- A. PS-I to NADP
- B. PS-I to ATP synthase
- C. PS-II to Cytb6f complex
- D. Cytb6f complex to PS-I
Correct answer & explanation hidden
Log in to view solution →- A. Palindromic sequence
- B. Recognition site
- C. Selectable marker
- D. Ori site
Correct answer & explanation hidden
Log in to view solution →- A. 5' - CTTAAG - 3' 3' - GAATTC - 5'
- B. 5' - GGATCC - 3' 3' - CCTAGG - 5'
- C. 5' - GAATTC - 3' 3' - CTTAAG - 5'
- D. 5' - GGAACC - 3' 3' - CCTTGG - 5'
Correct answer & explanation hidden
Log in to view solution →- A. Active immunity is quick and gives full response.
- B. Foetus receives some antibodies from mother, it is an example for passive immunity.
- C. When exposed to antigen (living or dead) antibodies are produced in the host’s body. It is called “Active immunity”.
- D. When ready-made antibodies are directly given, it is called “Passive immunity”.
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Log in to view solution →- A. Boveri
- B. Morgan
- C. Mendel
- D. Sutton
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Log in to view solution →- A. (iii)(iv)(ii)(i)
- B. (iv)(i)(ii)(iii)
- C. (ii)(i)(iv)(iii)
- D. (iv)(iii)(ii)(i)
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Log in to view solution →- A. Acetocarmine in UV radiation
- B. Ethidium bromide in infrared radiation
- C. Acetocarmine in bright blue light
- D. Ethidium bromide in UV radiation
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Log in to view solution →- A. DNA polymerase
- B. RNA polymerase
- C. DNA ligase
- D. DNA helicase
Correct answer & explanation hidden
Log in to view solution →- A. DNA polymerase
- B. RNA polymerase
- C. DNA ligase
- D. DNA helicase
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Log in to view solution →- A. ICSI and ZIFT
- B. GIFT and ICSI
- C. ZIFT and IUT
- D. GIFT and ZIFT
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Log in to view solution →- A. Lysine
- B. Valine
- C. Tyrosine
- D. Glutamic Acid
Correct answer & explanation hidden
Log in to view solution →- A. Higher H+ conc. in alveoli favours the formation of oxyhaemoglobin.
- B. Low pCO2 in alveoli favours the formation of oxyhaemoglobin.
- C. Binding of oxygen with haemoglobin is mainly related to partial pressure of O2.
- D. Partial pressure of CO2 can interfere with O2 binding with haemoglobin.
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Log in to view solution →- A. Mannitol and algin
- B. Laminarin and cellulose
- C. Starch and cellulose
- D. Amylopectin and glycogen
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Log in to view solution →- A. Cross breeding
- B. Inbreeding
- C. Out crossing
- D. Mutational breeding
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Log in to view solution →- A. (a)-(iii), (b)-(i), (c)-(iv), (d)-(ii)
- B. (a)-(ii), (b)-(i), (c)-(iv), (d)-(iii)
- C. (a)-(iv), (b)-(iii), (c)-(i), (d)-(ii)
- D. (a)-(iii), (b)-(ii), (c)-(i), (d)-(iv)
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Log in to view solution →- A. AIDS, Malaria, Filaria
- B. Cancer, AIDS, Syphilis
- C. Gonorrhoea, Syphilis, Genital herpes
- D. Gonorrhoea, Malaria, Genital herpes
Correct answer & explanation hidden
Log in to view solution →- A. Nucleases - Separate the two strands of DNA
- B. Exonucleases - Make cuts at specific positions within DNA
- C. Ligases - Join the two DNA molecules
- D. Polymerases - Break the DNA into fragments
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Log in to view solution →- A. Hypogynous ovary
- B. Half inferior ovary
- C. Inferior ovary
- D. Superior ovary
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Log in to view solution →- A. (a)(iii), (b)(ii), (c)(iv), (d)(i)
- B. (a)(iii), (b)(iv), (c)(i), (d)(ii)
- C. (a)(ii), (b)(iv), (c)(iii), (d)(i)
- D. (a)(iv), (b)(iii), (c)(i), (d)(ii)
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Log in to view solution →- A. Ammonia and oxygen
- B. Ammonia and hydrogen
- C. Ammonia alone
- D. Nitrate alone
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Log in to view solution →- A. Ethylene
- B. Abscisic acid
- C. Cytokinin
- D. Gibberellin
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Log in to view solution →- A. Nucellus
- B. Chalaza
- C. Hilum
- D. Micropyle
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Log in to view solution →- A. Senescence
- B. Dormancy
- C. Log phase
- D. Lag phase
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Log in to view solution →- A. Aschelminthes
- B. Annelida
- C. Ctenophora
- D. Platyhelminthes
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Log in to view solution →- A. Effluents of primary treatment
- B. Activated sludge
- C. Primary sludge
- D. Floating debris
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Log in to view solution →- A. (a)-(iii), (b)-(ii), (c)-(iv), (d)-(i)
- B. (a)-(iv), (b)-(iii), (c)-(i), (d)-(ii)
- C. (a)-(ii), (b)-(iv), (c)-(i), (d)-(iii)
- D. (a)-(i), (b)-(iii), (c)-(ii), (d)-(iv)
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Log in to view solution →- A. They are useful in genetic engineering.
- B. Sticky ends can be joined by using DNA ligases.
- C. Each restriction enzyme functions by inspecting the length of a DNA sequence.
- D. They cut the strand of DNA at palindromic sites.
Correct answer & explanation hidden
Log in to view solution →- A. (1)(iii)(ii)(i)(iv)
- B. (2)(ii)(i)(iii)(iv)
- C. (3)(i)(iii)(ii)(iv)
- D. (4)(iv)(i)(ii)(iii)
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Log in to view solution →- A. the head holds a small proportion of a nervous system while the rest is situated along the ventral part of its body.
- B. the head holds a 1/3rd of a nervous system while the rest is situated along the dorsal part of its body.
- C. the supra-oesophageal ganglia of the cockroach are situated in ventral part of abdomen.
- D. the cockroach does not have nervous system.
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Log in to view solution →- A. Himalayas
- B. Amazon forests
- C. Western Ghats of India
- D. Madagascar
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Log in to view solution →- A. Golgi bodies
- B. Polysomes
- C. Endoplasmic reticulum
- D. Peroxisomes
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Log in to view solution →- A. Anabaena and Volvox
- B. Chlorella and Spirulina
- C. Laminaria and Sargassum
- D. Gelidium and Gracilaria
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Log in to view solution →- A. Lectin
- B. Insulin
- C. Haemoglobin
- D. Collagen
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Log in to view solution →- A. Diplotene
- B. Leptotene
- C. Pachytene
- D. Zygotene
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Log in to view solution →- A. 14
- B. 8
- C. 4
- D. 2
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Log in to view solution →- A. proximal convoluted tubule of nephron
- B. eustachian tube
- C. lining of intestine
- D. ducts of salivary glands
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Log in to view solution →- A. (1)(i)(ii)(iv)(iii)
- B. (2)(ii)(iv)(iii)(i)
- C. (3)(iii)(iv)(i)(ii)
- D. (4)(iv)(iii)(ii)(i)
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Log in to view solution →- A. They lie free in the cytoplasm.
- B. These represent reserve material in cytoplasm.
- C. They are not bound by any membrane.
- D. These are involved in ingestion of food particles.
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Log in to view solution →- A. Atrial natriuretic factor causes vasoconstriction
- B. Decrease in secretion of renin by JG cells
- C. More water reabsorption due to undersecretion of ADH
- D. Reabsorption of Na+ and water from renal tubules due to aldosterone
Correct answer & explanation hidden
Log in to view solution →- A. Dicotyledonous stem
- B. Dicotyledonous root
- C. Monocotyledonous stem
- D. Monocotyledonous root
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Log in to view solution →- A. Dicotyledonous stem
- B. Dicotyledonous root
- C. Monocotyledonous stem
- D. Monocotyledonous root
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Log in to view solution →- A. Adenine pairs with thymine through three H-bonds.
- B. Adenine does not pair with thymine.
- C. Adenine pairs with thymine through two H-bonds.
- D. Adenine pairs with thymine through one H-bond.
Correct answer & explanation hidden
Log in to view solution →- A. Adenine pairs with thymine through three H-bonds.
- B. Adenine does not pair with thymine.
- C. Adenine pairs with thymine through two H-bonds.
- D. Adenine pairs with thymine through one H-bond.
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Log in to view solution →- A. (1)(ii)(iii)(iv)(i)
- B. (2)(i)(ii)(iii)(iv)
- C. (3)(iv)(i)(ii)(iii)
- D. (4)(iii)(ii)(i)(iv)
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Log in to view solution →- A. Industrial melanism
- B. Natural selection
- C. Adaptive radiation
- D. Convergent evolution
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Log in to view solution →- A. 1 molecule of 6-C compound
- B. 1 molecule of 4-C compound and 1 molecule of 2-C compound
- C. 2 molecules of 3-C compound
- D. 1 molecule of 3-C compound
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Log in to view solution →- A. Female gametocytes
- B. Male gametocytes
- C. Trophozoites
- D. Sporozoites
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Log in to view solution →- A. Sapwood is the innermost secondary xylem and is lighter in colour.
- B. Due to deposition of tannins, resins, oils etc., heart wood is dark in colour.
- C. Heart wood does not conduct water but gives mechanical support.
- D. Sapwood is involved in conduction of water and minerals from root to leaf.
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Log in to view solution →- A. They have DNA with protein coat.
- B. They have free DNA without protein coat.
- C. They have RNA with protein coat.
- D. They have free RNA without protein coat.
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Log in to view solution →- A. (1)(ii)(i)(iii)(iv)
- B. (2)(iv)(i)(ii)(iii)
- C. (3)(i)(iii)(ii)(iv)
- D. (4)(iii)(iv)(i)(ii)
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Log in to view solution →- A. When IA and IB are present together, they express same type of sugar.
- B. Allele ‘i’ does not produce any sugar.
- C. The gene (I) has three alleles.
- D. A person will have only two of the three alleles.
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Log in to view solution →- A. 50 million
- B. 7 million
- C. 1.5 million
- D. 20 million
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Log in to view solution →- A. Mortality
- B. Species interaction
- C. Sex ratio
- D. Natality
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Log in to view solution →- A. wind and water
- B. insects and water
- C. insects or wind
- D. water currents only
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Log in to view solution →- A. Depolarisation of ventricles
- B. Repolarisation of ventricles
- C. Repolarisation of auricles
- D. Depolarisation of auricles
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Log in to view solution →- A. Sickle cell anaemia -Autosomal recessive trait, chromosome-11
- B. Thalassemia -X linked
- C. Haemophilia -Y linked
- D. Phenylketonuria -Autosomal dominant trait
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Log in to view solution →- A. Two
- B. Three
- C. Zero
- D. One
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Log in to view solution →- A. (1)(iii)(iv)(i)(ii)
- B. (2)(ii)(iii)(i)(iv)
- C. (3)(ii)(iv)(iii)(i)
- D. (4)(iii)(i)(iv)(ii)
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Log in to view solution →- A. (b), (c) and (d)
- B. only (d)
- C. only (a)
- D. (a) and (c)
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Log in to view solution →- A. S phase
- B. G2 phase
- C. M phase
- D. G1 phase
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Log in to view solution →- A. Defence action
- B. Effect on reproduction
- C. Nutritive value
- D. Growth response
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Log in to view solution →- A. After zygote formation
- B. At the time of fusion of a sperm with an ovum
- C. Prior to ovulation
- D. At the time of copulation
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Log in to view solution →- A. The functional insulin has A and B chains linked together by hydrogen bonds.
- B. Genetically engineered insulin is produced in E-Coli.
- C. In man insulin is synthesised as a proinsulin.
- D. The proinsulin has an extra peptide called C-peptide.
Correct answer & explanation hidden
Log in to view solution →- A. High reflection of light from snow
- B. Damage to retina caused by infra-red rays
- C. Freezing of fluids in the eye by low temperature
- D. Inflammation of cornea due to high dose of UV-B radiation
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Log in to view solution →- A. Marchantia
- B. Equisetum
- C. Salvinia
- D. Pteris
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Log in to view solution →- A. CH4, H2, NH3 and water vapor at 6008C
- B. CH3, H2, NH3 and water vapor at 6008C
- C. CH4, H2, NH3 and water vapor at 8008C
- D. CH3, H2, NH4 and water vapor at 8008C
Correct answer & explanation hidden
Log in to view solution →- A. Gross primary productivity and Net primary productivity are one and same.
- B. There is no relationship between Gross primary productivity and Net primary productivity.
- C. Gross primary productivity is always less than net primary productivity.
- D. Gross primary productivity is always more than net primary productivity.
Correct answer & explanation hidden
Log in to view solution →- A. (1)(iv)(iii)(ii)(i)
- B. (2)(i)(ii)(iii)(iv)
- C. (3)(ii)(iii)(iv)(i)
- D. (4)(iii)(ii)(i)(iv)
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Log in to view solution →- A. Insulin acts on pancreatic cells and adipocytes.
- B. Insulin is associated with hyperglycemia.
- C. Glucocorticoids stimulate gluconeogenesis.
- D. Glucagon is associated with hypoglycemia.
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Log in to view solution →- A. (a), (b) and (d)
- B. only (d)
- C. (a) and (b)
- D. (c) and (d)
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Log in to view solution →- A. Prop roots
- B. Lateral roots
- C. Fibrous roots
- D. Primary roots
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Log in to view solution →- A. Chondrocytes
- B. Compound epithelial cells
- C. Squamous epithelial cells
- D. Columnar epithelial cells
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Log in to view solution →- A. Release of Green House gases
- B. Disposal of e-wastes
- C. Transport of Genetically modified organisms from one country to another
- D. Emission of ozone depleting substances
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Log in to view solution →- A. (a) and (b)
- B. (b) and (c)
- C. (d) and (c)
- D. (c) and (a)
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Log in to view solution →- A. Cellulose, lecithin
- B. Inulin, insulin
- C. Chitin, cholesterol
- D. Glycerol, trypsin
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Log in to view solution →- A. (1)(iii)(ii)(iv)(i)
- B. (2)(ii)(iii)(iv)(i)
- C. (3)(iv)(iii)(i)(ii)
- D. (4)(i)(iv)(ii)(iii)
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Log in to view solution →- A. 2.2 meters
- B. 2.7 meters
- C. 2.0 meters
- D. 2.5 meters
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Log in to view solution →- A. Sunflower
- B. Plum
- C. Brinjal
- D. Mustard
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Log in to view solution →- A. Cell is metabolically active, grows but does not replicate its DNA.
- B. Nuclear Division takes place.
- C. DNA synthesis or replication takes place.
- D. Reorganisation of all cell components takes place.
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Log in to view solution →- A. Low concentration of LH
- B. Low concentration of FSH
- C. High concentration of Estrogen
- D. High concentration of Progesterone
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Log in to view solution →- A. Ileum is a highly coiled part.
- B. Vermiform appendix arises from duodenum.
- C. Ileum opens into small intestine.
- D. Serosa is the innermost layer of the alimentary canal.
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Log in to view solution →- A. (i)(ii)(iv)(iii)
- B. (ii)(i)(iii)(iv)
- C. (iii)(iv)(ii)(i)
- D. (iv)(i)(ii)(iii)
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Log in to view solution →- A. (c) and (d)
- B. (a) and (d)
- C. (a) only
- D. (a), (b) and (c)
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Log in to view solution →- A. Plant nematodes
- B. Insect predators
- C. Insect pests
- D. Fungal diseases
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Log in to view solution →- A. Aminoacylation of tRNA
- B. Recognition of an anti-codon
- C. Binding of mRNA to ribosome
- D. Recognition of DNA molecule
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Log in to view solution →- A. Charles Darwin
- B. Oparin
- C. Karl Ernst von Baer
- D. Alfred Wallace
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Log in to view solution →- A. (iv)(ii)(iii)(i)
- B. (i)(iv)(iii)(ii)
- C. (ii)(iii)(iv)(i)
- D. (iii)(iv)(i)(ii)
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Log in to view solution →- A. (i)(ii)(iv)(iii)
- B. (iv)(iii)(ii)(i)
- C. (iii)(iv)(ii)(i)
- D. (ii)(i)(iv)(iii)
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Log in to view solution →- A. Phenolic acid
- B. Para-ascorbic acid
- C. Gibberellic acid
- D. Abscisic acid
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Log in to view solution →- A. (iv)(ii)(i)(iii)
- B. (i)(ii)(iv)(iii)
- C. (ii)(iii)(i)(iv)
- D. (iii)(i)(iv)(ii)
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Log in to view solution →- A. (a)-(iv), (b)-(ii), (c)-(i), (d)-(iii)
- B. (a)-(i), (b)-(ii), (c)-(iv), (d)-(iii)
- C. (a)-(ii), (b)-(iii), (c)-(i), (d)-(iv)
- D. (a)-(iii), (b)-(i), (c)-(iv), (d)-(ii)
Correct answer & explanation hidden
Log in to view solution →- A. caseinogen into casein
- B. pepsinogen into pepsin
- C. protein into polypeptides
- D. trypsinogen into trypsin
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Log in to view solution →- A. Ketonuria and Glycosuria
- B. Renal calculi and Hyperglycaemia
- C. Uremia and Ketonuria
- D. Uremia and Renal Calculi
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Log in to view solution →- A. Imbibition
- B. Plasmolysis
- C. Transpiration
- D. Root pressure
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Log in to view solution →- A. 400 V
- B. zero
- C. 50 V
- D. 200 V
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Log in to view solution →- A. 1.0
- B. -1.0
- C. zero
- D. 0.5
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Log in to view solution →- A. one-fourth
- B. zero
- C. doubled
- D. four times
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Log in to view solution →- A. [ M L^0 T^-2 ]
- B. [ M L^-1 T^-2 ]
- C. [ M L T^-2 ]
- D. [ M L^2 T^-2 ]
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Log in to view solution →- A. 10^3 V
- B. 10^4 V
- C. 10 V
- D. 10^2 V
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Log in to view solution →- A. 0.44 x 10^-10 C² N^-1 m^-2
- B. 5.00 C² N^-1 m^-2
- C. 0.44 x 10^-13 C² N^-1 m^-2
- D. 1.77 x 10^-12 C² N^-1 m^-2
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Log in to view solution →- A. semiconductors only
- B. insulators and semiconductors
- C. metals
- D. insulators only
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Log in to view solution →- A. Both emitter junction as well as the collector junction are forward biased.
- B. The base region must be very thin and lightly doped.
- C. Base, emitter and collector regions should have same doping concentrations.
- D. Base, emitter and collector regions should have same size.
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Log in to view solution →- A. 0.5 mm
- B. 1.0 mm
- C. 0.01 mm
- D. 0.25 mm
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Log in to view solution →- A. π/2 rad
- B. zero
- C. π rad
- D. 3π/2 rad
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Log in to view solution →- A. 6.28 x 10^-5 T
- B. 3.14 x 10^-5 T
- C. 6.28 x 10^-4 T
- D. 3.14 x 10^-4 T
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Log in to view solution →- A. 320 m
- B. 300 m
- C. 360 m
- D. 340 m
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Log in to view solution →- A. 4.7 kΩ, 5%
- B. 470 Ω, 5%
- C. 470 kΩ, 5%
- D. 47 kΩ, 10%
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Log in to view solution →- A. 45° < i_b < 90°
- B. i_b = 90°
- C. 0° < i_b < 30°
- D. 30° < i_b < 45°
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Log in to view solution →- A. µA
- B. A / (2µ)
- C. A / (2µ)
- D. 2A / µ
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Log in to view solution →- A. isochoric
- B. isobaric
- C. isothermal
- D. adiabatic
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Log in to view solution →- A. Deuteron atom
- B. Singly ionised neon atom (Ne+)
- C. Hydrogen atom
- D. Singly ionised helium atom (He+)
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Log in to view solution →- A. g/5
- B. g/10
- C. g
- D. g/2
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Log in to view solution →- A. 1 N/C
- B. 5 N/C
- C. zero
- D. 0.5 N/C
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Log in to view solution →- A. 110/36 Kr
- B. 103/36 Kr
- C. 144/56 Ba
- D. 91/40 Zr
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Log in to view solution →- A. 1.5×10^13 J
- B. 0.5×10^13 J
- C. 4.5×10^16 J
- D. 4.5×10^13 J
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Log in to view solution →- A. 1 / (sqrt(2) * n * pi * d^2)
- B. 1 / (sqrt(2) * n * pi * d^2)
- C. 1 / (n * pi * d^2)
- D. 1 / (2 * n * pi * d^2)
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Log in to view solution →- A. MgL / AL1
- B. MgL / A(L1 - L)
- C. MgL / AL
- D. Mg(L1 - L) / AL
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Log in to view solution →- A. 0.06
- B. 0.006
- C. 6
- D. 0.6
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Log in to view solution →- A. 30 N
- B. 24 N
- C. 48 N
- D. 32 N
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Log in to view solution →- A. four times
- B. one-fourth
- C. double
- D. half
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Log in to view solution →- A. 10.0 g
- B. 20.0 g
- C. 2.5 g
- D. 5.0 g
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Log in to view solution →- A. 0.1 kg/m^3
- B. 0.02 kg/m^3
- C. 0.5 kg/m^3
- D. 0.2 kg/m^3
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Log in to view solution →- A. 2.4π×10^-5 T m A^-1
- B. 2.4π×10^-7 T m A^-1
- C. 2.4π×10^-4 T m A^-1
- D. 8.0×10^-5 T m A^-1
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Log in to view solution →- A. -6 N m i-hat
- B. 6 N m k-hat
- C. 6 N m i-hat
- D. 6 N m j-hat
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Log in to view solution →- A. 5/2 kB T
- B. 7/2 kB T
- C. 1/2 kB T
- D. 3/2 kB T
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Log in to view solution →- A. 7.32×10^-7 rad
- B. 6.00×10^-7 rad
- C. 3.66×10^-7 rad
- D. 1.83×10^-7 rad
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Log in to view solution →- A. 24×10^3 J
- B. 48×10^3 J
- C. 10×10^3 J
- D. 12×10^3 J
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Log in to view solution →- A. 24 × 10^3 J
- B. 48 × 10^3 J
- C. 10 × 10^3 J
- D. 12 × 10^3 J
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Log in to view solution →- A. 1 : c
- B. 1 : c^2
- C. c : 1
- D. 1 : 1
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Log in to view solution →- A. 1.5 × 10^-1 m
- B. 1.5 × 10^-2 m
- C. 1.0 × 10^-2 m
- D. 1.0 × 10^-1 m
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Log in to view solution →- A. both forward bias and reverse bias
- B. increase in forward current
- C. forward bias only
- D. reverse bias only
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Log in to view solution →- A. 2.5 A
- B. 25.1 A
- C. 1.7 A
- D. 2.05 A
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Log in to view solution →- A. 9.980 m
- B. 9.9 m
- C. 9.9801 m
- D. 9.98 m
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Log in to view solution →- A. 2.5 × 10^-6
- B. 2.25 × 10^-15
- C. 2.25 × 10^15
- D. 2.5 × 10^6
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Log in to view solution →- A. 536 Hz
- B. 537 Hz
- C. 523 Hz
- D. 524 Hz
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Log in to view solution →- A. 67 cm
- B. 80 cm
- C. 33 cm
- D. 50 cm
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Log in to view solution →- A. Cross Cannizzaro’s reaction
- B. Cross Aldol condensation
- C. Aldol condensation
- D. Cannizzaro’s reaction
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Log in to view solution →- A. Stability of the colloidal particles
- B. Size of the colloidal particles
- C. Viscosity
- D. Solubility
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Log in to view solution →- A. -R effect of -CH3 groups
- B. Hyperconjugation
- C. -I effect of -CH3 groups
- D. 1R effect of -CH3 groups
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Log in to view solution →- A. q < 0, ΔT=0 and w=0
- B. q > 0, ΔT > 0 and w > 0
- C. q=0, ΔT=0 and w=0
- D. q=0, ΔT < 0 and w > 0
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Log in to view solution →- A. (iii)(iv)(i)(ii)
- B. (iv)(iii)(ii)(i)
- C. (i)(ii)(iii)(iv)
- D. (ii)(i)(iv)(iii)
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Log in to view solution →- A. Tert. butyl alcohol
- B. Isobutyl alcohol
- C. Isopropyl alcohol
- D. Sec. butyl alcohol
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Log in to view solution →- A. Calcium
- B. Potassium
- C. Iron
- D. Copper
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Log in to view solution →- A. Calcium
- B. Potassium
- C. Iron
- D. Copper
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Log in to view solution →- A. Tyrosine
- B. Lysine
- C. Serine
- D. Alanine
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Log in to view solution →- A. Cetyltrimethyl ammonium bromide
- B. Sodium dodecylbenzene sulphonate
- C. Sodium lauryl sulphate
- D. Sodium stearate
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Log in to view solution →- A. 1 g of O2 (g)
- B. 1 g of Li(s)
- C. 1 g of Ag(s)
- D. 1 g of Mg(s)
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Log in to view solution →- A. (c), (iii)
- B. (d), (iv)
- C. (a), (i)
- D. (b), (ii)
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Log in to view solution →- A. Thin layer chromatography
- B. Column chromatography
- C. Adsorption chromatography
- D. Partition chromatography
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Log in to view solution →- A. 15 bar
- B. 18 bar
- C. 9 bar
- D. 12 bar
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Log in to view solution →- A. 71, 71 and 104
- B. 175, 104 and 71
- C. 71, 104 and 71
- D. 104, 71 and 71
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Log in to view solution →- A. 500 s
- B. 1000 s
- C. 100 s
- D. 200 s
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Log in to view solution →- A. C2
- B. O2
- C. He2
- D. Li2
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Log in to view solution →- A. ∆rH < 0 and ∆rS > 0
- B. ∆rH < 0 and ∆rS < 0
- C. ∆rH > 0 and ∆rS > 0
- D. ∆rH > 0 and ∆rS < 0
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Log in to view solution →- A. 1×10−13 M
- B. 1×108 M
- C. 2×10−13 M
- D. 2×10−8 M
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Log in to view solution →- A. H2S gas
- B. SO2 gas
- C. Hydrogen gas
- D. Oxygen gas
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Log in to view solution →- A. The carboxyhaemoglobin is less stable than oxyhaemoglobin.
- B. It is produced due to incomplete combustion.
- C. It forms carboxyhaemoglobin.
- D. It reduces oxygen carrying ability of blood.
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Log in to view solution →- A. 3
- B. 4
- C. 1
- D. 2
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Log in to view solution →- A. (b), (c), (d)
- B. (a), (b), (d)
- C. (a), (b), (c)
- D. (a), (c), (d)
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Log in to view solution →- A. -4 to 14
- B. 0 to -4
- C. 14 to 14
- D. 0 to 14
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Log in to view solution →- A. n-Heptane
- B. n-Butane
- C. n-Hexane
- D. 2,3-Dimethylbutane
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Log in to view solution →- A. α-D-Glucose + β-D-Fructose
- B. α-D-Fructose + β-D-Fructose
- C. β-D-Glucose + α-D-Fructose
- D. α-D-Glucose + β-D-Glucose
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Log in to view solution →- A. Interstitial compounds are those that are formed when small atoms like H, C or N are trapped inside the crystal lattices of metals.
- B. The oxidation states of chromium in CrO4^2- and Cr2O7^2- are not the same.
- C. Cr2+ (d4) is a stronger reducing agent than Fe2+ (d6) in water.
- D. The transition metals and their compounds are known for their catalytic activity due to their ability to adopt multiple oxidation states and to form complexes.
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Log in to view solution →- A. Only MgCl2
- B. NaCl, MgCl2 and CaCl2
- C. Both MgCl2 and CaCl2
- D. Only NaCl
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Log in to view solution →- A. (b) and (c) only
- B. (c) and (d) only
- C. (a), (b) and (c) only
- D. (a) and (c) only
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Log in to view solution →- A. threshold energy
- B. collision frequency
- C. activation energy
- D. heat of reaction
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Log in to view solution →- A. 5.92 BM
- B. 2.84 BM
- C. 3.87 BM
- D. 4.90 BM
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Log in to view solution →- A. (iii)(iv)(ii)(i)
- B. (i)(iii)(ii)(iv)
- C. (iii)(i)(ii)(iv)
- D. (iii)(ii)(i)(iv)
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Log in to view solution →- A. Acetone + Chloroform
- B. Chloroethane + Bromoethane
- C. Ethanol + Acetone
- D. Benzene + Toluene
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Log in to view solution →- A. 0.40 K
- B. 0.60 K
- C. 0.20 K
- D. 0.80 K
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Log in to view solution →- A. H2S2O8, peroxodisulphuric acid
- B. H2S2O7, pyrosulphuric acid
- C. H2SO3, sulphurous acid
- D. H2SO4, sulphuric acid
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Log in to view solution →- A. Vapour phase refining is carried out for Nickel by Van Arkel method.
- B. Pig iron can be moulded into a variety of shapes.
- C. Wrought iron is impure iron with 4% carbon.
- D. Blister copper has blistered appearance due to evolution of CO2.
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Log in to view solution →- A. Vapour phase refining is carried out for Nickel by Van Arkel method.
- B. Pig iron can be moulded into a variety of shapes.
- C. Wrought iron is impure iron with 4% carbon.
- D. Blister copper has blistered appearance due to evolution of CO2.
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Log in to view solution →- A. polybutadiene
- B. poly (Butadiene-acrylonitrile)
- C. cis-1,4-polyisoprene
- D. poly (Butadiene-styrene)
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Log in to view solution →- A. polybutadiene
- B. poly (Butadiene-acrylonitrile)
- C. cis-1,4-polyisoprene
- D. poly (Butadiene-styrene)
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Log in to view solution →- A. (sqrt(3)/4) * 288 pm
- B. (sqrt(2)/4) * 288 pm
- C. (sqrt(3)/4) * 288 pm
- D. (sqrt(2)/4) * 288 pm
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Log in to view solution →- A. Nitrogen trifluoride, beryllium difluoride, water, 1,3-dichlorobenzene
- B. Boron trifluoride, beryllium difluoride, carbon dioxide, 1,4-dichlorobenzene
- C. Ammonia, beryllium difluoride, water, 1,4-dichlorobenzene
- D. Boron trifluoride, hydrogen fluoride, carbon dioxide, 1,3-dichlorobenzene
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