- A. (iii) (iv) (i) (ii)
- B. (iii) (ii) (i) (iv)
- C. (iii) (i) (ii) (iv)
- D. (ii) (iv) (i) (iii)
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Log in to view solution →- A. Pteridophytes
- B. Gymnosperms
- C. Liverworts
- D. Mosses
Correct answer & explanation hidden
Log in to view solution →- A. Before entry of sperm into ovum
- B. Simultaneously with first cleavage
- C. After entry of sperm but before fertilization
- D. After fertilization
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Log in to view solution →- A. Methanol at room temperature
- B. Chilled chloroform
- C. Isopropanol
- D. Chilled ethanol
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Log in to view solution →- A. Proliferation of fibrous tissues and damage of the alveolar walls
- B. Reduction in the secretion of surfactants by pneumocytes
- C. Benign growth on mucous lining of nasal cavity
- D. Inflammation of bronchi and bronchioles
Correct answer & explanation hidden
Log in to view solution →- A. to assess threat posed to native species by invasive weed species
- B. for immediate steps to discontinue use of CFCs that were damaging the ozone layer
- C. to reduce CO2 emissions and global warming
- D. for conservation of biodiversity and sustainable utilization of its benefits
Correct answer & explanation hidden
Log in to view solution →- A. (1) (iii) (iv) (i) (ii)
- B. (2) (iv) (iii) (i) (ii)
- C. (3) (iii) (i) (iv) (ii)
- D. (4) (iii) (ii) (i) (iv)
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Log in to view solution →- A. Activating cyclic AMP located on the cell membrane
- B. Using aquaporin channels as second messenger
- C. Changing the permeability of the cell membrane
- D. Binding to DNA and forming a gene-hormone complex
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Log in to view solution →- A. DNA polymorphism
- B. Novel DNA sequences
- C. Genes expressed as RNA
- D. Polypeptide expression
Correct answer & explanation hidden
Log in to view solution →- A. Gibberellin and Abscicic acid
- B. Cytokinin and Abscisic acid
- C. Auxin and Ethylene
- D. Gibberellin and Cytokinin
Correct answer & explanation hidden
Log in to view solution →- A. Gibberellin and Abscisic acid
- B. Cytokinin and Abscisic acid
- C. Auxin and Ethylene
- D. Gibberellin and Cytokinin
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Log in to view solution →- A. Pyramid of biomass in a forest
- B. Pyramid of biomass in a sea
- C. Pyramid of numbers in grassland
- D. Pyramid of energy
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Log in to view solution →- A. Pyramid of biomass in a forest
- B. Pyramid of biomass in a sea
- C. Pyramid of numbers in grassland
- D. Pyramid of energy
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Log in to view solution →- A. Lysosomes and Vacuoles
- B. Nuclear envelope and Mitochondria
- C. Mitochodria and Lysosomes
- D. Chloroplast and Vacuoles
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Log in to view solution →- A. Lysosomes and Vacuoles
- B. Nuclear envelope and Mitochondria
- C. Mitochondria and Lysosomes
- D. Chloroplast and Vacuoles
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Log in to view solution →- A. Seminiferous tubules -> Vasa efferentia -> Epididymis -> Inguinal canal -> Urethra
- B. Testis -> Epididymis -> Vasa efferentia -> Vas deferens -> Ejaculatory duct -> Inguinal canal -> Urethra -> Urethral meatus
- C. Testis -> Epididymis -> Vasa efferentia -> Rete testis -> Inguinal canal -> Urethra
- D. Seminiferous tubules -> Rete testis -> Vasa efferentia -> Epididymis -> Vas deferens -> Ejaculatory duct -> Urethra -> Urethral meatus
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Log in to view solution →- A. (a)-(v), (b)-(iv), (c)-(i), (d)-(iii)
- B. (a)-(ii), (b)-(iv), (c)-(i), (d)-(iii)
- C. (a)-(v), (b)-(i), (c)-(ii), (d)-(iii)
- D. (a)-(ii), (b)-(iv), (c)-(iii), (d)-(i)
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Log in to view solution →- A. Hilum
- B. Tegmen
- C. Chalaza
- D. Perisperm
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Log in to view solution →- A. it has very hard seed coat
- B. Its seed contain inhibitors that prevent germination
- C. its embryo is immature
- D. it has obligate association with mycorrhizae
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Log in to view solution →- A. suspend the cell cycle
- B. terminate the cell cycle
- C. exit the cell cycle
- D. enter the cell cycle
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Log in to view solution →- A. (a)-(iii), (b)-(iv), (c)-(i), (d)-(ii)
- B. (a)-(iii), (b)-(ii), (c)-(i), (d)-(iv)
- C. (a)-(iii), (b)-(i), (c)-(ii), (d)-(iv)
- D. (a)-(ii), (b)-(iv), (c)-(i), (d)-(iii)
Correct answer & explanation hidden
Log in to view solution →- A. Shrinkage of air spaces in spongy mesophyll
- B. Tyloses in vessels
- C. Closure of stomata
- D. Flaccidity of bulliform cells
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Log in to view solution →- A. Shrinkage of air spaces in spongy mesophyll
- B. Tyloses in vessels
- C. Closure of stomata
- D. Flaccidity of bulliform cells
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Log in to view solution →- A. Both (A) and (B) are false
- B. (A) is false but (B) is true
- C. Both (A) and (B) are true
- D. (A) is true but (B) is false
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Log in to view solution →- A. 0.07
- B. 0.09
- C. 0.9
- D. 0.7
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Log in to view solution →- A. Infective constituent in viruses is the protein coat
- B. Prions consist of abnormally folded proteins
- C. Viroids lack a protein coat
- D. Viruses are obligate parasites
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Log in to view solution →- A. Companion cells only
- B. Both sieve tubes and companion cells
- C. Albuminous cells and sieve cells
- D. Sieve tubes only
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Log in to view solution →- A. Insertion of A and G at 4th and 5th positions respectively
- B. Deletion of GGU from 7th, 8th and 9th positions
- C. Insertion of G at 5th positions
- D. Deletion of G from 5th positions
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Log in to view solution →- A. Oxyntic Cells
- B. Duodenal Cells
- C. Chief Cells
- D. Goblet Cells
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Log in to view solution →- A. Shoot apex
- B. Leaves
- C. Lateral buds
- D. Pulvinus
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Log in to view solution →- A. 100 beats per minute
- B. 125 beats per minute
- C. 50 beats per minute
- D. 75 beats per minute
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Log in to view solution →- A. 100 beats per minute
- B. 125 beats per minute
- C. 50 beats per minute
- D. 75 beats per minute
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Log in to view solution →- A. 2200 mL
- B. 2700 mL
- C. 1500 mL
- D. 1700 mL
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Log in to view solution →- A. 2200 mL
- B. 2700 mL
- C. 1500 mL
- D. 1700 mL
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Log in to view solution →- A. Parietal
- B. Free central
- C. Basal
- D. Axile
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Log in to view solution →- A. Parietal
- B. Free central
- C. Basal
- D. Axile
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Log in to view solution →- A. Dump the waste within rocks under deep ocean
- B. Bury the waste within rocks deep below the Earth’s surface
- C. Shoot the waste into space
- D. Bury the waste under Antarctic ice-cover
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Log in to view solution →- A. Dump the waste within rocks under deep ocean
- B. Bury the waste within rocks deep below the Earth’s surface
- C. Shoot the waste into space
- D. Bury the waste under Antarctic ice-cover
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Log in to view solution →- A. Conidia are produced exogenously and ascospores endogenously.
- B. Yeasts have filamentous bodies with long thread-like hyphae.
- C. Morels and truffles are edible delicacies.
- D. Claviceps is a source of many alkaloids and LSD.
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Log in to view solution →- A. Industrial oven
- B. Bioreactor
- C. BOD incubator
- D. Sludge digester
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Log in to view solution →- A. (a)-(iii), (b)-(iv), (c)-(v), (d)-(i)
- B. (a)-(ii), (b)-(i), (c)-(iii), (d)-(v)
- C. (a)-(ii), (b)-(iv), (c)-(v), (d)-(iii)
- D. (a)-(ii), (b)-(iv), (c)-(iii), (d)-(v)
Correct answer & explanation hidden
Log in to view solution →- A. Inbreeding selects harmful recessive genes that reduce fertility and productivity.
- B. Inbreeding helps in accumulation of superior genes and elimination of undesirable genes.
- C. Inbreeding increases homozygosity.
- D. Inbreeding is essential to evolve purelines in any animal.
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Log in to view solution →- A. Inflammatory immune response
- B. Cell-mediated immune response
- C. Auto-immune response
- D. Humoral immune response
Correct answer & explanation hidden
Log in to view solution →- A. Activity of cambium depends upon variation in climate.
- B. Annual rings are not prominent in trees of temperate region.
- C. Annual ring is a combination of spring wood and autumn wood produced in a year.
- D. Differential activity of cambium causes light and dark bands of tissue-early and late wood respectively
Correct answer & explanation hidden
Log in to view solution →- A. It is drought tolerant, developed using Agrobacterium vector.
- B. It has yellow grains, because of a gene introduced from a primitive variety of rice.
- C. It is Vitamin A enriched, with a gene from daffodil.
- D. It is pest resistant, with a gene from Bacillus thuringiensis.
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Log in to view solution →- A. It is drought tolerant, developed using Agrobacterium vector.
- B. It has yellow grains, because of a gene introduced from a primitive variety of rice.
- C. It is Vitamin A enriched, with a gene from daffodil.
- D. It is pest resistant, with a gene from Bacillus thuringiensis.
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Log in to view solution →- A. Edward syndrome
- B. Down’s syndrome
- C. Turner’s syndrome
- D. Klinefelter’s syndrome
Correct answer & explanation hidden
Log in to view solution →- A. Edward syndrome
- B. Down’s syndrome
- C. Turner’s syndrome
- D. Klinefelter’s syndrome
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Log in to view solution →- A. Central cell develop into endosperm
- B. Ovules develop into embryo sac
- C. Ovary develops into fruit
- D. Zygote develops into embryo
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Log in to view solution →- A. Economic exploitation
- B. Alien species invasion
- C. Habitat loss and fragmentation
- D. Drought and floods
Correct answer & explanation hidden
Log in to view solution →- A. CuT, Pills, Emergency contraceptives
- B. Pills, Emergency contraceptives, Barrier methods
- C. Lactational amenorrhea, Pills, Emergency contraceptives
- D. Barrier method, Lactational amenorrhea, Pills
Correct answer & explanation hidden
Log in to view solution →- A. Arthropoda, Mollusca and chordata
- B. Annelida, Mollusca and chordata
- C. Annelida, Arthropoda and chordata
- D. Annelida, Arthropoda and Mollusca
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Log in to view solution →- A. Secretion of erythropoietin by Juxtaglomerular complex.
- B. Hydrostatic pressure during glomerular filtration.
- C. Low levels of antidiuretic hormone.
- D. Maintaining hyperosmolarity towards inner medullary interstitum in the kidneys
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Log in to view solution →- A. (1) (ii) (iv) (iii) (i)
- B. (2) (iii) (ii) (iv) (i)
- C. (3) (iii) (ii) (i) (iv)
- D. (4) (iii) (iv) (ii) (i)
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Log in to view solution →- A. Water, mineral salts and some organic nitrogen only
- B. Water, mineral salts, some organic nitrogen and hormones
- C. Water only
- D. Water and mineral salts only
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Log in to view solution →- A. Water, mineral salts and some organic nitrogen only
- B. Water, mineral salts, some organic nitrogen and hormones
- C. Water only
- D. Water and mineral salts only
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Log in to view solution →- A. Downward
- B. Bi-directional
- C. Non-multidirectional
- D. Upward
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Log in to view solution →- A. Downward
- B. Bi-directional
- C. Non-multidirectional
- D. Upward
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Log in to view solution →- A. S -> G1 -> G2 -> M
- B. G1 -> S -> G2 -> M
- C. M -> G1 -> G2 -> S
- D. G1 -> G2 -> S -> M
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Log in to view solution →- A. S -> G1 -> G2 -> M
- B. G1 -> S -> G2 -> M
- C. M -> G1 -> G2 -> S
- D. G1 -> G2 -> S -> M
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Log in to view solution →- A. q-arm and p-arm respectively
- B. m-arm and n-arm respectively
- C. s-arm and l-arm respectively
- D. p-arm and q-arm respectively
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Log in to view solution →- A. Anabaena
- B. Lactobacillus
- C. Trichoderma
- D. Chlorella
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Log in to view solution →- A. GLUT III
- B. GLUT IV
- C. GLUT I
- D. GLUT II
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Log in to view solution →- A. Guanine and cytosine
- B. Cytosine and thymine
- C. Adenine and thymine
- D. Adenine and guanine
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Log in to view solution →- A. glycosylation of morphine
- B. nitration of morphine
- C. methylation of morphine
- D. acetylation of morphine
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Log in to view solution →- A. Each rib is a flat thin bone and all the ribs are connected dorsally to the thoracic vertebrae and ventrally to the sternum
- B. There are seven pairs of vertebrosternal, three pairs of vertebrochondral and two pairs of vertebral ribs
- C. 8th, 9th and 10th pairs of ribs articulate directly with the sternum
- D. 11th and 12th pairs of ribs are connected to the sternum with the help of hyaline cartilage.
Correct answer & explanation hidden
Log in to view solution →- A. 0.16(AA); 0.48 (Aa); 0.36(aa)
- B. 0.16 (AA); 0.36(Aa); 0.48(aa)
- C. 0.36 (AA); 0.48 (Aa); 0.16 (aa)
- D. 0.16 (AA); 0.24 (Aa); 0.36 (aa)
Correct answer & explanation hidden
Log in to view solution →- A. Inner membrane is convoluted with infoldings
- B. Mitochondrial matrix contains single circular DNA molecule and ribosomes
- C. Outer membrane is permeable to monomers of carbohydrates, fats and proteins
- D. Enzymes of electron transport are embedded in outer membrane.
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Log in to view solution →- A. small and directional
- B. small and directionless
- C. random and directional
- D. random and directionless
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Log in to view solution →- A. small and directional
- B. small and directionless
- C. random and directional
- D. random and directionless
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Log in to view solution →- A. The enzyme cuts the sugar-phosphate backbone at specific sites on each strand
- B. The enzyme recognizes a specific palindromic nucleotide sequence in the DNA
- C. The enzyme cuts DNA molecule at identified position within the DNA
- D. The enzyme binds DNA at specific sites and cuts only one of the two strands
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Log in to view solution →- A. Corpus callosum
- B. Medulla oblongata
- C. Cerebrum
- D. Hypothalamus
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Log in to view solution →- A. (c) and (d) are correct
- B. (a) and (d) are correct
- C. (a) and (b) are correct
- D. (b) and (c) are correct
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Log in to view solution →- A. Alkaline pH of gut
- B. Acidic pH of stomach
- C. Body temperature
- D. Moist surface of midgut
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Log in to view solution →- A. Gothenburg Protocol
- B. Geneva Protocol
- C. Montreal Protocol
- D. Kyoto Protocol
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Log in to view solution →- A. Genital herpes
- B. Chlamydiasis
- C. Gonorrhoea
- D. Genital warts
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Log in to view solution →- A. Nitrification
- B. Denitrification
- C. Nitrogen fixation
- D. Chemoautotrophic fixation
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Log in to view solution →- A. Ratio of F2 is 1/4 (Red) : 2/4 (Pink) : 1/4 (White)
- B. Law of Segregation does not apply in this experiment
- C. This experiment does not follow the Principle of Dominance
- D. Pink colour in F1 is due to incomplete dominance
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Log in to view solution →- A. Disruptive Selection
- B. Cyclical Selection
- C. Directional Selection
- D. Stabilizing Selection
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Log in to view solution →- A. A²/2ω
- B. zero
- C. Aω/2
- D. Aω
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Log in to view solution →- A. 2 : 3
- B. 3 : 4
- C. 2 : 1
- D. 1 : 2
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Log in to view solution →- A. remain constant
- B. change according to the smallest force
- C. increase
- D. decrease
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Log in to view solution →- A. 4 : 1
- B. 1 : 4
- C. 2 : 1
- D. 1 : 2
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Log in to view solution →- A. 4 : 1
- B. 1 : 4
- C. 2 : 1
- D. 1 : 2
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Log in to view solution →- A. 4/9
- B. 5/9
- C. 1/9
- D. 8/9
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Log in to view solution →- A. 4/9
- B. 5/9
- C. 1/9
- D. 8/9
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Log in to view solution →- A. 60º west
- B. 45º west
- C. 30º west
- D. 0º
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Log in to view solution →- A. V1 = V2 and i1 = i2
- B. V2 > V1 and i1 > i2
- C. V2 > V1 and i1 = i2
- D. V1 = V2 and i1 > i2
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Log in to view solution →- A. 2 × 10^-3 V
- B. 0.02 V
- C. 2 V
- D. 0.2 V
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Log in to view solution →- A. A is located in the northern hemisphere and B is located in the southern hemisphere
- B. A and B are both located in the southern hemisphere
- C. A and B are both located in the northern hemisphere
- D. A is located in the southern hemisphere and B is located in the northern hemisphere
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Log in to view solution →- A. 12.2 × 10^-14 m
- B. 12.2 nm
- C. 12.2 × 10^-13 m
- D. 12.2 × 10^-12 m
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Log in to view solution →- A. sqrt(A0^2 + (A+B)^2)
- B. A + B
- C. A0 + sqrt(A^2 + B^2)
- D. sqrt(A^2 + B^2)
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Log in to view solution →- A. 2 electrons and 4 protons only
- B. 2 protons only
- C. 2 protons and 2 neutrons only
- D. 2 electrons, 2 protons and 2 neutrons
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Log in to view solution →- A. 2 electrons and 4 protons only
- B. 2 protons only
- C. 2 protons and 2 neutrons only
- D. 2 electrons, 2 protons and 2 neutrons
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Log in to view solution →- A. zero as r increases for r < R, increases as r increases for r > R
- B. decreases as r increases for r < R and for r > R
- C. increases as r increases for r < R and for r > R
- D. zero as r increases for r < R, decreases as r increases for r > R
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Log in to view solution →- A. zero as r increases for r < R, increases as r increases for r > R
- B. decreases as r increases for r < R and for r > R
- C. increases as r increases for r < R and for r > R
- D. zero as r increases for r < R, decreases as r increases for r > R
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Log in to view solution →- A. –10%
- B. 10%
- C. (13/3)%
- D. 16%
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Log in to view solution →- A. 25 J
- B. 20 J
- C. 30 J
- D. 5 J
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Log in to view solution →- A. isobaric
- B. isochoric
- C. isothermal
- D. adiabatic
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Log in to view solution →- A. electromagnet
- B. electric heater
- C. induction furnace
- D. magnetic braking in train
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Log in to view solution →- A. W m K–1
- B. W m–1 K–1
- C. J m K–1
- D. J m–1 K–1
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Log in to view solution →- A. 250 N
- B. 100 N
- C. 150 N
- D. 200 N
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Log in to view solution →- A. λ / (πε0R)
- B. λ / (2πε0R)
- C. zero
- D. λ / (2πε0R^2)
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Log in to view solution →- A. the mass is at the lowest point
- B. inclined at an angle of 60° from vertical
- C. the mass is at the highest point
- D. the wire is horizontal
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Log in to view solution →- A. NAND
- B. NOR
- C. AND
- D. OR
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Log in to view solution →- A. NAND
- B. NOR
- C. AND
- D. OR
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Log in to view solution →- A. 10 rad/s
- B. 10 π rad/s
- C. 10rad/s
- D. 10/2π rad/s
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Log in to view solution →- A. 10 rad/s
- B. 10 pi rad/s
- C. 10/pi rad/s
- D. sqrt(10)/pi rad/s
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Log in to view solution →- A. 2.23 x 10^-6 m^3/s
- B. 6.4 x 10^-6 m^3/s
- C. 12.6 x 10^-6 m^3/s
- D. 8.9 x 10^-6 m^3/s
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Log in to view solution →- A. 3:1
- B. sqrt(3):1
- C. 2:1
- D. 1:2
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Log in to view solution →- A. Plot with linear increase up to R and hyperbolic decrease after R
- B. Plot with jump at R
- C. Plot with constant inside and zero outside
- D. Plot with constant everywhere
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Log in to view solution →- A. 1 cm
- B. 0.5 cm
- C. 100 cm
- D. 10 cm
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Log in to view solution →- A. 1/2 mgR
- B. 3/2 mgR
- C. mgR
- D. 2 mgR
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Log in to view solution →- A. switch
- B. fuse
- C. conductor
- D. inductor
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Log in to view solution →- A. rB : rA
- B. 1 : 1
- C. rA : rB
- D. vA : vB
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Log in to view solution →- A. 60 uA, zero
- B. zero, zero
- C. zero, 60 uA
- D. 60 uA, 60 uA
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Log in to view solution →- A. 60 μA, zero
- B. zero, zero
- C. zero, 60 μA
- D. 60 μA, 60 μA
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Log in to view solution →- A. y(t) = 3 cos(3*pi/2 * t)
- B. y(t) = 3 cos(pi/2 * t)
- C. y(t) = -3 cos(2*pi * t)
- D. y(t) = 4 sin(pi/2 * t)
Correct answer & explanation hidden
Log in to view solution →- A. y(t) = 3 cos(π/2 t)
- B. y(t) = 3 cos(π/2 t)
- C. y(t) = -3 cos 2πt
- D. y(t) = 4 sin(π/2 t)
Correct answer & explanation hidden
Log in to view solution →- A. Holes are the majority carriers and pentavalent atoms are the dopants
- B. Electrons are the majority carriers and pentavalent atoms are the dopants
- C. Electrons are the majority carriers and trivalent atoms are the dopants
- D. Holes are the majority carriers and trivalent atoms are the dopants
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Log in to view solution →- A. 1 : 2
- B. 2 : 1
- C. 4 : 9
- D. 9 : 4
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Log in to view solution →- A. decrease in its pressure
- B. decrease in intermolecular distance
- C. increase in its mass
- D. increase in its kinetic energy
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Log in to view solution →- A. 0.05°
- B. 0.1°
- C. 0.266°
- D. 0.15°
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Log in to view solution →- A. 3.4 eV, – 6.8 eV
- B. 3.4 eV, 3.4 eV
- C. – 3.4 eV, – 3.4 eV
- D. – 3.4 eV, – 6.8 eV
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Log in to view solution →- A. green
- B. violet
- C. red
- D. blue
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Log in to view solution →- A. equal to angle of incidence
- B. 90°
- C. 180°
- D. 0°
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Log in to view solution →- A. Equal to angle of incidence
- B. 90°
- C. 180°
- D. 0°
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Log in to view solution →- A. 2 J
- B. 1 J
- C. 3 J
- D. 30 kJ
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Log in to view solution →- A. 2 J
- B. 1 J
- C. 3 J
- D. 30 kJ
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Log in to view solution →- A. 1/2 Mgl
- B. 1/2 MgL
- C. Mgl
- D. MgL
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Log in to view solution →- A. 1/2 Mgl
- B. 1/2 MgL
- C. Mgl
- D. MgL
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Log in to view solution →- A. 12 × 10^-4 Nm
- B. 2 × 10^6 Nm
- C. 2 × 10^-6 Nm
- D. 2 × 10^-3 Nm
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Log in to view solution →- A. 16F/9
- B. 4F/3
- C. F
- D. 9F/16
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Log in to view solution →- A. An observer can see a rainbow when his front is towards the sun
- B. Rainbow is a combined effect of dispersion, refraction and reflection of sunlight
- C. When the light rays undergo two internal reflections in a water drop, a secondary rainbow is formed
- D. The order of colours is reversed in the secondary rainbow
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Log in to view solution →- A. 88 cm
- B. 68 cm
- C. 6.8 cm
- D. 113.9 cm
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Log in to view solution →- A. Sublimation of solid to gas
- B. 2H(g) → H2(g)
- C. Evaporation of water
- D. Expansion of a gas at temperature
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Log in to view solution →- A. -d[N2]/dt = 1/2 d[NH3]/dt
- B. 2/3 d[H2]/dt = 3/2 d[NH3]/dt
- C. -1/3 d[H2]/dt = -1/2 d[NH3]/dt
- D. -d[N2]/dt = 3/2 d[NH3]/dt
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Log in to view solution →- A. C2
- B. Be2
- C. O2
- D. N2
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Log in to view solution →- A. GeX4(X = F, Cl, Br, I) is more stable than GeX2
- B. SnF4 is ionic in nature
- C. PbF4 is covalent in nature
- D. SiCl4 is easily hydrolysed
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Log in to view solution →- A. GeX4(X = F, Cl, Br, I) is more stable than GeX2
- B. SnF4 is ionic in nature
- C. PbF4 is covalent in nature
- D. SiCl4 is easily hydrolysed
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Log in to view solution →- A. 25 J
- B. 30 J
- C. -30 J
- D. 5 kJ
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Log in to view solution →- A. 25 J
- B. 30 J
- C. -30 J
- D. 5 kJ
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Log in to view solution →- A. Dimethyl ether (CH3-O-CH3)
- B. Phenol (Ph-OH)
- C. Water (H-O-H)
- D. Methanol (H3C-O-H)
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Log in to view solution →- A. Mg(OH)2
- B. Be(OH)2
- C. Sr(OH)2
- D. Ca(OH)2
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Log in to view solution →- A. nylon-6
- B. Buna-S
- C. nylon-6, 6
- D. nylon 2-nylon 6
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Log in to view solution →- A. (1) (iii) (iv) (ii) (i)
- B. (2) (iv) (iii) (ii) (i)
- C. (3) (i) (ii) (iii) (iv)
- D. (4) (ii) (iv) (i) (iii)
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Log in to view solution →- A. 11 σ bonds and 2 π bonds
- B. 13 σ bonds and no π bond
- C. 10 σ bonds and 3 π bonds
- D. 8 σ bonds and 5 π bonds
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Log in to view solution →- A. Ca
- B. Sr
- C. Be
- D. Mg
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Log in to view solution →- A. Axial P-Cl bonds are longer than equatorial P-Cl bonds
- B. PCl5 molecule is non-reactive
- C. Three equatorial P-Cl bonds make an angle of 120º with each other
- D. Two axial P-Cl bonds make an angle of 180º with each other
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Log in to view solution →- A. t = 4.606/k
- B. t = 2.303/k
- C. t = 0.693/k
- D. t = 6.909/k
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Log in to view solution →- A. t = 4.606/k
- B. t = 2.303/k
- C. t = 0.693/k
- D. t = 6.909/k
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Log in to view solution →- A. Zn / HCl
- B. Hg2+ / H+, H2O
- C. Na / liquid NH3
- D. H2, Pd/C, quinoline
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Log in to view solution →- A. Zn / HCl
- B. Hg2+ / H+, H2O
- C. Na / liquid NH3
- D. H2, Pd/C, quinoline
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Log in to view solution →- A. The π-bonding involves overlap of p-orbitals of oxygen with p-orbitals of manganese
- B. The π-bonding involves overlap of d-orbitals of oxygen with d-orbitals of manganese
- C. The π-bonding involves overlap of p-orbitals of oxygen with d-orbitals of manganese
- D. There is no π-bonding
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Log in to view solution →- A. The π-bonding involves overlap of p-orbitals of oxygen with p-orbitals of manganese
- B. The π-bonding involves overlap of d-orbitals of oxygen with d-orbitals of manganese
- C. The π-bonding involves overlap of p-orbitals of oxygen with d-orbitals of manganese
- D. There is no π-bonding
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Log in to view solution →- A. 1.0 × 10^10
- B. 1.0 × 10^30
- C. 1.0 × 10^2
- D. 1.0 × 10^5
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Log in to view solution →- A. 0.125 × 10^–15
- B. 0.5 × 10^–10
- C. 0.5 × 10^–15
- D. 0.25 × 10^–10
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Log in to view solution →- A. Δmix H = 0 at constant T and P
- B. Δmix G = 0 at constant T and P
- C. Δmix S = 0 at constant T and P
- D. Δmix V ≠ 0 at constant T and P
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Log in to view solution →- A. Z < 1 and attractive forces are dominant
- B. Z < 1 and repulsive forces are dominant
- C. Z > 1 and attractive forces are dominant
- D. Z > 1 and repulsive forces are dominant
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Log in to view solution →- A. (CH3)3N > (CH3)2NH > CH3NH2
- B. CH3NH2 > (CH3)2NH > (CH3)3N
- C. (CH3)2NH > CH3NH2 > (CH3)3N
- D. (CH3)3N > CH3NH2 > (CH3)2NH
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Log in to view solution →- A. Li < B < Be < C < N < O < F < Ne
- B. Li < Be < B < C < O < N < F < Ne
- C. Li < Be < B < C < N < O < F < Ne
- D. Li < B < Be < C < O < N < F < Ne
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Log in to view solution →- A. 50 mL of 2 M AgNO3 + 50 mL of 1.5 M KI
- B. 50 mL of 0.1 M AgNO3 + 50 mL of 0.1 M KI
- C. 50 mL of 1 M AgNO3 + 50 mL of 1.5 M KI
- D. 50 mL of 1 M AgNO3 + 50 mL of 2 M KI
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Log in to view solution →- A. 46.32 kJ mol–1
- B. 23.16 kJ mol–1
- C. –46.32 kJ mol–1
- D. –23.16 kJ mol–1
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Log in to view solution →- A. 46.32 kJ mol-1
- B. 23.16 kJ mol-1
- C. -46.32 kJ mol-1
- D. -23.16 kJ mol-1
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Log in to view solution →- A. H2Po < H2Te < H2Se < H2S < H2O
- B. H2Se < H2Te < H2Po < H2O < H2S
- C. H2S < H2O < H2Se < H2Te < H2Po
- D. H2O < H2S < H2Se < H2Te < H2Po
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Log in to view solution →- A. 30
- B. 40
- C. 10
- D. 20
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Log in to view solution →- A. Paschen series
- B. Brackett series
- C. Lyman series
- D. Balmer series
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Log in to view solution →- A. C3A4
- B. C4A3
- C. C2A3
- D. C3A2
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Log in to view solution →- A. alanine
- B. lysine
- C. valine
- D. leucine
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Log in to view solution →- A. H3C – C(Cl)(CH3) – CH2 – CH3
- B. H3C – CH(Cl) – CH(CH3)2
- C. Cl – CH2 – CH2 – CH(CH3)2
- D. H3C – CH2 – CH(CH2Cl) – CH3
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Log in to view solution →- A. [Sn(OH)6]2-
- B. [SiCl6]2-
- C. [SiF6]2-
- D. [GeCl6]2-
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Log in to view solution →- A. (1) (a)-(ii), (b)-(iii), (c)-(i), (d)-(iv)
- B. (2) (a)-(iii), (b)-(iv), (c)-(i), (d)-(ii)
- C. (3) (a)-(i), (b)-(ii), (c)-(iii), (d)-(iv)
- D. (4) (a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)
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Log in to view solution →- A. (1) (a), (c) and (d)
- B. (2) (a) and (d) only
- C. (3) (a) and (b) only
- D. (4) (a), (b) and (c)
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Log in to view solution →- A. Acetone + Carbon disulphide
- B. Heptane + Octane
- C. Water + Nitric acid
- D. Ethanol + Water
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Log in to view solution →- A. t2g3 eg3
- B. t2g4 eg2
- C. t2g2 eg4
- D. t2g6 eg0
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Log in to view solution →- A. OH- and F-, respectively
- B. H3O+ and H2F+, respectively
- C. OH- and H2F+, respectively
- D. H3O+ and F-, respectively
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Log in to view solution →- A. 100 mL of 0.1 M HCl + 200 mL of 0.1 M NH4OH
- B. 100 mL of 0.1 M HCl + 100 mL of 0.1 M NH4OH
- C. 50 mL of 0.1 M NaOH + 25 mL of 0.1 M CH3COOH
- D. 100 mL of 0.1 M CH3COOH + 100 mL of 0.1 M NaOH
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Log in to view solution →- A. 6p > 5f > 4d > 5p
- B. 5f > 6p > 4d > 5p
- C. 5f > 6p > 5p > 4d
- D. 6p > 5f > 5p > 4d
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Log in to view solution →- A. Ion-exchange method
- B. Synthetic resins method
- C. Calgon’s method
- D. clark’s method
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Log in to view solution →- A. Fe3O4
- B. CuCO3·Cu(OH)2
- C. CuFeS2
- D. Cu(OH)2
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