- A. 400 kJ mol–1
- B. 200 kJ mol–1
- C. 800 kJ mol–1
- D. 100 kJ mol–1
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Log in to view solution →- A. remains unchanged
- B. is halved
- C. is tripled
- D. is doubled
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Log in to view solution →- A. forces of attraction between the gas molecules
- B. density of the gas molecules
- C. electric field present between the gas molecules
- D. volume of the gas molecules
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Log in to view solution →- A. High temperature and low pressure
- B. Low temperature and high pressure
- C. High temperature and high pressure
- D. Low temperature and low pressure
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Log in to view solution →- A. 5, 16, 2
- B. 16, 5, 2
- C. 2, 16, 5
- D. 2, 5, 16
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Log in to view solution →- A. formation of intermolecular H-bonding
- B. formation of intramolecular H-bonding
- C. more extensive association of carboxylic acid via van der Waals force of attraction
- D. formation of carboxylate ion
Correct answer & explanation hidden
Log in to view solution →- A. formation of intermolecular H-bonding
- B. formation of intramolecular H-bonding
- C. more extensive association of carboxylic acid via van der Waals force of attraction
- D. formation of carboxylate ion
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Log in to view solution →- A. the rate of a first-order reaction does depend on reactant concentrations; the rate of a second-order reaction does not depend on reactant concentrations
- B. the rate of a first-order reaction does not depend on reactant concentrations; the rate of a second-order reaction does depend on reactant concentrations
- C. a first-order reaction can be catalyzed; a second-order reaction cannot be catalyzed
- D. the half-life of a first-order reaction does not depend on [A]0; the half-life of a second-order reaction does depend on [A]0
Correct answer & explanation hidden
Log in to view solution →- A. BaH2 < BeH2 < CaH2
- B. BeH2 < CaH2 < BaH2
- C. BeH2 < BaH2 < CaH2
- D. CaH2 < BeH2 < BaH2
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Log in to view solution →- A. 10^-3 mol of water
- B. 18 mL of water
- C. 0.00224 L of water vapours at 1 atm and 273 K
- D. 0.18 g of water
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Log in to view solution →- A. Amylose is made up of glucose and galactose
- B. Amylopectin have 1->4 alpha-linkage and 1->6 alpha-linkage
- C. Amylopectin have 1->4 alpha-linkage and 1->6 beta-linkage
- D. Amylose have 1->4 alpha-linkage and 1->6 beta-linkage
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Log in to view solution →- A. In acidic (strong) medium aniline is present as anilinium ion.
- B. In spite of substituents nitro group always goes to only m-position.
- C. In absence of substituents nitro group always goes to m-position.
- D. In electrophilic substitution reactions amino group is meta directive.
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Log in to view solution →- A. CaO
- B. MgO
- C. BaO
- D. BeO
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Log in to view solution →- A. They contain strong covalent bonds in their polymer chains.
- B. They contain covalent bonds between various linear polymer chains.
- C. Examples are bakelite and melamine.
- D. They are formed from bi- and tri-functional monomers.
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Log in to view solution →- A. Mg3X2
- B. Mg2X3
- C. Mg2X
- D. MgX2
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Log in to view solution →- A. The value of m for 2z^2d is zero.
- B. Total orbital angular momentum of electron in 's' orbital is equal to zero.
- C. The electronic configuration of N atom is
- D. An orbital is designated by three quantum numbers while an electron in an atom is designated by four quantum numbers.
Correct answer & explanation hidden
Log in to view solution →- A. The value of m for 2pz orbital is zero.
- B. Total orbital angular momentum of electron in 's' orbital is equal to zero.
- C. The electronic configuration of N atom is [He] 2s2 2px1 2py1 2pz1.
- D. An orbital is designated by three quantum numbers while an electron in an atom is designated by four quantum numbers.
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Log in to view solution →- A. CN
- B. NO
- C. CN+
- D. CN-
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Log in to view solution →- A. CN
- B. NO
- C. CN+
- D. CN-
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Log in to view solution →- A. c
- B. b
- C. d
- D. a
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Log in to view solution →- A. 1.08 x 10^-8 mol2 L^-2
- B. 1.08 x 10^-10 mol2 L^-2
- C. 1.08 x 10^-14 mol2 L^-2
- D. 1.08 x 10^-12 mol2 L^-2
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Log in to view solution →- A. The sign of charge on the ion alone
- B. The magnitude of the charge on the ion alone
- C. Both magnitude and sign of the charge on the ion
- D. Size of the ion alone
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Log in to view solution →- A. CO2
- B. NH3
- C. O2
- D. H2
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Log in to view solution →- A. tetrahedral geometry and paramagnetic
- B. square planar geometry and diamagnetic
- C. square planar geometry and paramagnetic
- D. tetrahedral geometry and diamagnetic
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Log in to view solution →- A. dinuclear
- B. tetranuclear
- C. trinuclear
- D. mononuclear
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Log in to view solution →- A. iii v i ii
- B. iv v ii i
- C. iv i ii iii
- D. i ii iii iv
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Log in to view solution →- A. Linkage isomerism
- B. Geometrical isomerism
- C. Ionization isomerism
- D. Coordination isomerism
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Log in to view solution →- A. MnO4^2-
- B. CrO4^2-
- C. MnO4^-
- D. Cr2O7^2-
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Log in to view solution →- A. C2H5OH, C2H5ONa, C2H5Cl
- B. C2H5OH, C2H6, C2H5Cl
- C. C2H5Cl, C2H6, C2H5OH
- D. C2H5OH, C2H5Cl, C2H5ONa
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Log in to view solution →- A. CH4
- B. CH triple bond CH
- C. CH3 - CH3
- D. CH2 = CH2
Correct answer & explanation hidden
Log in to view solution →- A. NO
- B. N2O5
- C. N2O
- D. NO2
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Log in to view solution →- A. CH3 – CH = CH – CH3
- B. HC ≡ C – C ≡ CH
- C. CH2 = CH – CH = CH2
- D. CH2 = CH – C ≡ CH
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Log in to view solution →- A. – NR2 > – OR > – F
- B. – NH2 < – OR < – F
- C. – NH2 > – OR > – F
- D. – NR2 < – OR < – F
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Log in to view solution →- A. Chlorine has the highest electron-gain enthalpy.
- B. All form monobasic oxyacids.
- C. All but fluorine show positive oxidation states.
- D. All are oxidizing agents.
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Log in to view solution →- A. Cu
- B. Fe
- C. Mg
- D. Zn
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Log in to view solution →- A. B < Ga < Al < In < Tl
- B. B < Al < In < Ga < Tl
- C. B < Ga < Al < Tl < In
- D. B < Al < Ga < In < Tl
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Log in to view solution →- A. three
- B. one
- C. four
- D. two
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Log in to view solution →- A. NH4Cl, N2, NO, HNO3
- B. HNO3, NO, N2, NH4Cl
- C. HNO3, NH4Cl, NO, N2
- D. HNO3, NO, NH4Cl, N2
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Log in to view solution →- A. In
- B. Ga
- C. B
- D. Al
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Log in to view solution →- A. Decreased respiratory surface; Inflammation of bronchioles
- B. Inflammation of bronchioles; Decreased respiratory surface
- C. Increased respiratory surface; Inflammation of bronchioles
- D. Increased number of bronchioles; Increased respiratory surface
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Log in to view solution →- A. ii i iii
- B. iii i ii
- C. i ii iii
- D. i iii ii
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Log in to view solution →- A. smooth muscles attached to the ciliary body
- B. ligaments attached to the ciliary body
- C. smooth muscles attached to the iris
- D. ligaments attached to the iris
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Log in to view solution →- A. Estriol
- B. Epinephrine
- C. Estradiol
- D. Ecdysone
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Log in to view solution →- A. Corpus callosum : band of fibers connecting left and right cerebral hemispheres.
- B. Medulla oblongata : controls respiration and cardiovascular reflexes.
- C. Hypothalamus : production of releasing hormones and regulation of temperature, hunger and thirst.
- D. Limbic system : consists of fibre tracts that interconnect different regions of brain; controls movement.
Correct answer & explanation hidden
Log in to view solution →- A. Parathyroid hormone and Prolactin
- B. Aldosterone and Prolactin
- C. Estrogen and Parathyroid hormone
- D. Progesterone and Aldosterone
Correct answer & explanation hidden
Log in to view solution →- A. UCCAUAGCGUA
- B. AGGUAUCGCAU
- C. ACCUAUGCGAU
- D. UGGTUTCGCAT
Correct answer & explanation hidden
Log in to view solution →- A. UCCAUAGCGUA
- B. AGGUAUCGCAU
- C. ACCUAUGCGAU
- D. UGGTUTCGCAT
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Log in to view solution →- A. (1) iii i ii
- B. (2) iii ii i
- C. (3) ii iii i
- D. (4) i iii ii
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Log in to view solution →- A. a promoter
- B. an operator
- C. an enhancer
- D. structural genes
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Log in to view solution →- A. a promoter
- B. an operator
- C. an enhancer
- D. structural genes
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Log in to view solution →- A. Minor mutations
- B. Multiple step mutations
- C. Phenotypic variations
- D. Saltation
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Log in to view solution →- A. Minor mutations
- B. Multiple step mutations
- C. Phenotypic variations
- D. Saltation
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Log in to view solution →- A. Both sons and daughters
- B. Only daughters
- C. Only grandchildren
- D. Only sons
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Log in to view solution →- A. Both sons and daughters
- B. Only daughters
- C. Only grandchildren
- D. Only sons
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Log in to view solution →- A. Amoebiasis
- B. Elephantiasis
- C. Ringworm disease
- D. Ascariasis
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Log in to view solution →- A. Eye of octopus, bat and man
- B. Forelimbs of man, bat and cheetah
- C. Brain of bat, man and cheetah
- D. Heart of bat, man and cheetah
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Log in to view solution →- A. Vitamin E
- B. Vitamin D
- C. Vitamin B12
- D. Vitamin A
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Log in to view solution →- A. Vitiligo
- B. Psoriasis
- C. Alzheimer’s disease
- D. Rheumatoid arthritis
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Log in to view solution →- A. Adaptive radiation
- B. Homology
- C. Convergent evolution
- D. Analogy
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Log in to view solution →- A. a, c and e
- B. b, c and e
- C. b, d and e
- D. a, b and c
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Log in to view solution →- A. (1) i ii iv iii
- B. (2) ii i iii iv
- C. (3) iii iv i ii
- D. (4) i iii iv ii
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Log in to view solution →- A. Seed banks
- B. Wildlife safari parks
- C. Botanical gardens
- D. Sacred groves
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Log in to view solution →- A. Amensalism
- B. Commensalism
- C. Parasitism
- D. Mutualism
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Log in to view solution →- A. pre-reproductive individuals are less than the reproductive individuals.
- B. pre-reproductive individuals are more than the reproductive individuals.
- C. reproductive and pre-reproductive individuals are equal in number.
- D. reproductive individuals are less than the post-reproductive individuals.
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Log in to view solution →- A. Leaves
- B. Flowers
- C. Roots
- D. Latex
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Log in to view solution →- A. hCG, progestogens, estrogens, glucocorticoids
- B. hCG, hPL, progestogens, prolactin
- C. hCG, hPL, progestogens, estrogens
- D. hCG, hPL, estrogens, relaxin, oxytocin
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Log in to view solution →- A. ectoderm and endoderm
- B. ectoderm and mesoderm
- C. mesoderm and trophoblast
- D. endoderm and mesoderm
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Log in to view solution →- A. ectoderm and endoderm
- B. ectoderm and mesoderm
- C. mesoderm and trophoblast
- D. endoderm and mesoderm
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Log in to view solution →- A. is a post-coital contraceptive.
- B. blocks estrogen receptors in the uterus, preventing eggs from getting implanted.
- C. is an IUD.
- D. increases the concentration of estrogen and prevents ovulation in females.
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Log in to view solution →- A. is a post-coital contraceptive.
- B. blocks estrogen receptors in the uterus, preventing eggs from getting implanted.
- C. is an IUD.
- D. increases the concentration of estrogen and prevents ovulation in females.
Correct answer & explanation hidden
Log in to view solution →- A. In spermiogenesis spermatozoa are formed, while in spermiation spermatozoa are released from sertoli cells into the cavity of seminiferous tubules.
- B. In spermiogenesis spermatids are formed, while in spermiation spermatozoa are formed.
- C. In spermiogenesis spermatozoa from sertoli cells are released into the cavity of seminiferous tubules, while in spermiation spermatozoa are formed.
- D. In spermiogenesis spermatozoa are formed, while in spermiation spermatids are formed.
Correct answer & explanation hidden
Log in to view solution →- A. In spermiogenesis spermatozoa are formed, while in spermiation spermatozoa are released from sertoli cells into the cavity of seminiferous tubules.
- B. In spermiogenesis spermatids are formed, while in spermiation spermatozoa are formed.
- C. In spermiogenesis spermatozoa from sertoli cells are released into the cavity of seminiferous tubules, while in spermiation spermatozoa are formed.
- D. In spermiogenesis spermatozoa are formed, while in spermiation spermatids are formed.
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Log in to view solution →- A. iv i ii iii
- B. iii ii iv i
- C. ii iii i iv
- D. i ii iii iv
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Log in to view solution →- A. v iv i iii
- B. iv v ii iii
- C. v iv i ii
- D. iv i ii iii
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Log in to view solution →- A. Parietal cells
- B. Chief cells
- C. Goblet cells
- D. Mucous cells
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Log in to view solution →- A. ii iii i
- B. iii ii i
- C. i iii ii
- D. i ii iii
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Log in to view solution →- A. Emphysema
- B. Anthracis
- C. Botulism
- D. Silicosis
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Log in to view solution →- A. prevents the formation of bonds between the myosin cross bridges and the actin filament.
- B. binds to troponin to remove the masking of active sites on actin for myosin.
- C. detaches the myosin head from the actin filament.
- D. activates the myosin ATPase by binding to it.
Correct answer & explanation hidden
Log in to view solution →- A. Phospholipid synthesis
- B. Protein folding
- C. Cleavage of signal peptide
- D. Protein glycosylation
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Log in to view solution →- A. Nucleosome
- B. Polysome
- C. Plastidome
- D. Polyhedral bodies
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Log in to view solution →- A. Free ribosomes and RER
- B. Proteins and lipids
- C. Nucleic acids and SER
- D. DNA and RNA
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Log in to view solution →- A. Oxidative phosphorylation takes place in outer mitochondrial membrane.
- B. Enzymes of TCA cycle are present in mitochondrial matrix.
- C. Glycolysis operates as long as it is supplied with NAD that can pick up hydrogen atoms.
- D. Glycolysis occurs in cytosol.
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Log in to view solution →- A. Polytene – Oocytes of amphibians chromosomes
- B. Lampbrush – Diplotene bivalents chromosomes
- C. Submetacentric – L-shaped chromosomes
- D. Allosomes – Sex chromosomes
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Log in to view solution →- A. Pleurodont, Diphyodont, Heterodont
- B. Thecodont, Diphyodont, Homodont
- C. Pleurodont, Monophyodont, Homodont
- D. Thecodont, Diphyodont, Heterodont
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Log in to view solution →- A. Pleurodont, Diphyodont, Heterodont
- B. Thecodont, Diphyodont, Homodont
- C. Pleurodont, Monophyodont, Homodont
- D. Thecodont, Diphyodont, Heterodont
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Log in to view solution →- A. Psittacula
- B. Macropus
- C. Camelus
- D. Chelone
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Log in to view solution →- A. Psittacula
- B. Macropus
- C. Camelus
- D. Chelone
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Log in to view solution →- A. Presence of anal cerci
- B. Presence of a boat shaped sternum on the 9th abdominal segment
- C. Forewings with darker tegmina
- D. Presence of caudal styles
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Log in to view solution →- A. Presence of anal cerci
- B. Presence of a boat shaped sternum on the 9th abdominal segment
- C. Forewings with darker tegmina
- D. Presence of caudal styles
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Log in to view solution →- A. Euglenoids
- B. Dinoflagellates
- C. Cyanobacteria
- D. Diatoms
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Log in to view solution →- A. Euglenoids
- B. Dinoflagellates
- C. Cyanobacteria
- D. Diatoms
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Log in to view solution →- A. having two types of nuclei
- B. using flagella for locomotion
- C. using pseudopodia for capturing prey
- D. having a contractile vacuole for removing excess water
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Log in to view solution →- A. having two types of nuclei
- B. using flagella for locomotion
- C. using pseudopodia for capturing prey
- D. having a contractile vacuole for removing excess water
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Log in to view solution →- A. Starfish
- B. Earthworm
- C. Moth
- D. Tunicate
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Log in to view solution →- A. Osteichthyes
- B. Amphibia
- C. Aves
- D. Reptilia
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Log in to view solution →- A. carbonyl and hydroxyl
- B. hydroxyl and methyl
- C. carbonyl and phosphate
- D. carbonyl and methyl
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Log in to view solution →- A. Oscillatoria
- B. Saccharomyces
- C. Nostoc
- D. Mycobacterium
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Log in to view solution →- A. Oxygen
- B. ATP
- C. NADPH
- D. NADH
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Log in to view solution →- A. CO2 concentration
- B. Temperature
- C. O2 concentration
- D. Light
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Log in to view solution →- A. Activation of amino acid
- B. Fatty acid breakdown
- C. Respiration in bacteria
- D. Formation of secretory vesicles
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Log in to view solution →- A. It is a site for active ribosomal RNA synthesis.
- B. Larger nucleoli are present in dividing cells.
- C. It takes part in spindle formation.
- D. It is a membrane-bound structure.
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Log in to view solution →- A. Zygotene
- B. Pachytene
- C. Diakinesis
- D. Diplotene
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Log in to view solution →- A. Barrel shaped
- B. Dumb-bell shaped
- C. Rectangular
- D. Kidney shaped
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Log in to view solution →- A. – 160°C
- B. – 120°C
- C. – 196°C
- D. – 80°C
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Log in to view solution →- A. Chara
- B. Green sulphur bacteria
- C. Cycas
- D. Nostoc
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Log in to view solution →- A. Syngamy and triple fusion
- B. Fusion of two male gametes of a pollen tube with two different eggs
- C. Fusion of two male gametes with one egg
- D. Fusion of one male gamete with two polar nuclei
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Log in to view solution →- A. Viola
- B. Hydrilla
- C. Banana
- D. Yucca
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Log in to view solution →- A. Calcium
- B. Magnesium
- C. Potassium
- D. Sodium
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Log in to view solution →- A. Both ferric and ferrous
- B. Ferric
- C. Free element
- D. Ferrous
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Log in to view solution →- A. It is the final electron acceptor for anaerobic respiration.
- B. It functions as an enzyme.
- C. It is a nucleotide source for ATP synthesis.
- D. It functions as an electron carrier.
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Log in to view solution →- A. Francois Jacob and Jacques Monod – Lac operon
- B. Alec Jeffreys – Streptococcus pneumoniae
- C. Matthew Meselson and F. Stahl – Pisum sativum
- D. Alfred Hershey and Martha Chase – TMV
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Log in to view solution →- A. Francois Jacob and Jacques Monod - Lac operon
- B. Alec Jeffreys - Streptococcus pneumoniae
- C. Matthew Meselson and F. Stahl - Pisum sativum
- D. Alfred Hershey and Martha Chase - TMV
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Log in to view solution →- A. Virus
- B. Fungus
- C. Plant
- D. Bacterium
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Log in to view solution →- A. Virus
- B. Fungus
- C. Plant
- D. Bacterium
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Log in to view solution →- A. Transduction was discovered by S. Altman.
- B. Franklin Stahl coined the term “linkage”.
- C. Spliceosomes take part in translation.
- D. Punnett square was developed by a British scientist.
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Log in to view solution →- A. Transduction was discovered by S. Altman.
- B. Franklin Stahl coined the term 'linkage'.
- C. Spliceosomes take part in translation.
- D. Punnett square was developed by a British scientist.
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Log in to view solution →- A. T.H. Morgan : Linkage
- B. Starch synthesis in pea : Multiple alleles
- C. XO type sex determination : Grasshopper
- D. ABO blood grouping : Co-dominance
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Log in to view solution →- A. T.H. Morgan : Linkage
- B. Starch synthesis in pea : Multiple alleles
- C. XO type sex determination : Grasshopper
- D. ABO blood grouping : Co-dominance
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Log in to view solution →- A. Parthenogenesis
- B. Meiotic divisions
- C. Parthenocarpy
- D. Mitotic divisions
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Log in to view solution →- A. Parthenogenesis
- B. Meiotic divisions
- C. Parthenocarpy
- D. Mitotic divisions
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Log in to view solution →- A. Papaya
- B. Bamboo species
- C. Mango
- D. Jackfruit
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Log in to view solution →- A. Sporopollenin
- B. Pollenkitt
- C. Oil content
- D. Cellulosic intine
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Log in to view solution →- A. Bioexploitation
- B. Bio-infringement
- C. Biodegradation
- D. Biopiracy
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Log in to view solution →- A. pBR 322
- B. Retrovirus
- C. λ phage
- D. Ti plasmid
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Log in to view solution →- A. Denaturation, Annealing, Extension
- B. Extension, Denaturation, Annealing
- C. Denaturation, Extension, Annealing
- D. Annealing, Extension, Denaturation
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Log in to view solution →- A. Basmati
- B. Co-667
- C. Lerma Rojo
- D. Sharbati Sonora
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Log in to view solution →- A. G. Mendel – Transformation
- B. Ribozyme – Nucleic acid
- C. T.H. Morgan – Transduction
- D. F2 × Recessive parent – Dihybrid cross
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Log in to view solution →- A. Genetic Engineering Appraisal Committee (GEAC)
- B. Indian Council of Medical Research (ICMR)
- C. Research Committee on Genetic Manipulation (RCGM)
- D. Council for Scientific and Industrial Research (CSIR)
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Log in to view solution →- A. O3
- B. CO
- C. SO2
- D. CO2
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Log in to view solution →- A. Number of individuals entering a habitat
- B. Death rate
- C. Number of individuals leaving the habitat
- D. Birth rate
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Log in to view solution →- A. the functional role played by the organism where it lives
- B. all the biological factors in the organism’s environment
- C. the range of temperature that the organism needs to live
- D. the physical space where an organism lives
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Log in to view solution →- A. 22nd April
- B. 5th June
- C. 16th September
- D. 21st April
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Log in to view solution →- A. Oxygen
- B. Carbon
- C. Fe
- D. Cl
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Log in to view solution →- A. Upright pyramid of biomass
- B. Inverted pyramid of biomass
- C. Upright pyramid of numbers
- D. Pyramid of energy
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Log in to view solution →- A. Submerged hydrophytes
- B. Halophytes
- C. Carnivorous plants
- D. Free-floating hydrophytes
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Log in to view solution →- A. Submerged hydrophytes
- B. Halophytes
- C. Carnivorous plants
- D. Free-floating hydrophytes
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Log in to view solution →- A. 16 cm
- B. 13.2 cm
- C. 12.5 cm
- D. 8 cm
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Log in to view solution →- A. 1.254 x 10^4 K
- B. 2.508 x 10^4 K
- C. 5.016 x 10^4 K
- D. 8.360 x 10^4 K
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Log in to view solution →- A. 12.5%
- B. 26.8%
- C. 6.25%
- D. 20%
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Log in to view solution →- A. 1.13 W
- B. 0.79 W
- C. 2.74 W
- D. 0.43 W
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Log in to view solution →- A. the induced electric field due to the changing magnetic field
- B. the current source
- C. the lattice structure of the material of the rod
- D. the magnetic field
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Log in to view solution →- A. the induced electric field due to the changing magnetic field
- B. the current source
- C. the lattice structure of the material of the rod
- D. the magnetic field
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Log in to view solution →- A. 500 Ohm
- B. 40 Ohm
- C. 250 Ohm
- D. 25 Ohm
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Log in to view solution →- A. 500 Ω
- B. 40 Ω
- C. 250 Ω
- D. 25 Ω
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Log in to view solution →- A. 0.4
- B. 0.5
- C. 0.8
- D. 0.25
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Log in to view solution →- A. Coefficient of sliding friction has dimensions of length.
- B. Rolling friction is smaller than sliding friction.
- C. Frictional force opposes the relative motion.
- D. Limiting value of static friction is directly proportional to normal reaction.
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Log in to view solution →- A. WA > WC > WB
- B. WC > WB > WA
- C. WB > WA > WC
- D. WA > WB > WC
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Log in to view solution →- A. i = tan^-1(1/μ)
- B. Reflected light is polarised with its electric vector parallel to the plane of incidence
- C. i = sin^-1(1/μ)
- D. Reflected light is polarised with its electric vector perpendicular to the plane of incidence
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Log in to view solution →- A. 1.7 mm
- B. 1.8 mm
- C. 2.1 mm
- D. 1.9 mm
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Log in to view solution →- A. small focal length and small diameter
- B. small focal length and large diameter
- C. large focal length and large diameter
- D. large focal length and small diameter
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Log in to view solution →- A. affects the overall V – I characteristics of p-n junction
- B. affects only reverse resistance
- C. does not affect resistance of p-n junction
- D. affects only forward resistance
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Log in to view solution →- A. affects the overall V – I characteristics of p-n junction
- B. affects only reverse resistance
- C. does not affect resistance of p-n junction
- D. affects only forward resistance
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Log in to view solution →- A. Green – Orange – Violet – Gold
- B. Violet – Yellow – Orange – Silver
- C. Yellow – Green – Violet – Gold
- D. Yellow – Violet – Orange – Silver
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Log in to view solution →- A. Green – Orange – Violet – Gold
- B. Violet – Yellow – Orange – Silver
- C. Yellow – Green – Violet – Gold
- D. Yellow – Violet – Orange – Gold
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Log in to view solution →- A. 9
- B. 10
- C. 20
- D. 11
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Log in to view solution →- A. 9
- B. 10
- C. 20
- D. 11
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Log in to view solution →- A. F
- B. 9 F
- C. 4 F
- D. 6 F
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Log in to view solution →- A. 84.5 J
- B. 104.3 J
- C. 42.2 J
- D. 208.7 J
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Log in to view solution →- A. r^4
- B. r^3
- C. r^5
- D. r^2
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Log in to view solution →- A. 256/81
- B. 4/3
- C. 81/256
- D. 3/4
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Log in to view solution →- A. 1 s
- B. 2π s
- C. 2 s
- D. π s
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Log in to view solution →- A. 300 m/s
- B. 330 m/s
- C. 350 m/s
- D. 339 m/s
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Log in to view solution →- A. inversely proportional to the distance between the plates.
- B. independent of the distance between the plates.
- C. proportional to the square root of the distance between the plates.
- D. linearly proportional to the distance between the plates.
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Log in to view solution →- A. inversely proportional to the distance between the plates.
- B. independent of the distance between the plates.
- C. proportional to the square root of the distance between the plates.
- D. linearly proportional to the distance between the plates.
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Log in to view solution →- A. 2 : 1
- B. 1 : 2
- C. 4 : 1
- D. 1 : 4
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Log in to view solution →- A. 2 : 1
- B. 1 : 2
- C. 4 : 1
- D. 1 : 4
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Log in to view solution →- A. 15
- B. 20
- C. 30
- D. 10
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Log in to view solution →- A. 15
- B. 20
- C. 30
- D. 10
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Log in to view solution →- A. 1 : -2
- B. 1 : 1
- C. 2 : -1
- D. 1 : -1
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Log in to view solution →- A. λ₀
- B. (λ₀) / (1 + (eE₀t / mV₀))
- C. λ₀t
- D. λ₀(1 + (eE₀t / mV₀))
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Log in to view solution →- A. 2 : 5
- B. 7 : 10
- C. 10 : 7
- D. 5 : 7
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Log in to view solution →- A. ‘g’ on the Earth will not change.
- B. Raindrops will fall faster.
- C. Time period of a simple pendulum on the Earth would decrease.
- D. Walking on the ground would become more difficult.
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Log in to view solution →- A. Angular momentum
- B. Angular velocity
- C. Rotational kinetic energy
- D. Moment of inertia
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Log in to view solution →- A. 13.89 H
- B. 0.138 H
- C. 1.389 H
- D. 138.88 H
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Log in to view solution →- A. – x direction
- B. – z direction
- C. – y direction
- D. + z direction
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Log in to view solution →- A. - x direction
- B. - z direction
- C. - y direction
- D. + z direction
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Log in to view solution →- A. a = g tan θ
- B. a = g / cos θ
- C. a = g cos θ
- D. a = g / sin θ
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Log in to view solution →- A. 0.529 cm
- B. 0.521 cm
- C. 0.053 cm
- D. 0.525 cm
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Log in to view solution →- A. - 7î - 4ĵ - 8k̂
- B. - 8î - 4ĵ - 7k̂
- C. - 7î - 8ĵ - 4k̂
- D. - 4î - ĵ - 8k̂
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Log in to view solution →- A. 1.5 m/s, 3 m/s
- B. 2 m/s, 4 m/s
- C. 1 m/s, 3.5 m/s
- D. 1 m/s, 3 m/s
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