Green – Orange – Violet – Gold
- B. Yellow – Green – Violet – Gold
- C. Yellow – Violet – Orange – Silver
- D. Violet – Yellow – Orange – Silver
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Log in to view solution →- A. K_B > K_A > K_C
- B. K_B < K_A < K_C
- C. K_A > K_B > K_C
- D. K_A < K_B < K_C
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Log in to view solution →- A. 'g' on the Earth will not change.
- B. Time period of a simple pendulum on the Earth would decrease.
- C. Walking on the ground would become more difficult.
- D. Raindrops will fall faster.
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Log in to view solution →- A. 2 : 5
- B. 10 : 7
- C. 5 : 7
- D. 7 : 10
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Log in to view solution →- A. 2 : 5
- B. 10 : 7
- C. 5 : 7
- D. 7 : 10
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Log in to view solution →- A. Angular momentum
- B. Rotational kinetic energy
- C. Moment of inertia
- D. Angular velocity
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Log in to view solution →- A. Angular momentum
- B. Rotational kinetic energy
- C. Moment of inertia
- D. Angular velocity
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Log in to view solution →- A. small focal length and small diameter
- B. large focal length and large diameter
- C. large focal length and small diameter
- D. small focal length and large diameter
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Log in to view solution →- A. i = tan⁻¹(1/μ)
- B. i = sin⁻¹(1/μ)
- C. Reflected light is polarised with its electric vector perpendicular to the plane of incidence
- D. Reflected light is polarised with its electric vector parallel to the plane of incidence
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Log in to view solution →- A. 1.7 mm
- B. 2.1 mm
- C. 1.9 mm
- D. 1.8 mm
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Log in to view solution →- A. 16 cm
- B. 12.5 cm
- C. 8 cm
- D. 13.2 cm
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Log in to view solution →- A. 12.5%
- B. 6.25%
- C. 20%
- D. 26.8%
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Log in to view solution →- A. 1.254 × 10⁴ K
- B. 5.016 × 10⁴ K
- C. 8.360 × 10⁴ K
- D. 2.508 × 10⁴ K
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Log in to view solution →- A. 1.5 m/s, 3 m/s
- B. 1 m/s, 3.5 m/s
- C. 1 m/s, 3 m/s
- D. 2 m/s, 4 m/s
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Log in to view solution →- A. a = g tan θ
- B. a = g cos θ
- C. a = g / sin θ
- D. a = g / cosec θ
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Log in to view solution →- A. a = g tan θ
- B. a = g cos θ
- C. a = g / sin θ
- D. a = g / cos θ
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Log in to view solution →- A. 0.529 cm
- B. 0.053 cm
- C. 0.525 cm
- D. 0.521 cm
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Log in to view solution →- A. 0.529 cm
- B. 0.053 cm
- C. 0.525 cm
- D. 0.521 cm
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Log in to view solution →- A. –7î – 4ĵ – 8k̂
- B. –7î – 8ĵ – 4k̂
- C. –4î – ĵ – 8k̂
- D. –8î – 4ĵ – 7k̂
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Log in to view solution →- A. −7î − 4ĵ − 8k̂
- B. −7î − 8ĵ − 4k̂
- C. −4î − ĵ − 8k̂
- D. −8î − 4ĵ − 7k̂
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Log in to view solution →- A. −x direction
- B. −y direction
- C. +z direction
- D. −z direction
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Log in to view solution →- A. 13.89 H
- B. 1.389 H
- C. 138.88 H
- D. 0.138 H
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Log in to view solution →- A. 36 cm towards the mirror
- B. 30 cm towards the mirror
- C. 36 cm away from the mirror
- D. 30 cm away from the mirror
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Log in to view solution →- A. zero
- B. 30°
- C. 45°
- D. 60°
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Log in to view solution →- A. I_B = 40 μA, I_C = 5 mA, β = 125
- B. I_B = 20 μA, I_C = 5 mA, β = 250
- C. I_B = 25 μA, I_C = 5 mA, β = 200
- D. I_B = 40 μA, I_C = 10 mA, β = 250
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Log in to view solution →- A. affects the overall V–I characteristics of p-n junction
- B. does not affect resistance of p-n junction
- C. affects only forward resistance
- D. affects only reverse resistance
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Log in to view solution →- A. B̄·A
- B. B·A + A·B
- C. A·B̄ + Ā·B
- D. B·A
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Log in to view solution →- A. 256/81
- B. 81/256
- C. 3/4
- D. 4/3
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Log in to view solution →- A. F
- B. 4F
- C. 6F
- D. 9F
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Log in to view solution →- A. 84.5 J
- B. 42.2 J
- C. 208.7 J
- D. 104.3 J
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Log in to view solution →- A. r⁴
- B. r⁵
- C. r²
- D. r³
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Log in to view solution →- A. r⁴
- B. r⁵
- C. r²
- D. r³
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Log in to view solution →- A. 11.32 A
- B. 14.76 A
- C. 5.98 A
- D. 7.14 A
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Log in to view solution →- A. 11.32 A
- B. 14.76 A
- C. 5.98 A
- D. 7.14 A
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Log in to view solution →- A. 1.13 W
- B. 2.74 W
- C. 0.43 W
- D. 0.79 W
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Log in to view solution →- A. 1.13 W
- B. 2.74 W
- C. 0.43 W
- D. 0.79 W
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Log in to view solution →- A. the induced electric field due to the changing magnetic field
- B. the lattice structure of the material of the rod
- C. the magnetic field
- D. the current source
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Log in to view solution →- A. 500 Ω
- B. 250 Ω
- C. 25 Ω
- D. 40 Ω
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Log in to view solution →- A. 300 m/s
- B. 350 m/s
- C. 339 m/s
- D. 330 m/s
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Log in to view solution →- A. inversely proportional to the distance between the plates.
- B. proportional to the square root of the distance between the plates.
- C. linearly proportional to the distance between the plates.
- D. independent of the distance between the plates.
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Log in to view solution →- A. 1 s
- B. 2 s
- C. π s
- D. 2π s
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Log in to view solution →- A. equal
- B. 10 times greater
- C. 5 times greater
- D. smaller
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Log in to view solution →- A. λ₀
- B. λ₀ t
- C. λ₀ / (1 + eE₀t / mV₀)
- D. λ₀ (1 + eE₀t / mV₀)
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Log in to view solution →- A. 1 : –2
- B. 2 : –1
- C. 1 : –1
- D. 1 : 1
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Log in to view solution →- A. 2 : 1
- B. 4 : 1
- C. 1 : 4
- D. 1 : 2
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Log in to view solution →- A. 2 : 1
- B. 4 : 1
- C. 1 : 4
- D. 1 : 2
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Log in to view solution →- A. 15
- B. 30
- C. 10
- D. 20
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Log in to view solution →- A. 15
- B. 30
- C. 10
- D. 20
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Log in to view solution →- A. W_A > W_C > W_B
- B. W_B > W_A > W_C
- C. W_A > W_B > W_C
- D. W_C > W_B > W_A
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Log in to view solution →- A. W_A > W_C > W_B
- B. W_B > W_A > W_C
- C. W_A > W_B > W_C
- D. W_C > W_B > W_A
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Log in to view solution →- A. (4/5)D
- B. (5/7)D
- C. D
- D. (2/3)D
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Log in to view solution →- A. Coefficient of sliding friction has dimensions of length.
- B. Frictional force opposes the relative motion.
- C. Limiting value of static friction is directly proportional to normal reaction.
- D. Rolling friction is smaller than sliding friction.
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Log in to view solution →- A. 0.4
- B. 0.8
- C. 0.25
- D. 0.5
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Log in to view solution →- A. Adaptive radiation
- B. Convergent evolution
- C. Analogy
- D. Homology
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Log in to view solution →- A. Amoebiasis
- B. Ringworm disease
- C. Ascariasis
- D. Elephantiasis
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Log in to view solution →- A. Vitamin E
- B. Vitamin B₁₂
- C. Vitamin A
- D. Vitamin D
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Log in to view solution →- A. a, c and e
- B. b, d and e
- C. a, b and c
- D. b, c and e
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Log in to view solution →- A. Eye of octopus, bat and man
- B. Brain of bat, man and cheetah
- C. Heart of bat, man and cheetah
- D. Forelimbs of man, bat and cheetah
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Log in to view solution →- A. Vitiligo
- B. Alzheimer's disease
- C. Rheumatoid arthritis
- D. Psoriasis
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Log in to view solution →- A. a-iv, b-i, c-ii, d-iii
- B. a-ii, b-iii, c-i, d-iv
- C. a-i, b-ii, c-iii, d-iv
- D. a-iii, b-ii, c-iv, d-i
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Log in to view solution →- A. a-v, b-iv, c-i, d-iii
- B. a-v, b-iv, c-i, d-ii
- C. a-iv, b-i, c-ii, d-iii
- D. a-iv, b-v, c-ii, d-iii
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Log in to view solution →- A. is a post-coital contraceptive.
- B. is an IUD.
- C. increases the concentration of estrogen and prevents ovulation in females.
- D. blocks estrogen receptors in the uterus, preventing eggs from getting implanted.
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Log in to view solution →- A. is a post-coital contraceptive.
- B. is an IUD.
- C. increases the concentration of estrogen and prevents ovulation in females.
- D. blocks estrogen receptors in the uterus, preventing eggs from getting implanted.
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Log in to view solution →- A. ectoderm and endoderm
- B. mesoderm and trophoblast
- C. endoderm and mesoderm
- D. ectoderm and mesoderm
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Log in to view solution →- A. ectoderm and endoderm
- B. mesoderm and trophoblast
- C. endoderm and mesoderm
- D. ectoderm and mesoderm
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Log in to view solution →- A. In spermiogenesis spermatozoa are formed, while in spermiation spermatozoa are released from sertoli cells into the cavity of seminiferous tubules.
- B. In spermiogenesis spermatozoa from sertoli cells are released into the cavity of seminiferous tubules, while in spermiation spermatozoa are formed.
- C. In spermiogenesis spermatozoa are formed, while in spermiation spermatids are formed.
- D. In spermiogenesis spermatids are formed, while in spermiation spermatozoa are released.
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Log in to view solution →- A. In spermiogenesis spermatozoa are formed, while in spermiation spermatozoa are released from sertoli cells into the cavity of seminiferous tubules.
- B. In spermiogenesis spermatozoa from sertoli cells are released into the cavity of seminiferous tubules, while in spermiation spermatozoa are formed.
- C. In spermiogenesis spermatozoa are formed, while in spermiation spermatids are formed.
- D. In spermiogenesis spermatids are formed, while in spermiation spermatozoa are formed.
Correct answer & explanation hidden
Log in to view solution →- A. hCG, progestogens, estrogens, glucocorticoids
- B. hCG, hPL, progestogens, estrogens
- C. hCG, hPL, estrogens, relaxin, oxytocin
- D. hCG, hPL, progestogens, prolactin
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Log in to view solution →- A. Parietal cells
- B. Goblet cells
- C. Mucous cells
- D. Chief cells
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Log in to view solution →- A. a-ii, b-iii, c-i
- B. a-i, b-iii, c-ii
- C. a-i, b-ii, c-iii
- D. a-iii, b-ii, c-i
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Log in to view solution →- A. prevents the formation of bonds between the myosin cross bridges and the actin filament.
- B. detaches the myosin head from the actin filament.
- C. activates the myosin ATPase by binding to it.
- D. binds to troponin to remove the masking of active sites on actin for myosin.
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Log in to view solution →- A. Emphysema
- B. Botulism
- C. Silicosis
- D. Anthracis
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Log in to view solution →- A. a-i, b-ii, c-iv, d-iii
- B. a-iii, b-iv, c-i, d-ii
- C. a-i, b-iii, c-iv, d-ii
- D. a-ii, b-i, c-iii, d-iv
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Log in to view solution →- A. Amensalism
- B. Parasitism
- C. Mutualism
- D. Commensalism
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Log in to view solution →- A. Leaves
- B. Roots
- C. Latex
- D. Flowers
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Log in to view solution →- A. pre-reproductive individuals are less than the reproductive individuals.
- B. reproductive and pre-reproductive individuals are equal in number.
- C. reproductive individuals are less than the post-reproductive individuals.
- D. pre-reproductive individuals are more than the reproductive individuals.
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Log in to view solution →- A. Seed banks
- B. Botanical gardens
- C. Sacred groves
- D. Wildlife safari parks
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Log in to view solution →- A. UCCAUAGCGUA
- B. ACCUAUGCGAU
- C. UGGTUTCGCAT
- D. AGGUAUCGCAU
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Log in to view solution →- A. Both sons and daughters
- B. Only grandchildren
- C. Only sons
- D. Only daughters
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Log in to view solution →- A. Both sons and daughters
- B. Only grandchildren
- C. Only sons
- D. Only daughters
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Log in to view solution →- A. a-iii, b-i, c-ii
- B. a-ii, b-iii, c-i
- C. a-i, b-iii, c-ii
- D. a-iii, b-ii, c-i
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Log in to view solution →- A. a-iii, b-i, c-ii
- B. a-ii, b-iii, c-i
- C. a-i, b-iii, c-ii
- D. a-iii, b-ii, c-i
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Log in to view solution →- A. a promoter
- B. an enhancer
- C. structural genes
- D. an operator
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Log in to view solution →- A. a promoter
- B. an enhancer
- C. structural genes
- D. an operator
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Log in to view solution →- A. Minor mutations
- B. Phenotypic variations
- C. Saltation
- D. Multiple step mutations
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Log in to view solution →- A. Minor mutations
- B. Phenotypic variations
- C. Saltation
- D. Multiple step mutations
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Log in to view solution →- A. Decreased respiratory surface; Inflammation of bronchioles
- B. Increased respiratory surface; Inflammation of bronchioles
- C. Increased number of bronchioles; Increased respiratory surface
- D. Inflammation of bronchioles; Decreased respiratory surface
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Log in to view solution →- A. a-ii, b-i, c-iii
- B. a-i, b-ii, c-iii
- C. a-i, b-iii, c-ii
- D. a-iii, b-i, c-ii
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Log in to view solution →- A. a-iv, b-iii, c-ii, d-i
- B. a-i, b-iv, c-ii, d-iii
- C. a-iii, b-i, c-iv, d-ii
- D. a-iii, b-ii, c-i, d-iv
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Log in to view solution →- A. Estriol
- B. Estradiol
- C. Ecdysone
- D. Epinephrine
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Log in to view solution →- A. Corpus callosum: band of fibers connecting left and right cerebral hemispheres.
- B. Hypothalamus: production of releasing hormones and regulation of temperature, hunger and thirst.
- C. Limbic system: consists of fibre tracts that interconnect different regions of brain; controls movement.
- D. Medulla oblongata: controls respiration and cardiovascular reflexes.
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Log in to view solution →- A. Parathyroid hormone and Prolactin
- B. Estrogen and Parathyroid hormone
- C. Progesterone and Aldosterone
- D. Aldosterone and Prolactin
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Log in to view solution →- A. smooth muscles attached to the ciliary body
- B. smooth muscles attached to the iris
- C. ligaments attached to the iris
- D. ligaments attached to the ciliary body
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Log in to view solution →- A. Pleurodont, Diphyodont, Heterodont
- B. Pleurodont, Monophyodont, Homodont
- C. Thecodont, Diphyodont, Heterodont
- D. Thecodont, Diphyodont, Homodont
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Log in to view solution →- A. Phospholipid synthesis
- B. Cleavage of signal peptide
- C. Protein glycosylation
- D. Protein folding
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Log in to view solution →- A. Polytene chromosomes — Oocytes of amphibians
- B. Submetacentric chromosomes — L-shaped chromosomes
- C. Allosomes — Sex chromosomes
- D. Lampbrush chromosomes — Diplotene bivalents
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Log in to view solution →- A. Free ribosomes and RER
- B. Nucleic acids and SER
- C. DNA and RNA
- D. Proteins and lipids
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Log in to view solution →- A. Free ribosomes and RER
- B. Nucleic acids and SER
- C. DNA and RNA
- D. Proteins and lipids
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Log in to view solution →- A. Nucleosome
- B. Plastidome
- C. Polyhedral bodies
- D. Polysome
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Log in to view solution →- A. Nucleosome
- B. Plastidome
- C. Polyhedral bodies
- D. Polysome
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Log in to view solution →- A. Oxidative phosphorylation takes place in outer mitochondrial membrane.
- B. Glycolysis operates as long as it is supplied with NAD that can pick up hydrogen atoms.
- C. Glycolysis occurs in cytosol.
- D. Enzymes of TCA cycle are present in mitochondrial matrix.
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Log in to view solution →- A. Oxidative phosphorylation takes place in outer mitochondrial membrane.
- B. Glycolysis operates as long as it is supplied with NAD that can pick up hydrogen atoms.
- C. Glycolysis occurs in cytosol.
- D. Enzymes of TCA cycle are present in mitochondrial matrix.
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Log in to view solution →- A. Osteichthyes
- B. Aves
- C. Reptilia
- D. Amphibia
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Log in to view solution →- A. Osteichthyes
- B. Aves
- C. Reptilia
- D. Amphibia
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Log in to view solution →- A. having two types of nuclei
- B. using pseudopodia for capturing prey
- C. having a contractile vacuole for removing excess water
- D. using flagella for locomotion
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Log in to view solution →- A. having two types of nuclei
- B. using pseudopodia for capturing prey
- C. having a contractile vacuole for removing excess water
- D. using flagella for locomotion
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Log in to view solution →- A. Starfish
- B. Moth
- C. Tunicate
- D. Earthworm
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Log in to view solution →- A. Presence of anal cerci
- B. Forewings with darker tegmina
- C. Presence of caudal styles
- D. Presence of a boat shaped sternum on the 9th abdominal segment
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Log in to view solution →- A. Euglenoids
- B. Cyanobacteria
- C. Diatoms
- D. Dinoflagellates
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Log in to view solution →- A. Psittacula
- B. Camelus
- C. Chelone
- D. Macropus
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Log in to view solution →- A. T.H. Morgan : Linkage
- B. XO type sex determination : Grasshopper
- C. ABO blood grouping : Co-dominance
- D. Starch synthesis in pea : Multiple alleles
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Log in to view solution →- A. Papaya
- B. Mango
- C. Jackfruit
- D. Bamboo species
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Log in to view solution →- A. Francois Jacob and Jacques Monod – Lac operon
- B. Matthew Meselson and F. Stahl – Pisum sativum
- C. Alfred Hershey and Martha Chase – TMV
- D. Alec Jeffreys – Streptococcus pneumoniae
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Log in to view solution →- A. Transduction was discovered by S. Altman.
- B. Spliceosomes take part in translation.
- C. Punnett square was developed by a British scientist.
- D. Franklin Stahl coined the term 'linkage'.
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Log in to view solution →- A. Sporopollenin
- B. Oil content
- C. Cellulosic intine
- D. Pollenkitt
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Log in to view solution →- A. Parthenogenesis
- B. Parthenocarpy
- C. Mitotic divisions
- D. Meiotic divisions
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Log in to view solution →- A. Virus
- B. Plant
- C. Bacterium
- D. Fungus
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Log in to view solution →- A. Pinus
- B. Mango
- C. Cycas
- D. Mustard
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Log in to view solution →- A. Saccharomyces
- B. Agaricus
- C. Alternaria
- D. Neurospora
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Log in to view solution →- A. Unicellular organism – Chlorella
- B. Gemma cups – Marchantia
- C. Biflagellate zoospores – Brown algae
- D. Uniflagellate gametes – Polysiphonia
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Log in to view solution →- A. a-iii, b-iv, c-i, d-ii
- B. a-ii, b-iv, c-iii, d-i
- C. a-iii, b-ii, c-i, d-iv
- D. a-i, b-iv, c-iii, d-ii
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Log in to view solution →- A. Both ferric and ferrous
- B. Free element
- C. Ferrous
- D. Ferric
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Log in to view solution →- A. Both ferric and ferrous
- B. Free element
- C. Ferrous
- D. Ferric
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Log in to view solution →- A. Viola
- B. Banana
- C. Yucca
- D. Hydrilla
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Log in to view solution →- A. Viola
- B. Banana
- C. Yucca
- D. Hydrilla
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Log in to view solution →- A. Chara
- B. Cycas
- C. Nostoc
- D. Green sulphur bacteria
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Log in to view solution →- A. Chara
- B. Cycas
- C. Nostoc
- D. Green sulphur bacteria
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Log in to view solution →- A. Calcium
- B. Potassium
- C. Sodium
- D. Magnesium
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Log in to view solution →- A. Calcium
- B. Potassium
- C. Sodium
- D. Magnesium
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Log in to view solution →- A. The sign of charge on the ion alone
- B. Both magnitude and sign of the charge on the ion
- C. Size of the ion alone
- D. The magnitude of the charge on the ion alone
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Log in to view solution →- A. 1.08 × 10⁻⁸ mol² L⁻²
- B. 1.08 × 10⁻¹⁴ mol² L⁻²
- C. 1.08 × 10⁻¹² mol² L⁻²
- D. 1.08 × 10⁻¹⁰ mol² L⁻²
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Log in to view solution →- A. CO₂
- B. O₂
- C. H₂
- D. NH₃
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Log in to view solution →- A. c
- B. d
- C. a
- D. b
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Log in to view solution →- A. In
- B. B
- C. Al
- D. Ga
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Log in to view solution →- A. In
- B. B
- C. Al
- D. Ga
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Log in to view solution →- A. Chlorine has the highest electron-gain enthalpy.
- B. All but fluorine show positive oxidation states.
- C. All are oxidizing agents.
- D. All form monobasic oxyacids.
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Log in to view solution →- A. Chlorine has the highest electron-gain enthalpy.
- B. All but fluorine show positive oxidation states.
- C. All are oxidizing agents.
- D. All form monobasic oxyacids.
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Log in to view solution →- A. three
- B. four
- C. two
- D. one
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Log in to view solution →- A. three
- B. four
- C. two
- D. one
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Log in to view solution →- A. Cu
- B. Mg
- C. Zn
- D. Fe
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Log in to view solution →- A. Cu
- B. Mg
- C. Zn
- D. Fe
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Log in to view solution →- A. NH₄Cl, N₂, NO, HNO₃
- B. HNO₃, NH₄Cl, NO, N₂
- C. HNO₃, NO, NH₄Cl, N₂
- D. HNO₃, NO, N₂, NH₄Cl
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Log in to view solution →- A. NH₄Cl, N₂, NO, HNO₃
- B. HNO₃, NH₄Cl, NO, N₂
- C. HNO₃, NO, NH₄Cl, N₂
- D. HNO₃, NO, N₂, NH₄Cl
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Log in to view solution →- A. B < Ga < Al < In < Tl
- B. B < Ga < Al < Tl < In
- C. B < Al < Ga < In < Tl
- D. B < Al < In < Ga < Tl
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Log in to view solution →- A. B < Ga < Al < In < Tl
- B. B < Ga < Al < Tl < In
- C. B < Al < Ga < In < Tl
- D. B < Al < In < Ga < Tl
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Log in to view solution →- A. C₂H₅OH, C₂H₅ONa, C₂H₅Cl
- B. C₂H₅Cl, C₂H₆, C₂H₅OH
- C. C₂H₅OH, C₂H₅Cl, C₂H₅ONa
- D. C₂H₅OH, C₂H₆, C₂H₅Cl
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Log in to view solution →- A. CH₄
- B. CH₃–CH₃
- C. CH₂=CH₂
- D. CH≡CH
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Log in to view solution →- A. NO
- B. N₂O
- C. NO₂
- D. N₂O₅
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Log in to view solution →- A. Linkage isomerism
- B. Ionization isomerism
- C. Coordination isomerism
- D. Geometrical isomerism
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Log in to view solution →- A. MnO₄²⁻
- B. MnO₄⁻
- C. Cr₂O₇²⁻
- D. CrO₄²⁻
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Log in to view solution →- A. a-iii, b-v, c-i, d-ii
- B. a-iv, b-i, c-ii, d-iii
- C. a-i, b-ii, c-iii, d-iv
- D. a-iv, b-v, c-ii, d-i
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Log in to view solution →- A. dinuclear
- B. trinuclear
- C. mononuclear
- D. tetranuclear
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Log in to view solution →- A. tetrahedral geometry and paramagnetic
- B. square planar geometry and paramagnetic
- C. tetrahedral geometry and diamagnetic
- D. square planar geometry and diamagnetic
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Log in to view solution →- A. formation of intermolecular H-bonding
- B. more extensive association of carboxylic acid via van der Waals force of attraction
- C. formation of carboxylate ion
- D. formation of intramolecular H-bonding
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Log in to view solution →- A. 400 kJ mol⁻¹
- B. 800 kJ mol⁻¹
- C. 100 kJ mol⁻¹
- D. 200 kJ mol⁻¹
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Log in to view solution →- A. remains unchanged
- B. is tripled
- C. is doubled
- D. is halved
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Log in to view solution →- A. remains unchanged
- B. is tripled
- C. is doubled
- D. is halved
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Log in to view solution →- A. forces of attraction between the gas molecules
- B. electric field present between the gas molecules
- C. volume of the gas molecules
- D. density of the gas molecules
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Log in to view solution →- A. forces of attraction between the gas molecules
- B. electric field present between the gas molecules
- C. volume of the gas molecules
- D. density of the gas molecules
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Log in to view solution →- A. 5, 16, 2
- B. 2, 16, 5
- C. 2, 5, 16
- D. 16, 5, 2
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Log in to view solution →- A. 5 : 16 : 2
- B. 2 : 16 : 5
- C. 2 : 5 : 16
- D. 16 : 5 : 2
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Log in to view solution →- A. High temperature and low pressure
- B. High temperature and high pressure
- C. Low temperature and low pressure
- D. Low temperature and high pressure
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Log in to view solution →- A. 4.4
- B. 2.8
- C. 3.0
- D. 1.4
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Log in to view solution →- A. Amylose is made up of glucose and galactose
- B. Amylopectin have α 1→4 linkage and α 1→6 linkage
- C. Amylose have α 1→4 linkage and α 1→6 linkage
- D. Amylopectin have α 1→4 linkage and α 1→6 linkage
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Log in to view solution →- A. CaO
- B. BaO
- C. BeO
- D. MgO
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Log in to view solution →- A. They contain strong covalent bonds in their polymer chains.
- B. Examples are bakelite and melamine.
- C. They are formed from bi- and tri-functional monomers.
- D. They contain covalent bonds between various linear polymer chains.
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Log in to view solution →- A. In acidic (strong) medium aniline is present as anilinium ion.
- B. In absence of substituents nitro group always goes to m-position.
- C. In electrophilic substitution reactions amino group is meta directive.
- D. In spite of substituents nitro group always goes to only m-position.
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Log in to view solution →- A. CH₃ – CH = CH – CH₃
- B. CH₂ = CH – CH = CH₂
- C. CH₂ = CH – C≡CH
- D. HC≡C – C≡CH
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Log in to view solution →- A. −NR₂ > −OR > −F
- B. −NH₂ > −OR > −F
- C. −NR₂ < −OR < −F
- D. −NH₂ < −OR < −F
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Log in to view solution →- A. Mg₃X₂
- B. Mg₂X
- C. MgX₂
- D. Mg₂X₃
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Log in to view solution →- A. √2 / 1
- B. 2√4 / 3√3
- C. 2√3 / 3√4
- D. √2 / √3
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Log in to view solution →- A. The value of mₗ for dz² is zero.
- B. The electronic configuration of N atom has all three 2p electrons with parallel spins (half-filled, maximum multiplicity).
- C. An orbital is designated by three quantum numbers while an electron in an atom is designated by four quantum numbers.
- D. Total orbital angular momentum of electron in 's' orbital is equal to zero.
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Log in to view solution →- A. CN
- B. CN⁺
- C. CN⁻
- D. NO
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Log in to view solution →- A. CN
- B. CN⁺
- C. CN⁻
- D. NO
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Log in to view solution →- A. Glycine
- B. Benzoic acid
- C. Acetanilide
- D. Aniline
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Log in to view solution →- A. Glycine
- B. Benzoic acid
- C. Acetanilide
- D. Aniline
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Log in to view solution →- A. the rate of a first-order reaction does depend on reactant concentrations; the rate of a second-order reaction does not depend on reactant concentrations
- B. a first-order reaction can be catalyzed; a second-order reaction cannot be catalyzed
- C. the half-life of a first-order reaction does not depend on [A]₀; the half-life of a second-order reaction does depend on [A]₀
- D. the rate of a first-order reaction does not depend on reactant concentrations; the rate of a second-order reaction does depend on reactant concentrations
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Log in to view solution →- A. BaH₂ < BeH₂ < CaH₂
- B. BeH₂ < BaH₂ < CaH₂
- C. CaH₂ < BeH₢ < BaH₂
- D. BeH₂ < CaH₂ < BaH₂
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Log in to view solution →- A. 10⁻³ mol of water
- B. 0.00224 L of water vapours at 1 atm and 273 K
- C. 0.18 g of water
- D. 18 mL of water
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