- A. Primary aliphatic or aromatic amine
- B. Secondary amine
- C. Tertiary amine
- D. Secondary amine with different alkyl groups
Correct answer & explanation hidden
Log in to view solution →- A. CH3-CH=CH2
- B. CH3-CH2-CH=CH2
- C. CH2=CH-CH2-CH3
- D. CH3-CH2-CH=CH-CH3
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Log in to view solution →- A. (a)-(iii), (b)-(i), (c)-(ii), (d)-(iv)
- B. (a)-(iii), (b)-(ii), (c)-(i), (d)-(iv)
- C. (a)-(iii), (b)-(iv), (c)-(ii), (d)-(i)
- D. (a)-(i), (b)-(iii), (c)-(ii), (d)-(iv)
Correct answer & explanation hidden
Log in to view solution →- A. 0.20 K
- B. 0.80 K
- C. 0.40 K
- D. 0.60 K
Correct answer & explanation hidden
Log in to view solution →- A. Hydrogen gas
- B. Oxygen gas
- C. H2S gas
- D. SO2 gas
Correct answer & explanation hidden
Log in to view solution →- A. Chlorotoluene
- B. Benzyl chloride
- C. Benzal chloride (Benzylidene chloride)
- D. Benzotrichloride
Correct answer & explanation hidden
Log in to view solution →- A. 1 g of Ag(s)
- B. 1 g of Mg(s)
- C. 1 g of O2(g)
- D. 1 g of Li(s)
Correct answer & explanation hidden
Log in to view solution →- A. Wrought iron is impure iron with 4% carbon.
- B. Blister copper has blistered appearance due to evolution of CO2.
- C. Vapour phase refining is carried out for Nickel by Van Arkel method.
- D. Pig iron can be moulded into a variety of shapes.
Correct answer & explanation hidden
Log in to view solution →- A. – I effect of – CH3 groups
- B. + R effect of – CH3 groups
- C. – R effect of – CH3 groups
- D. Hyperconjugation
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Log in to view solution →- A. CuSO4
- B. [Cu(NH3)4]2+
- C. Cu(OH)2
- D. CuCO3·Cu(OH)2
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Log in to view solution →- A. CuSO4
- B. [Cu(NH3)4]2+
- C. Cu(OH)2
- D. CuCO3⋅Cu(OH)2
Correct answer & explanation hidden
Log in to view solution →- A. 9 bar
- B. 12 bar
- C. 15 bar
- D. 18 bar
Correct answer & explanation hidden
Log in to view solution →- A. 9 bar
- B. 12 bar
- C. 15 bar
- D. 18 bar
Correct answer & explanation hidden
Log in to view solution →- A. (sqrt(3)/4) * 288 pm
- B. (sqrt(2)/4) * 288 pm
- C. (4/sqrt(3)) * 288 pm
- D. (4/sqrt(2)) * 288 pm
Correct answer & explanation hidden
Log in to view solution →- A. (√3/4) * 288 pm
- B. (√2/4) * 288 pm
- C. (4/√3) * 288 pm
- D. (4/√2) * 288 pm
Correct answer & explanation hidden
Log in to view solution →- A. 100 s
- B. 200 s
- C. 500 s
- D. 1000 s
Correct answer & explanation hidden
Log in to view solution →- A. 100 s
- B. 200 s
- C. 500 s
- D. 1000 s
Correct answer & explanation hidden
Log in to view solution →- A. Isopropyl alcohol
- B. Sec. butyl alcohol
- C. Tert. butyl alcohol
- D. Isobutyl alcohol
Correct answer & explanation hidden
Log in to view solution →- A. Ammonia, beryllium difluoride, water, 1,4-dichlorobenzene
- B. Boron trifluoride, hydrogen fluoride, carbon dioxide, 1,3-dichlorobenzene
- C. Nitrogen trifluoride, beryllium difluoride, water, 1,3-dichlorobenzene
- D. Boron trifluoride, beryllium difluoride, carbon dioxide, 1,4-dichlorobenzene
Correct answer & explanation hidden
Log in to view solution →- A. + 4 to + 4
- B. 0 to + 4
- C. – 4 to + 4
- D. 0 to – 4
Correct answer & explanation hidden
Log in to view solution →- A. (a)-(i), (b)-(ii), (c)-(iii), (d)-(iv)
- B. (a)-(ii), (b)-(i), (c)-(iv), (d)-(iii)
- C. (a)-(iii), (b)-(iv), (c)-(i), (d)-(ii)
- D. (a)-(iv), (b)-(iii), (c)-(ii), (d)-(i)
Correct answer & explanation hidden
Log in to view solution →- A. It forms carboxyhaemoglobin
- B. It reduces oxygen carrying ability of blood.
- C. The carboxyhaemoglobin (haemoglobin bound to CO) is less stable than oxyhaemoglobin.
- D. It is produced due to incomplete combustion.
Correct answer & explanation hidden
Log in to view solution →- A. Viscosity
- B. Solubility
- C. Stability of the colloidal particles
- D. Size of the colloidal particles
Correct answer & explanation hidden
Log in to view solution →- A. SCN– < F– < C2O42– < CN–
- B. SCN– < F– < CN– < C2O42–
- C. F– < SCN– < C2O42– < CN–
- D. CN– < C2O42– < SCN– < F–
Correct answer & explanation hidden
Log in to view solution →- A. (a), (b), (c)
- B. (a), (c), (d)
- C. (b), (c), (d)
- D. (a), (b), (d)
Correct answer & explanation hidden
Log in to view solution →- A. q = 0, ΔT = 0 and w = 0
- B. q = 0, ΔT < 0 and w > 0
- C. q < 0, ΔT = 0 and w = 0
- D. q > 0, ΔT > 0 and w > 0
Correct answer & explanation hidden
Log in to view solution →- A. Cr2+ (d4) is a stronger reducing agent than Fe2+ (d6) in water.
- B. The transition metals and their compounds are known for their catalytic activity.
- C. Interstitial compounds are those that are formed when small atoms like H, C or N are trapped inside the crystal lattices of metals.
- D. The oxidation states of chromium in CrO4^2– and Cr2O7^2– are not the same.
Correct answer & explanation hidden
Log in to view solution →- A. (a) Unnilunium (i) Mendelevium
- B. (b) Unniltrium (ii) Lawrencium
- C. (c) Unnilhexium (iii) Seaborgium
- D. (d) Unununnium (iv) Darmstadtium
Correct answer & explanation hidden
Log in to view solution →- A. Unnilunium (i) Mendelevium
- B. Unniltrium (ii) Lawrencium
- C. Unnilhexium (iii) Seaborgium
- D. Unununnium (iv) Darmstadtium
Correct answer & explanation hidden
Log in to view solution →- A. Aldol condensation
- B. Cannizzaro’s reaction
- C. Cross Cannizzaro’s reaction
- D. Cross Aldol condensation
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Log in to view solution →- A. Aldol condensation
- B. Cannizzaro’s reaction
- C. Cross Cannizzaro’s reaction
- D. Cross Aldol condensation
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Log in to view solution →- A. H2SO3, sulphurous acid
- B. H2SO4, sulphuric acid
- C. H2S2O8, peroxodisulphuric acid
- D. H2S2O7, pyrosulphuric acid
Correct answer & explanation hidden
Log in to view solution →- A. H2SO3, sulphurous acid
- B. H2SO4, sulphuric acid
- C. H2S2O8, peroxodisulphuric acid
- D. H2S2O7, pyrosulphuric acid
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Log in to view solution →- A. Both MgCl2 and CaCl2
- B. Only NaCl
- C. Only MgCl2
- D. NaCl, MgCl2 and CaCl2
Correct answer & explanation hidden
Log in to view solution →- A. Both MgCl2 and CaCl2
- B. Only NaCl
- C. Only MgCl2
- D. NaCl, MgCl2 and CaCl2
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Log in to view solution →- A. Phenol + CH3I
- B. Iodobenzene + CH3OH
- C. Phenol + C2H5I
- D. Iodobenzene + C2H5OH
Correct answer & explanation hidden
Log in to view solution →- A. (a), (b) and (c) only
- B. (a) and (c) only
- C. (b) and (c) only
- D. (c) and (d) only
Correct answer & explanation hidden
Log in to view solution →- A. ΔrH > 0 and ΔrS > 0
- B. ΔrH > 0 and ΔrS < 0
- C. ΔrH < 0 and ΔrS > 0
- D. ΔrH < 0 and ΔrS < 0
Correct answer & explanation hidden
Log in to view solution →- A. Adsorption chromatography
- B. Partition chromatography
- C. Thin layer chromatography
- D. Column chromatography
Correct answer & explanation hidden
Log in to view solution →- A. n-Hexane
- B. 2,3-Dimethylbutane
- C. n-Heptane
- D. n-Butane
Correct answer & explanation hidden
Log in to view solution →- A. activation energy
- B. heat of reaction
- C. threshold energy
- D. collision frequency
Correct answer & explanation hidden
Log in to view solution →- A. 1
- B. 2
- C. 3
- D. 4
Correct answer & explanation hidden
Log in to view solution →- A. Ethanol + Acetone
- B. Benzene + Toluene
- C. Acetone + Chloroform
- D. Chloroethane + Bromoethane
Correct answer & explanation hidden
Log in to view solution →- A. -8.314 J mol–1 K–1 × 300 K × ln(2 × 10^13)
- B. 8.314 J mol–1 K–1 × 300 K × ln(2 × 10^13)
- C. 8.314 J mol–1 K–1 × 300 K × ln(3 × 10^13)
- D. -8.314 J mol–1 K–1 × 300 K × ln(4 × 10^13)
Correct answer & explanation hidden
Log in to view solution →- A. β-D-Glucose + α-D-Fructose
- B. α-D-Glucose + β-D-Glucose
- C. α-D-Glucose + β-D-Fructose
- D. α-D-Fructose + β-D-Fructose
Correct answer & explanation hidden
Log in to view solution →- A. 3.87 BM
- B. 4.90 BM
- C. 5.92 BM
- D. 2.84 BM
Correct answer & explanation hidden
Log in to view solution →- A. cis-1, 4-polyisoprene
- B. poly (Butadiene-styrene)
- C. polybutadiene
- D. poly (Butadiene-acrylonitrile)
Correct answer & explanation hidden
Log in to view solution →- A. Serine
- B. Alanine
- C. Tyrosine
- D. Lysine
Correct answer & explanation hidden
Log in to view solution →- A. Sodium lauryl sulphate
- B. Sodium stearate
- C. Cetyltrimethyl ammonium bromide
- D. Sodium dodecylbenzene sulphonate
Correct answer & explanation hidden
Log in to view solution →- A. 2 × 10^-13 M
- B. 2 × 10^-8 M
- C. 1 × 10^-13 M
- D. 1 × 10^8 M
Correct answer & explanation hidden
Log in to view solution →- A. 2 × 10^–13 M
- B. 2 × 10^–8 M
- C. 1 × 10^–13 M
- D. 1 × 10^8 M
Correct answer & explanation hidden
Log in to view solution →- A. He2
- B. Li2
- C. C2
- D. O2
Correct answer & explanation hidden
Log in to view solution →- A. He2
- B. Li2
- C. C2
- D. O2
Correct answer & explanation hidden
Log in to view solution →- A. Iron
- B. Copper
- C. Calcium
- D. Potassium
Correct answer & explanation hidden
Log in to view solution →- A. Iron
- B. Copper
- C. Calcium
- D. Potassium
Correct answer & explanation hidden
Log in to view solution →- A. 71, 104 and 71
- B. 104, 71 and 71
- C. 71, 71 and 104
- D. 175, 104 and 71
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Log in to view solution →- A. 71, 104 and 71
- B. 104, 71 and 71
- C. 71, 71 and 104
- D. 175, 104 and 71
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Log in to view solution →- A. 10 × 10^3 J
- B. 12 × 10^3 J
- C. 24 × 10^3 J
- D. 48 × 10^3 J
Correct answer & explanation hidden
Log in to view solution →- A. 10 × 10^3 J
- B. 12 × 10^3 J
- C. 24 × 10^3 J
- D. 48 × 10^3 J
Correct answer & explanation hidden
Log in to view solution →- A. Base, emitter and collector regions should have same doping concentrations.
- B. Base, emitter and collector regions should have same size.
- C. Both emitter junction as well as the collector junction are forward biased.
- D. The base region must be very thin and lightly doped.
Correct answer & explanation hidden
Log in to view solution →- A. zero
- B. 0.5 N/C
- C. 1 N/C
- D. 5 N/C
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Log in to view solution →- A. 1.7 A
- B. 2.05 A
- C. 2.5 A
- D. 25.1 A
Correct answer & explanation hidden
Log in to view solution →- A. 0.5 kg/m^3
- B. 0.2 kg/m^3
- C. 0.1 kg/m^3
- D. 0.02 kg/m^3
Correct answer & explanation hidden
Log in to view solution →- A. 9.9801 m
- B. 9.98 m
- C. 9.980 m
- D. 9.9 m
Correct answer & explanation hidden
Log in to view solution →- A. 1 / (√2 n dπ)
- B. 1 / (√2 n π d^2)
- C. 1 / (2 √2 n π d^2)
- D. 1 / (2 √2 n π d^2)
Correct answer & explanation hidden
Log in to view solution →- A. 2.4π × 10^-4 T m A^-1
- B. 8.0 × 10^-5 T m A^-1
- C. 2.4π × 10^-5 T m A^-1
- D. 2.4π × 10^-7 T m A^-1
Correct answer & explanation hidden
Log in to view solution →- A. 50 V
- B. 200 V
- C. 400 V
- D. zero
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Log in to view solution →- A. 48 N
- B. 32 N
- C. 30 N
- D. 24 N
Correct answer & explanation hidden
Log in to view solution →- A. metals
- B. insulators only
- C. semiconductors only
- D. insulators and semiconductors
Correct answer & explanation hidden
Log in to view solution →- A. doubled
- B. four times
- C. one-fourth
- D. zero
Correct answer & explanation hidden
Log in to view solution →- A. zero
- B. 0.5
- C. 1.0
- D. –1.0
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Log in to view solution →- A. zero
- B. 0.5
- C. 1.0
- D. -1.0
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Log in to view solution →- A. 1.28 × 10^4 N/C
- B. 1.28 × 10^5 N/C
- C. 1.28 × 10^6 N/C
- D. 1.28 × 10^7 N/C
Correct answer & explanation hidden
Log in to view solution →- A. 1.28 × 10⁴ N/C
- B. 1.28 × 10⁵ N/C
- C. 1.28 × 10⁶ N/C
- D. 1.28 × 10⁷ N/C
Correct answer & explanation hidden
Log in to view solution →- A. 6i Nm
- B. 6j Nm
- C. 6i Nm (negative)
- D. 6k Nm
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Log in to view solution →- A. 6i Nm
- B. 6j Nm
- C. 6i Nm
- D. 6k Nm
Correct answer & explanation hidden
Log in to view solution →- A. 2.25 × 10¹⁵
- B. 2.5 × 10⁶
- C. 2.5 × 10⁻⁶
- D. 2.25 × 10⁻¹⁵
Correct answer & explanation hidden
Log in to view solution →- A. A/2μ
- B. 2A/μ
- C. μA
- D. A/2μ
Correct answer & explanation hidden
Log in to view solution →- A. 27/8
- B. 9/4
- C. 3/2
- D. 5/3
Correct answer & explanation hidden
Log in to view solution →- A. ¹⁴⁴₅₆Ba
- B. ⁹¹₄₀Zr
- C. ¹⁰¹₃₆Kr
- D. ¹⁰³₃₆Kr
Correct answer & explanation hidden
Log in to view solution →- A. π rad
- B. 3π/2 rad
- C. π/2 rad
- D. zero
Correct answer & explanation hidden
Log in to view solution →- A. 1.0 × 10⁻² m
- B. 1.0 × 10⁻¹ m
- C. 1.5 × 10⁻¹ m
- D. 1.5 × 10⁻² m
Correct answer & explanation hidden
Log in to view solution →- A. 2.5 g
- B. 5.0 g
- C. 10.0 g
- D. 20.0 g
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Log in to view solution →- A. c : 1
- B. 1 : 1
- C. 1 : c
- D. 1 : c²
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Log in to view solution →- A. double
- B. half
- C. four times
- D. one-fourth
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Log in to view solution →- A. 6.28 × 10⁻⁴ T
- B. 3.14 × 10⁻⁴ T
- C. 6.28 × 10⁻⁵ T
- D. 3.14 × 10⁻⁵ T
Correct answer & explanation hidden
Log in to view solution →- A. 360 m
- B. 340 m
- C. 320 m
- D. 300 m
Correct answer & explanation hidden
Log in to view solution →- A. Hydrogen atom
- B. Singly ionised helium atom (He⁺)
- C. Deuteron atom
- D. Singly ionised neon atom (Ne⁺)
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Log in to view solution →- A. 1/2 kBT
- B. 3/2 kBT
- C. 5/2 kBT
- D. 7/2 kBT
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Log in to view solution →- A. 1/2 kB T
- B. 3/2 kB T
- C. 5/2 kB T
- D. 7/2 kB T
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Log in to view solution →- A. 33 cm
- B. 50 cm
- C. 67 cm
- D. 80 cm
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Log in to view solution →- A. 33 cm
- B. 50 cm
- C. 67 cm
- D. 80 cm
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Log in to view solution →- A. 523 Hz
- B. 524 Hz
- C. 536 Hz
- D. 537 Hz
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Log in to view solution →- A. 523 Hz
- B. 524 Hz
- C. 536 Hz
- D. 537 Hz
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Log in to view solution →- A. isothermal
- B. adiabatic
- C. isochoric
- D. isobaric
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Log in to view solution →- A. 0.44 × 10^–13 C^2 N^–1 m^–2
- B. 1.77 × 10^–12 C^2 N^–1 m^–2
- C. 0.44 × 10^–10 C^2 N^–1 m^–2
- D. 5.00 C^2 N^–1 m^–2
Correct answer & explanation hidden
Log in to view solution →- A. 10 V
- B. 10^2 V
- C. 10^3 V
- D. 10^4 V
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Log in to view solution →- A. MgL / AL1
- B. Mg(L1 - L) / AL
- C. MgL / AL
- D. MgL / A(L1 - L)
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Log in to view solution →- A. 0° < ib < 30°
- B. 30° < ib < 45°
- C. 45° < ib < 90°
- D. ib = 90°
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Log in to view solution →- A. g
- B. g/2
- C. g/5
- D. g/10
Correct answer & explanation hidden
Log in to view solution →- A. [MLT^–2]
- B. [ML^2T^–2]
- C. [ML^0T^–2]
- D. [ML^–1T^–2]
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Log in to view solution →- A. 0.01 mm
- B. 0.25 mm
- C. 0.5 mm
- D. 1.0 mm
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Log in to view solution →- A. 6
- B. 0.6
- C. 0.06
- D. 0.006
Correct answer & explanation hidden
Log in to view solution →- A. 470 kΩ, 5%
- B. 47 kΩ, 10%
- C. 4.7 kΩ, 5%
- D. 470 Ω, 5%
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Log in to view solution →- A. 3.66 × 10^–7 rad
- B. 1.83 × 10^–7 rad
- C. 7.32 × 10^–7 rad
- D. 6.00 × 10^–7 rad
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Log in to view solution →- A. forward bias only
- B. reverse bias only
- C. both forward bias and reverse bias
- D. increase in forward current
Correct answer & explanation hidden
Log in to view solution →- A. 4.5 × 10^16 J
- B. 4.5 × 10^13 J
- C. 1.5 × 10^13 J
- D. 0.5 × 10^13 J
Correct answer & explanation hidden
Log in to view solution →- A. only (a)
- B. (a) and (c)
- C. (b), (c) and (d)
- D. only (d)
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Log in to view solution →- A. only (a)
- B. (a) and (c)
- C. (b), (c) and (d)
- D. only (d)
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Log in to view solution →- A. (ii) (iii) (i) (iv)
- B. (iii) (i) (iv) (ii)
- C. (iv) (ii) (i) (iii)
- D. (i) (ii) (iv) (iii)
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Log in to view solution →- A. (1) (ii) (iii) (i) (iv)
- B. (2) (iii) (i) (iv) (ii)
- C. (3) (iv) (ii) (i) (iii)
- D. (4) (i) (ii) (iv) (iii)
Correct answer & explanation hidden
Log in to view solution →- A. When exposed to antigen (living or dead) antibodies are produced in the host’s body. It is called “Active immunity”.
- B. When ready-made antibodies are directly given, it is called “Passive immunity”.
- C. Active immunity is quick and gives full response.
- D. Foetus receives some antibodies from mother, it is an example for passive immunity.
Correct answer & explanation hidden
Log in to view solution →- A. (a) and (b)
- B. (c) and (d)
- C. (a), (b) and (d)
- D. only (d)
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Log in to view solution →- A. 2 molecules of 3-C compound
- B. 1 molecule of 3-C compound
- C. 1 molecule of 6-C compound
- D. 1 molecule of 4-C compound and 1 molecule of 2-C compound
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Log in to view solution →- A. Trophozoites
- B. Sporozoites
- C. Female gametocytes
- D. Male gametocytes
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Log in to view solution →- A. They are not bound by any membrane
- B. These are involved in ingestion of food particles
- C. They lie free in the cytoplasm
- D. These represent reserve material in cytoplasm
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Log in to view solution →- A. Pachytene
- B. Zygotene
- C. Diplotene
- D. Leptotene
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Log in to view solution →- A. Inferior ovary
- B. Superior ovary
- C. Hypogynous ovary
- D. Half inferior ovary
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Log in to view solution →- A. Acetocarmine in bright blue light
- B. Ethidium bromide in UV radiation
- C. Acetocarmine in UV radiation
- D. Ethidium bromide in infrared radiation
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Log in to view solution →- A. ZIFT and IUT
- B. GIFT and ZIFT
- C. ICSI and ZIFT
- D. GIFT and ICSI
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Log in to view solution →- A. Gonorrhoea, Syphilis, Genital herpes
- B. Gonorrhoea, Malaria, Genital herpes
- C. AIDS, Malaria, Filaria
- D. Cancer, AIDS, Syphilis
Correct answer & explanation hidden
Log in to view solution →- A. Binding of oxygen with haemoglobin is mainly related to partial pressure of O2
- B. Partial pressure of CO2 can interfere with O2 binding with haemoglobin
- C. Higher H+ conc. in alveoli favours the formation of oxyhaemoglobin
- D. Low pCO2 in alveoli favours the formation of oxyhaemoglobin
Correct answer & explanation hidden
Log in to view solution →- A. Heart wood does not conduct water but gives mechanical support
- B. Sapwood is involved in conduction of water and minerals from root to leaf
- C. Sapwood is the innermost secondary xylem and is lighter in colour
- D. Due to deposition of tannins, resins, oils etc., heart wood is dark in colour
Correct answer & explanation hidden
Log in to view solution →- A. Each restriction enzyme functions by inspecting the length of a DNA sequence.
- B. They cut the strand of DNA at palindromic sites.
- C. They are useful in genetic engineering.
- D. Sticky ends can be joined by using DNA ligases.
Correct answer & explanation hidden
Log in to view solution →- A. Each restriction enzyme functions by inspecting the length of a DNA sequence.
- B. They cut the strand of DNA at palindromic sites.
- C. They are useful in genetic engineering.
- D. Sticky ends can be joined by using DNA ligases.
Correct answer & explanation hidden
Log in to view solution →- A. Starch and cellulose
- B. Amylopectin and glycogen
- C. Mannitol and algin
- D. Laminarin and cellulose
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Log in to view solution →- A. Starch and cellulose
- B. Amylopectin and glycogen
- C. Mannitol and algin
- D. Laminarin and cellulose
Correct answer & explanation hidden
Log in to view solution →- A. Ligases - Join the two DNA molecules
- B. Polymerases - Break the DNA into fragments
- C. Nucleases - Separate the two strands of DNA
- D. Exonucleases - Make cuts at specific positions within DNA
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Log in to view solution →- A. Ligases - Join the two DNA molecules
- B. Polymerases - Break the DNA into fragments
- C. Nucleases - Separate the two strands of DNA
- D. Exonucleases - Make cuts at specific positions within DNA
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Log in to view solution →- A. Karl Ernst von Baer
- B. Alfred Wallace
- C. Charles Darwin
- D. Oparin
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Log in to view solution →- A. Karl Ernst von Baer
- B. Alfred Wallace
- C. Charles Darwin
- D. Oparin
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Log in to view solution →- A. Binding of mRNA to ribosome
- B. Recognition of DNA molecule
- C. Aminoacylation of tRNA
- D. Recognition of an anti-codon
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Log in to view solution →- A. Binding of mRNA to ribosome
- B. Recognition of DNA molecule
- C. Aminoacylation of tRNA
- D. Recognition of an anti-codon
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Log in to view solution →- A. (a) only
- B. (a), (b) and (c)
- C. (c) and (d)
- D. (a) and (d)
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Log in to view solution →- A. Zero
- B. One
- C. Two
- D. Three
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Log in to view solution →- A. (ii) (iv) (i) (iii)
- B. (i) (iii) (ii) (iv)
- C. (iii) (ii) (iv) (i)
- D. (iv) (iii) (i) (ii)
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Log in to view solution →- A. (i) (iii) (ii) (iv)
- B. (iii) (iv) (i) (ii)
- C. (ii) (i) (iii) (iv)
- D. (iv) (i) (ii) (iii)
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Log in to view solution →- A. Transport of Genetically modified organisms from one country to another
- B. Emission of ozone depleting substances
- C. Release of Green House gases
- D. Disposal of e-wastes
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Log in to view solution →- A. Repolarisation of auricles
- B. Depolarisation of auricles
- C. Depolarisation of ventricles
- D. Repolarisation of ventricles
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Log in to view solution →- A. Cytokinin
- B. Gibberellin
- C. Ethylene
- D. Abscisic acid
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Log in to view solution →- A. 4
- B. 2
- C. 14
- D. 8
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Log in to view solution →- A. Ctenophora
- B. Platyhelminthes
- C. Aschelminthes
- D. Annelida
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Log in to view solution →- A. Lining of intestine
- B. Ducts of salivary glands
- C. Proximal convoluted tubule of nephron
- D. Eustachian tube
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Log in to view solution →- A. Endoplasmic reticulum
- B. Peroxisomes
- C. Golgi bodies
- D. Polysomes
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Log in to view solution →- A. PS-II to Cytb6f complex
- B. Cytb6f complex to PS-I
- C. PS-I to NADP+
- D. PS-I to ATP synthase
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Log in to view solution →- A. (ii) (i) (iv) (iii)
- B. (iv) (iii) (ii) (i)
- C. (iii) (iv) (ii) (i)
- D. (iv) (i) (ii) (iii)
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Log in to view solution →- A. (1) (ii) (i) (iv) (iii)
- B. (2) (iv) (iii) (ii) (i)
- C. (3) (iii) (iv) (ii) (i)
- D. (4) (iv) (i) (ii) (iii)
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Log in to view solution →- A. Fibrous roots
- B. Primary roots
- C. Prop roots
- D. Lateral roots
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Log in to view solution →- A. Fibrous roots
- B. Primary roots
- C. Prop roots
- D. Lateral roots
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Log in to view solution →- A. CH4, H2, NH3 and water vapor at 800°C
- B. CH3, H2, NH4 and water vapor at 800°C
- C. CH4, H2, NH3 and water vapor at 600°C
- D. CH3, H2, NH3 and water vapor at 600°C
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Log in to view solution →- A. CH4, H2, NH3 and water vapor at 800°C
- B. CH3, H2, NH4 and water vapor at 800°C
- C. CH4, H2, NH3 and water vapor at 600°C
- D. CH3, H2, NH3 and water vapor at 600°C
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Log in to view solution →- A. Tyrosine
- B. Glutamic Acid
- C. Lysine
- D. Valine
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Log in to view solution →- A. Tyrosine
- B. Glutamic Acid
- C. Lysine
- D. Valine
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Log in to view solution →- A. Log phase
- B. Lag phase
- C. Senescence
- D. Dormancy
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Log in to view solution →- A. Log phase
- B. Lag phase
- C. Senescence
- D. Dormancy
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Log in to view solution →- A. Uremia and Ketonuria
- B. Uremia and Renal Calculi
- C. Ketonuria and Glycosuria
- D. Renal calculi and Hyperglycaemia
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Log in to view solution →- A. Haemophilia – Y linked
- B. Phenylketonuria – Autosomal dominant trait
- C. Sickle cell anaemia – Autosomal recessive trait, chromosome-11
- D. Thalassemia – X linked
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Log in to view solution →- A. Salvinia
- B. Pteris
- C. Marchantia
- D. Equisetum
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Log in to view solution →- A. The gene (I) has three alleles.
- B. A person will have only two of the three alleles.
- C. When IA and IB are present together, they express same type of sugar.
- D. Allele ‘i’ does not produce any sugar.
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Log in to view solution →- A. IIeum opens into small intestine
- B. Serosa is the innermost layer of the alimentary canal
- C. IIeum is a highly coiled part
- D. Vermiform appendix arises from duodenum
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Log in to view solution →- A. More water reabsorption due to undersecretion of ADH
- B. Reabsorption of Na+ and water from renal tubules due to aldosterone
- C. Atrial natriuretic factor causes vasoconstriction
- D. Decrease in secretion of renin by JG cells
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Log in to view solution →- A. (1) (iii) (iv) (i) (ii)
- B. (2) (iv) (iii) (ii) (i)
- C. (3) (i) (ii) (iv) (iii)
- D. (4) (ii) (iv) (iii) (i)
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Log in to view solution →- A. Gibberellic acid
- B. Abscisic acid
- C. Phenolic acid
- D. Para-ascorbic acid
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Log in to view solution →- A. (1) (iv) (i) (ii) (iii)
- B. (2) (iii) (ii) (i) (iv)
- C. (3) (ii) (iii) (iv) (i)
- D. (4) (i) (ii) (iii) (iv)
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Log in to view solution →- A. (1) (ii) (iv) (iii) (i)
- B. (2) (iii) (i) (iv) (ii)
- C. (3) (iii) (iv) (i) (ii)
- D. (4) (ii) (iii) (i) (iv)
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Log in to view solution →- A. Selectable marker
- B. Ori site
- C. Palindromic sequence
- D. Recognition site
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Log in to view solution →- A. Selectable marker
- B. Ori site
- C. Palindromic sequence
- D. Recognition site
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Log in to view solution →- A. Freezing of fluids in the eye by low temperature
- B. Inflammation of cornea due to high dose of UV-B radiation
- C. High reflection of light from snow
- D. Damage to retina caused by infra-red rays
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Log in to view solution →- A. Freezing of fluids in the eye by low temperature
- B. Inflammation of cornea due to high dose of UV-B radiation
- C. High reflection of light from snow
- D. Damage to retina caused by infra-red rays
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Log in to view solution →- A. 1.5 million
- B. 20 million
- C. 50 million
- D. 7 million
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Log in to view solution →- A. 1.5 million
- B. 20 million
- C. 50 million
- D. 7 million
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Log in to view solution →- A. Out crossing
- B. Mutational breeding
- C. Cross breeding
- D. Inbreeding
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Log in to view solution →- A. Out crossing
- B. Mutational breeding
- C. Cross breeding
- D. Inbreeding
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Log in to view solution →- A. Western Ghats of India
- B. Madagascar
- C. Himalayas
- D. Amazon forests
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Log in to view solution →- A. Western Ghats of India
- B. Madagascar
- C. Himalayas
- D. Amazon forests
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Log in to view solution →- A. (1) (ii) (iii) (iv) (i)
- B. (2) (iii) (iv) (i) (ii)
- C. (3) (iv) (ii) (iii) (i)
- D. (4) (i) (iv) (iii) (ii)
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Log in to view solution →- A. In man insulin is synthesised as a proinsulin
- B. The proinsulin has an extra peptide called C-peptide.
- C. The functional insulin has A and B chains linked together by hydrogen bonds.
- D. Genetically engineered insulin is produced in E.Coli.
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Log in to view solution →- A. (1) (ii) (iv) (iii) (i)
- B. (2) (iv) (iii) (i) (ii)
- C. (3) (iii) (ii) (iv) (i)
- D. (4) (iii) (iv) (i) (ii)
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Log in to view solution →- A. Laminaria and Sargassum
- B. Gelidium and Gracilaria
- C. Anabaena and Volvox
- D. Chlorella and Spirulina
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Log in to view solution →- A. Chitin, cholesterol
- B. Glycerol, trypsin
- C. Cellulose, lecithin
- D. Inulin, insulin
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