- A. Sex ratio
- B. Natality
- C. Mortality
- D. Species interaction
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Log in to view solution →- A. Log phase
- B. Lag phase
- C. Senescence
- D. Dormancy
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Log in to view solution →- A. Fibrous roots
- B. Primary roots
- C. Prop roots
- D. Lateral roots
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Log in to view solution →- A. (a) Typhoid – (i) Wuchereria; (b) Pneumonia – (iii) Salmonella; (c) Filariasis – (ii) Plasmodium; (d) Malaria – (iv) Haemophilus
- B. (a) Typhoid – (iii) Salmonella; (b) Pneumonia – (iv) Haemophilus; (c) Filariasis – (i) Wuchereria; (d) Malaria – (ii) Plasmodium
- C. (a) Typhoid – (ii) Plasmodium; (b) Pneumonia – (i) Wuchereria; (c) Filariasis – (iii) Salmonella; (d) Malaria – (iv) Haemophilus
- D. (a) Typhoid – (iv) Haemophilus; (b) Pneumonia – (i) Wuchereria; (c) Filariasis – (ii) Plasmodium; (d) Malaria – (iii) Salmonella
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Log in to view solution →- A. ZIFT and IUT
- B. GIFT and ZIFT
- C. ICSI and ZIFT
- D. GIFT and ICSI
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Log in to view solution →- A. The gene I has three alleles.
- B. A person will have only two of the three alleles.
- C. When Iᵉ and Iᵃ are present together, they express same type of sugar.
- D. Allele 'i' does not produce any sugar.
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Log in to view solution →- A. Ligases - Join the two DNA molecules
- B. Polymerases - Break the DNA into fragments
- C. Nucleases - Separate the two strands of DNA
- D. Exonucleases - Make cuts at specific positions within DNA
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Log in to view solution →- A. Haemophilia – Y linked
- B. Phenylketonuria – Autosomal dominant trait
- C. Sickle cell anaemia – Autosomal recessive trait, chromosome-11
- D. Thalassemia – X linked
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Log in to view solution →- A. (a) Gregarious, polyphagous pest – (i) Asterias; (b) Adult with radial symmetry and larva with bilateral symmetry – (iii) Ctenoplana; (c) Book lungs – (ii) Scorpion; (d) Bioluminescence – (iv) Locusta
- B. (a) Gregarious, polyphagous pest – (iv) Locusta; (b) Adult with radial symmetry and larva with bilateral symmetry – (i) Asterias; (c) Book lungs – (ii) Scorpion; (d) Bioluminescence – (iii) Ctenoplana
- C. (a) Gregarious, polyphagous pest – (iii) Ctenoplana; (b) Adult with radial symmetry and larva with bilateral symmetry – (ii) Scorpion; (c) Book lungs – (i) Asterias; (d) Bioluminescence – (iv) Locusta
- D. (a) Gregarious, polyphagous pest – (ii) Scorpion; (b) Adult with radial symmetry and larva with bilateral symmetry – (i) Asterias; (c) Book lungs – (iii) Ctenoplana; (d) Bioluminescence – (iv) Locusta
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Log in to view solution →- A. Trophozoites
- B. Sporozoites
- C. Female gametocytes
- D. Male gametocytes
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Log in to view solution →- A. Trophozoites
- B. Sporozoites
- C. Female gametocytes
- D. Male gametocytes
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Log in to view solution →- A. Chitin, cholesterol
- B. Glycerol, trypsin
- C. Cellulose, lecithin
- D. Inulin, insulin
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Log in to view solution →- A. Chitin, cholesterol
- B. Glycerol, trypsin
- C. Cellulose, lecithin
- D. Inulin, insulin
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Log in to view solution →- A. (a) Pollen grains inside the anther
- B. (b) Germinated pollen grain with two male gametes
- C. (c) Seed inside the fruit
- D. (d) Embryo sac inside the ovule
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Log in to view solution →- A. Ammonia alone
- B. Nitrate alone
- C. Ammonia and oxygen
- D. Ammonia and hydrogen
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Log in to view solution →- A. Ammonia alone
- B. Nitrate alone
- C. Ammonia and oxygen
- D. Ammonia and hydrogen
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Log in to view solution →- A. DNA synthesis or replication takes place.
- B. Reorganisation of all cell components takes place.
- C. Cell is metabolically active, grows but does not replicate its DNA.
- D. Nuclear division takes place.
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Log in to view solution →- A. Lining of intestine
- B. Ducts of salivary gland
- C. Proximal convoluted tubule of nephron
- D. Eustachian tube
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Log in to view solution →- A. They are not bound by any membrane
- B. These are involved in ingestion of food particles
- C. They lie free in the cytoplasm
- D. These represent reserve material in cytoplasm
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Log in to view solution →- A. Endoplasmic reticulum
- B. Peroxisomes
- C. Golgi bodies
- D. Polysomes
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Log in to view solution →- A. Acetocarmine in bright blue light
- B. Ethidium bromide in UV radiation
- C. Acetocarmine in UV radiation
- D. Ethidium bromide in infrared radiation
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Log in to view solution →- A. Binding of oxygen with haemoglobin is mainly related to partial pressure of O2
- B. Partial pressure of CO2 can interfere with O2 binding with haemoglobin
- C. Higher H+ concentration in alveoli favours the formation of oxyhaemoglobin
- D. Low pCO2 in alveoli favours the formation of oxyhaemoglobin
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Log in to view solution →- A. Inferior ovary
- B. Superior ovary
- C. Hypogynous ovary
- D. Half inferior ovary
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Log in to view solution →- A. 5′-GAATTC-3′ 3′-CTTAAG-5′
- B. 5′-GGAACC-3′ 3′-CCTTGG-5′
- C. 5′-CTTAAG-3′ 3′-GAATTC-5′
- D. 5′-GGATCC-3′ 3′-CCTAGG-5′
Correct answer & explanation hidden
Log in to view solution →- A. Each restriction enzyme functions by inspecting the length of a DNA sequence.
- B. They cut the strand of DNA at palindromic sites.
- C. They are useful in genetic engineering.
- D. Sticky ends can be joined by using DNA ligases.
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Log in to view solution →- A. Primary sludge
- B. Floating debris
- C. Effluents of primary treatment
- D. Activated sludge
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Log in to view solution →- A. Contraction of diaphragm
- B. Contraction of external inter-costal muscles
- C. Pulmonary volume decreases
- D. Intra pulmonary pressure increases
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Log in to view solution →- A. the supra-oesophageal ganglia of the cockroach are situated in ventral part of abdomen.
- B. the cockroach does not have nervous system.
- C. the head holds a small proportion of a nervous system while the rest is situated along the ventral part of its body.
- D. the head holds a 1/3rd of a nervous system while the rest is situated along the dorsal part of its body.
Correct answer & explanation hidden
Log in to view solution →- A. the supra-oesophageal ganglia of the cockroach are situated in ventral part of abdomen.
- B. the cockroach does not have nervous system.
- C. the head holds a small proportion of a nervous system while the rest is situated along the ventral part of its body.
- D. the head holds a 1/3rd of a nervous system while the rest is situated along the dorsal part of its body.
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Log in to view solution →- A. In Urochordata notochord extends from head to tail and it is present throughout their life.
- B. In Vertebrata notochord is present during the embryonic period only.
- C. Central nervous system is dorsal and hollow.
- D. Chordata is divided into 3 subphyla: Hemichordata, Tunicata and Cephalochordata.
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Log in to view solution →- A. (d) and (c)
- B. (c) and (a)
- C. (a) and (b)
- D. (b) and (c)
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Log in to view solution →- A. (ii) (iv) (iii) (i)
- B. (iv) (iii) (i) (ii)
- C. (iii) (ii) (iv) (i)
- D. (iii) (iv) (i) (ii)
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Log in to view solution →- A. (ii) (i) (iv) (iii)
- B. (iv) (iii) (ii) (i)
- C. (iii) (iv) (ii) (i)
- D. (iv) (i) (ii) (iii)
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Log in to view solution →- A. Heart wood does not conduct water but gives mechanical support
- B. Sapwood is involved in conduction of water and minerals from root to leaf
- C. Sapwood is the innermost secondary xylem and is lighter in colour
- D. Due to deposition of tannins, resins, oils etc., heart wood is dark in colour
Correct answer & explanation hidden
Log in to view solution →- A. (ii) (iv) (iii) (i)
- B. (iii) (i) (iv) (ii)
- C. (iii) (iv) (i) (ii)
- D. (ii) (iii) (i) (iv)
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Log in to view solution →- A. Prior to ovulation
- B. At the time of copulation
- C. After zygote formation
- D. At the time of fusion of a sperm with an ovum
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Log in to view solution →- A. 1.5 million
- B. 20 million
- C. 50 million
- D. 7 million
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Log in to view solution →- A. Binding of mRNA to ribosome
- B. Recognition of DNA molecule
- C. Aminoacylation of tRNA
- D. Recognition of an anti-codon
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Log in to view solution →- A. Western Ghats of India
- B. Madagascar
- C. Himalayas
- D. Amazon forests
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Log in to view solution →- A. In man insulin is synthesised as a proinsulin
- B. The proinsulin has an extra peptide called C-peptide.
- C. The functional insulin has A and B chains linked together by hydrogen bonds.
- D. Genetically engineered insulin is produced in E. coli.
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Log in to view solution →- A. Monocotyledonous stem
- B. Monocotyledonous root
- C. Dicotyledonous stem
- D. Dicotyledonous root
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Log in to view solution →- A. (ii) (iii) (iv) (i)
- B. (iii) (iv) (i) (ii)
- C. (iv) (ii) (iii) (i)
- D. (i) (iv) (iii) (ii)
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Log in to view solution →- A. (ii) (iii) (iv) (i)
- B. (iii) (iv) (i) (ii)
- C. (iv) (ii) (iii) (i)
- D. (i) (iv) (iii) (ii)
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Log in to view solution →- A. CH4, H2, NH3 and water vapor at 800°C
- B. CH3, H2, NH4 and water vapor at 800°C
- C. CH4, H2, NH3 and water vapor at 600°C
- D. CH3, H2, NH3 and water vapor at 600°C
Correct answer & explanation hidden
Log in to view solution →- A. CH4, H2, NH3 and water vapor at 800°C
- B. CH3, H2, NH4 and water vapor at 800°C
- C. CH4, H2, NH3 and water vapor at 600°C
- D. CH3, H2, NH3 and water vapor at 600°C
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Log in to view solution →- A. Karl Ernst von Baer
- B. Alfred Wallace
- C. Charles Darwin
- D. Oparin
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Log in to view solution →- A. Karl Ernst von Baer
- B. Alfred Wallace
- C. Charles Darwin
- D. Oparin
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Log in to view solution →- A. Transpiration
- B. Root pressure
- C. Imbibition
- D. Plasmolysis
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Log in to view solution →- A. Transpiration
- B. Root pressure
- C. Imbibition
- D. Plasmolysis
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Log in to view solution →- A. Nutritive value
- B. Growth response
- C. Defence action
- D. Effect on reproduction
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Log in to view solution →- A. 2 molecules of 3-C compound
- B. 1 molecule of 3-C compound
- C. 1 molecule of 6-C compound
- D. 1 molecule of 4-C compound and 1 molecule of 2-C compound
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Log in to view solution →- A. Insect pests
- B. Fungal diseases
- C. Plant nematodes
- D. Insect predators
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Log in to view solution →- A. only (a)
- B. (a) and (c)
- C. (b), (c) and (d)
- D. only (d)
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Log in to view solution →- A. When exposed to antigen (living or dead) antibodies are produced in the host’s body. It is called “Active immunity”.
- B. When ready-made antibodies are directly given, it is called “Passive immunity”.
- C. Active immunity is quick and gives full response.
- D. Foetus receives some antibodies from mother, it is an example for passive immunity.
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Log in to view solution →- A. Out crossing
- B. Mutational breeding
- C. Cross breeding
- D. Inbreeding
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Log in to view solution →- A. Ileum opens into small intestine
- B. Serosa is the innermost layer of the alimentary canal
- C. Ileum is a highly coiled part
- D. Vermiform appendix arises from duodenum
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Log in to view solution →- A. (iii) (iv) (ii) (i)
- B. (ii) (i) (iv) (iii)
- C. (i) (ii) (iv) (iii)
- D. (iv) (iii) (ii) (i)
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Log in to view solution →- A. Uremia and Ketonuria
- B. Uremia and Renal Calculi
- C. Ketonuria and Glycosuria
- D. Renal calculi and Hyperglycaemia
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Log in to view solution →- A. Starch and cellulose
- B. Amylopectin and glycogen
- C. Mannitol and algin
- D. Laminarin and cellulose
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Log in to view solution →- A. Gonorrhoea, Syphilis, Genital herpes
- B. Gonorrhoea, Malaria, Genital herpes
- C. AIDS, Malaria, Filaria
- D. Cancer, AIDS, Syphilis
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Log in to view solution →- A. Gonorrhoea, Syphilis, Genital herpes
- B. Gonorrhoea, Malaria, Genital herpes
- C. AIDS, Malaria, Filaria
- D. Cancer, AIDS, Syphilis
Correct answer & explanation hidden
Log in to view solution →- A. (iii) (iv) (i) (ii)
- B. (iv) (iii) (ii) (i)
- C. (i) (ii) (iv) (iii)
- D. (ii) (iv) (iii) (i)
Correct answer & explanation hidden
Log in to view solution →- A. (iii) (iv) (i) (ii)
- B. (iv) (iii) (ii) (i)
- C. (i) (ii) (iv) (iii)
- D. (ii) (iv) (iii) (i)
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Log in to view solution →- A. Laminaria and Sargassum
- B. Gelidium and Gracilaria
- C. Anabaena and Volvox
- D. Chlorella and Spirulina
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Log in to view solution →- A. Laminaria and Sargassum
- B. Gelidium and Gracilaria
- C. Anabaena and Volvox
- D. Chlorella and Spirulina
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Log in to view solution →- A. High concentration of Estrogen
- B. High concentration of Progesterone
- C. Low concentration of LH
- D. Low concentration of FSH
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Log in to view solution →- A. (iv) (i) (ii) (iii)
- B. (iii) (ii) (i) (iv)
- C. (ii) (iii) (iv) (i)
- D. (i) (ii) (iii) (iv)
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Log in to view solution →- A. Transport of genetically modified organisms from one country to another
- B. Emission of ozone depleting substances
- C. Release of greenhouse gases
- D. Disposal of e-wastes
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Log in to view solution →- A. 2.0 meters
- B. 2.5 meters
- C. 2.2 meters
- D. 2.7 meters
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Log in to view solution →- A. He2
- B. Li2
- C. C2
- D. O2
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Log in to view solution →- A. 2 × 10^-13 M
- B. 2 × 10^-8 M
- C. 1 × 10^-13 M
- D. 1 × 10^8 M
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Log in to view solution →- A. (a), (b) and (c) only
- B. (a) and (c) only
- C. (b) and (c) only
- D. (c) and (d) only
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Log in to view solution →- A. −8.314 J mol^-1 K^-1 × 300 K × ln(2 × 10^13)
- B. 8.314 J mol^-1 K^-1 × 300 K × ln(2 × 10^13)
- C. 8.314 J mol^-1 K^-1 × 300 K × ln(3 × 10^13)
- D. −8.314 J mol^-1 K^-1 × 300 K × ln(4 × 10^13)
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Log in to view solution →- A. Cl
- B. CHCl2
- C. CHCl2
- D. CCl3
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Log in to view solution →- A. (a), (i)
- B. (b), (ii)
- C. (c), (iii)
- D. (d), (iv)
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Log in to view solution →- A. 3/4 × 288 pm
- B. 2/4 × 288 pm
- C. 4/3 × 288 pm
- D. 4/2 × 288 pm
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Log in to view solution →- A. Ammonia, beryllium difluoride, water, 1,4-dichlorobenzene
- B. Boron trifluoride, hydrogen fluoride, carbon dioxide, 1,3-dichlorobenzene
- C. Nitrogen trifluoride, beryllium difluoride, water, 1,3-dichlorobenzene
- D. Boron trifluoride, beryllium difluoride, carbon dioxide, 1,4-dichlorobenzene
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Log in to view solution →- A. Hydrogen gas
- B. Oxygen gas
- C. H2S gas
- D. SO2 gas
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Log in to view solution →- A. Hydrogen gas
- B. Oxygen gas
- C. H2S gas
- D. SO2 gas
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Log in to view solution →- A. Isopropyl alcohol
- B. Sec. butyl alcohol
- C. Tert. butyl alcohol
- D. Isobutyl alcohol
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Log in to view solution →- A. Isopropyl alcohol
- B. Sec. butyl alcohol
- C. Tert. butyl alcohol
- D. Isobutyl alcohol
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Log in to view solution →- A. H2SO3, sulphurous acid
- B. H2SO4, sulphuric acid
- C. H2S2O8, peroxodisulphuric acid
- D. H2S2O7, pyrosulphuric acid
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Log in to view solution →- A. H2SO3, sulphurous acid
- B. H2SO4, sulphuric acid
- C. H2S2O8, peroxodisulphuric acid
- D. H2S2O7, pyrosulphuric acid
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Log in to view solution →- A. CH3NH2
- B. NHCH3
- C. N(CH3)2
- D. NH(C2H5)
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Log in to view solution →- A. Aniline (C6H5NH2)
- B. N-methylaniline (C6H5NHCH3)
- C. N,N-dimethylaniline (C6H5N(CH3)2)
- D. Ethylmethylamine (C2H5NHCH3)
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Log in to view solution →- A. 3.87 BM
- B. 4.90 BM
- C. 5.92 BM
- D. 2.84 BM
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Log in to view solution →- A. 3.87 BM
- B. 4.90 BM
- C. 5.92 BM
- D. 2.84 BM
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Log in to view solution →- A. q = 0, ΔT = 0 and w = 0
- B. q = 0, ΔT < 0 and w > 0
- C. q < 0, ΔT = 0 and w = 0
- D. q > 0, ΔT > 0 and w > 0
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Log in to view solution →- A. 0.20 K
- B. 0.80 K
- C. 0.40 K
- D. 0.60 K
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Log in to view solution →- A. 1
- B. 2
- C. 3
- D. 4
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Log in to view solution →- A. Aldol condensation
- B. Cannizzaro’s reaction
- C. Cross Cannizzaro’s reaction
- D. Cross Aldol condensation
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Log in to view solution →- A. Adsorption chromatography
- B. Partition chromatography
- C. Thin layer chromatography
- D. Column chromatography
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Log in to view solution →- A. activation energy
- B. heat of reaction
- C. threshold energy
- D. collision frequency
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Log in to view solution →- A. 9 bar
- B. 12 bar
- C. 15 bar
- D. 18 bar
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Log in to view solution →- A. Wrought iron is impure iron with 4% carbon.
- B. Blister copper has blistered appearance due to evolution of CO2.
- C. Vapour phase refining is carried out for Nickel by Van Arkel method.
- D. Pig iron can be moulded into a variety of shapes.
Correct answer & explanation hidden
Log in to view solution →- A. −I effect of −CH3 groups
- B. +R effect of −CH3 groups
- C. −R effect of −CH3 groups
- D. Hyperconjugation
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Log in to view solution →- A. Sodium lauryl sulphate
- B. Sodium stearate
- C. Cetyltrimethyl ammonium bromide
- D. Sodium dodecylbenzene sulphonate
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Log in to view solution →- A. (a), (b), (c)
- B. (a), (c), (d)
- C. (b), (c), (d)
- D. (a), (b), (d)
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Log in to view solution →- A. Ethanol + Acetone
- B. Benzene + Toluene
- C. Acetone + Chloroform
- D. Chloroethane + Bromoethane
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Log in to view solution →- A. SCN− < F− < CO < CN−
- B. SCN− < F− < CN− < CO
- C. F− < SCN− < CO < CN−
- D. CN− < CO < SCN− < F−
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Log in to view solution →- A. Serine
- B. Alanine
- C. Tyrosine
- D. Lysine
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Log in to view solution →- A. Serine
- B. Alanine
- C. Tyrosine
- D. Lysine
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Log in to view solution →- A. Both MgCl2 and CaCl2
- B. Only NaCl
- C. Only MgCl2
- D. NaCl, MgCl2 and CaCl2
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Log in to view solution →- A. Both MgCl2 and CaCl2
- B. Only NaCl
- C. Only MgCl2
- D. NaCl, MgCl2 and CaCl2
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Log in to view solution →- A. cis-1,4-polyisoprene
- B. poly(butadiene-styrene)
- C. polybutadiene
- D. poly(butadiene-acrylonitrile)
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Log in to view solution →- A. cis-1,4-polyisoprene
- B. poly(butadiene-styrene)
- C. polybutadiene
- D. poly(butadiene-acrylonitrile)
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Log in to view solution →- A. β-D-Glucose + α-D-Fructose
- B. α-D-Glucose + β-D-Glucose
- C. α-D-Glucose + β-D-Fructose
- D. α-D-Fructose + β-D-Fructose
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Log in to view solution →- A. β-D-Glucose + α-D-Fructose
- B. α-D-Glucose + β-D-Glucose
- C. α-D-Glucose + β-D-Fructose
- D. α-D-Fructose + β-D-Fructose
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Log in to view solution →- A. Iron
- B. Copper
- C. Calcium
- D. Potassium
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Log in to view solution →- A. 1 g of Ag(s) [Atomic mass of Ag = 108]
- B. 1 g of Mg(s) [Atomic mass of Mg = 24]
- C. 1 g of O2(g) [Atomic mass of O = 16]
- D. 1 g of Li(s) [Atomic mass of Li = 7]
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Log in to view solution →- A. 71, 104 and 71
- B. 104, 71 and 71
- C. 71, 71 and 104
- D. 175, 104 and 71
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Log in to view solution →- A. +4 to +4
- B. 0 to +4
- C. −4 to +4
- D. 0 to −4
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Log in to view solution →- A. Cr2+ (d4) is a stronger reducing agent than Fe2+ (d6) in water.
- B. The transition metals and their compounds are known for their catalytic activity due to their ability to adopt multiple oxidation states and to form complexes.
- C. Interstitial compounds are those that are formed when small atoms like H, C or N are trapped inside the crystal lattices of metals.
- D. The oxidation states of chromium in CrO4^2− and Cr2O7^2− are not the same.
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Log in to view solution →- A. ΔrH > 0 and ΔrS > 0
- B. ΔrH > 0 and ΔrS < 0
- C. ΔrH < 0 and ΔrS > 0
- D. ΔrH < 0 and ΔrS < 0
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Log in to view solution →- A. Viscosity
- B. Solubility
- C. Stability of the colloidal particles
- D. Size of the colloidal particles
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Log in to view solution →- A. CuSO4
- B. [Cu(NH3)4]2+
- C. Cu(OH)2
- D. CuCO3·Cu(OH)2
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Log in to view solution →- A. (a) (b) (c) (d) = (iii) (i) (ii) (iv)
- B. (a) (b) (c) (d) = (iii) (ii) (i) (iv)
- C. (a) (b) (c) (d) = (iii) (iv) (ii) (i)
- D. (a) (b) (c) (d) = (i) (iii) (ii) (iv)
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Log in to view solution →- A. (a) Neutral, (b) Basic, (c) Amphoteric, (d) Acidic
- B. (a) Neutral, (b) Basic, (c) Amphoteric, (d) Acidic
- C. (a) Acidic, (b) Amphoteric, (c) Neutral, (d) Basic
- D. (a) Amphoteric, (b) Acidic, (c) Basic, (d) Neutral
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Log in to view solution →- A. 100 s
- B. 200 s
- C. 500 s
- D. 1000 s
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Log in to view solution →- A. 100 s
- B. 200 s
- C. 500 s
- D. 1000 s
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Log in to view solution →- A. CH2=CH−CH3
- B. CH3−CH2−CH3
- C. CH2=CH−CH2−CH3
- D. CH3−CH=CH2
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Log in to view solution →- A. CH2=CH–CH3
- B. CH3–CH2–CH3
- C. CH2=C(CH3)2
- D. CH3CH2CH3
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Log in to view solution →- A. n-Hexane
- B. 2,3-Dimethylbutane
- C. n-Heptane
- D. n-Butane
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Log in to view solution →- A. n-Hexane
- B. 2,3-Dimethylbutane
- C. n-Heptane
- D. n-Butane
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Log in to view solution →- A. Phenol + CH3I
- B. Iodobenzene + CH3OH
- C. Phenol + C2H5I
- D. Iodobenzene + C2H5OH
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Log in to view solution →- A. Phenol + CH3I
- B. Iodobenzene + CH3OH
- C. Phenol + C2H5I
- D. Iodobenzene + C2H5OH
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Log in to view solution →- A. Hydrogen atom
- B. Singly ionised helium atom (He+)
- C. Deuteron atom
- D. Singly ionised neon atom (Ne+)
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Log in to view solution →- A. Hydrogen atom
- B. Singly ionised helium atom (He+)
- C. Deuteron atom
- D. Singly ionised neon atom (Ne+)
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Log in to view solution →- A. c : 1
- B. 1 : 1
- C. 1 : c
- D. 1 : c2
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Log in to view solution →- A. c : 1
- B. 1 : 1
- C. 1 : c
- D. 1 : c^2
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Log in to view solution →- A. 0° < i_b < 30°
- B. 30° < i_b < 45°
- C. 45° < i_b < 90°
- D. i_b = 90°
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Log in to view solution →- A. 0.5 kg/m^3
- B. 0.2 kg/m^3
- C. 0.1 kg/m^3
- D. 0.02 kg/m^3
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Log in to view solution →- A. A/(2μ)
- B. 2A/μ
- C. μA
- D. A/(2μ) (repeated)
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Log in to view solution →- A. isothermal
- B. adiabatic
- C. isochoric
- D. isobaric
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Log in to view solution →- A. 4.5 × 10^16 J
- B. 4.5 × 10^13 J
- C. 1.5 × 10^13 J
- D. 0.5 × 10^13 J
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Log in to view solution →- A. 48 N
- B. 32 N
- C. 30 N
- D. 24 N
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Log in to view solution →- A. π rad
- B. 3π/2 rad
- C. π/2 rad
- D. zero
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Log in to view solution →- A. 0.01 mm
- B. 0.25 mm
- C. 0.5 mm
- D. 1.0 mm
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Log in to view solution →- A. 523 Hz
- B. 524 Hz
- C. 536 Hz
- D. 537 Hz
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Log in to view solution →- A. 33 cm
- B. 50 cm
- C. 67 cm
- D. 80 cm
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Log in to view solution →- A. 6i N m
- B. 6j N m
- C. -6i N m
- D. 6k N m
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Log in to view solution →- A. 10 × 10^3 J
- B. 12 × 10^3 J
- C. 24 × 10^3 J
- D. 48 × 10^3 J
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Log in to view solution →- A. 1.28 × 10^4 N/C
- B. 1.28 × 10^5 N/C
- C. 1.28 × 10^6 N/C
- D. 1.28 × 10^7 N/C
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Log in to view solution →- A. 1.28 × 10^4 N/C
- B. 1.28 × 10^5 N/C
- C. 1.28 × 10^6 N/C
- D. 1.28 × 10^7 N/C
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Log in to view solution →- A. zero
- B. 0.5 N/C
- C. 1 N/C
- D. 5 N/C
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Log in to view solution →- A. zero
- B. 0.5 N/C
- C. 1 N/C
- D. 5 N/C
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Log in to view solution →- A. forward bias only
- B. reverse bias only
- C. both forward bias and reverse bias
- D. increase in forward current
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Log in to view solution →- A. forward bias only
- B. reverse bias only
- C. both forward bias and reverse bias
- D. increase in forward current
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Log in to view solution →- A. 1.7 A
- B. 2.05 A
- C. 2.5 A
- D. 25.1 A
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Log in to view solution →- A. 1.7 A
- B. 2.05 A
- C. 2.5 A
- D. 25.1 A
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Log in to view solution →- A. 1/(2nπd)
- B. 1/(2√2 nπd^2)
- C. 1/(2n^2πd^2)
- D. 1/(2√2 nπd)
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Log in to view solution →- A. Base, emitter and collector regions should have same doping concentrations.
- B. Base, emitter and collector regions should have same size.
- C. Both emitter junction as well as the collector junction are forward biased.
- D. The base region must be very thin and lightly doped.
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Log in to view solution →- A. doubled
- B. four times
- C. one-fourth
- D. zero
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Log in to view solution →- A. 14456Ba
- B. 9140Zr
- C. 10136Kr
- D. 10336Kr
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Log in to view solution →- A. 6
- B. 0.6
- C. 0.06
- D. 0.006
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Log in to view solution →- A. g
- B. g/2
- C. g/5
- D. g/10
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Log in to view solution →- A. MgL/(A L1)
- B. MgL/(A(L - L1))
- C. MgL1/(AL)
- D. MgL/(A(L1 - L))
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Log in to view solution →- A. 1/2 kB T
- B. 3/2 kB T
- C. 5/2 kB T
- D. 7/2 kB T
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Log in to view solution →- A. Graph 1
- B. Graph 2
- C. Graph 3
- D. Graph 4
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Log in to view solution →- A. 470 kΩ, 5%
- B. 47 kΩ, 10%
- C. 4.7 kΩ, 5%
- D. 470 Ω, 5%
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Log in to view solution →- A. double
- B. half
- C. four times
- D. one-fourth
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Log in to view solution →- A. 0.44 × 10^-13 C^2 N^-1 m^-2
- B. 1.77 × 10^-12 C^2 N^-1 m^-2
- C. 0.44 × 10^-10 C^2 N^-1 m^-2
- D. 5.00 C^2 N^-1 m^-2
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Log in to view solution →- A. 0.44 × 10^-13 C^2 N^-1 m^-2
- B. 1.77 × 10^-12 C^2 N^-1 m^-2
- C. 0.44 × 10^-10 C^2 N^-1 m^-2
- D. 5.00 C^2 N^-1 m^-2
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Log in to view solution →- A. [MLT^-2]
- B. [ML^2T^-2]
- C. [ML^0T^-2]
- D. [ML^-1T^-2]
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Log in to view solution →- A. [MLT^-2]
- B. [ML^2T^-2]
- C. [ML^0T^-2]
- D. [ML^-1T^-2]
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Log in to view solution →- A. 3.66 × 10^-7 rad
- B. 1.83 × 10^-7 rad
- C. 7.32 × 10^-7 rad
- D. 6.00 × 10^-7 rad
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Log in to view solution →- A. 3.66 × 10^-7 rad
- B. 1.83 × 10^-7 rad
- C. 7.32 × 10^-7 rad
- D. 6.00 × 10^-7 rad
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Log in to view solution →- A. zero
- B. 0.5
- C. 1.0
- D. -1.0
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Log in to view solution →- A. zero
- B. 0.5
- C. 1.0
- D. -1.0
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Log in to view solution →- A. 50 V
- B. 200 V
- C. 400 V
- D. zero
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Log in to view solution →- A. 2.4π × 10^-4 T m A^-1
- B. 8.0 × 10^-5 T m A^-1
- C. 2.4π × 10^-5 T m A^-1
- D. 2.4π × 10^-7 T m A^-1
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Log in to view solution →- A. 6.28 × 10^-4 T
- B. 3.14 × 10^-4 T
- C. 6.28 × 10^-5 T
- D. 3.14 × 10^-5 T
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Log in to view solution →- A. 2.25 × 10^15
- B. 2.5 × 10^6
- C. 2.5 × 10^-6
- D. 2.25 × 10^-15
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Log in to view solution →- A. 27/8
- B. 9/4
- C. 3/2
- D. 5/3
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Log in to view solution →- A. 10 V
- B. 10^2 V
- C. 10^3 V
- D. 10^4 V
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Log in to view solution →- A. 9.9801 m
- B. 9.98 m
- C. 9.980 m
- D. 9.9 m
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Log in to view solution →- A. 360 m
- B. 340 m
- C. 320 m
- D. 300 m
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Log in to view solution →- A. 2.5 g
- B. 5.0 g
- C. 10.0 g
- D. 20.0 g
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Log in to view solution →- A. 1.0 × 10^-2 m
- B. 1.0 × 10^-1 m
- C. 1.5 × 10^-1 m
- D. 1.5 × 10^-2 m
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Log in to view solution →- A. A B Y 0 0 0 0 1 0 1 0 0 1 1 1
- B. A B Y 0 0 0 0 1 1 1 0 1 1 1 1
- C. A B Y 0 0 1 0 1 1 1 0 1 1 1 0
- D. A B Y 0 0 1 0 1 0 1 0 0 1 1 0
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