- A. current in n-type > current in p-type.
- B. No current will flow in p-type, current will only flow in n-type.
- C. current in n-type = current in p-type.
- D. current in p-type > current in n-type.
Correct answer & explanation hidden
Log in to view solution →- A. current in n-type > current in p-type
- B. No current will flow in p-type, current will only flow in n-type
- C. current in n-type = current in p-type
- D. current in p-type > current in n-type
Correct answer & explanation hidden
Log in to view solution →- A. (2n+1)/(2n-1)
- B. 2n/(2n-1)
- C. (2n-1)/2n
- D. (2n-1)/(2n+1)
Correct answer & explanation hidden
Log in to view solution →- A. (2n+1)/(2n-1)
- B. 2n/(2n-1)
- C. (2n-1)/2n
- D. (2n-1)/(2n+1)
Correct answer & explanation hidden
Log in to view solution →- A. 3 v
- B. 4 v
- C. v
- D. 2 v
Correct answer & explanation hidden
Log in to view solution →- A. 3v
- B. 4v
- C. v
- D. 2v
Correct answer & explanation hidden
Log in to view solution →- A. 4 Ω
- B. 5 Ω
- C. 4√2 Ω
- D. 5√2 Ω
Correct answer & explanation hidden
Log in to view solution →- A. acquire a dipole moment only when magnetic field is absent
- B. having a permanent electric dipole moment
- C. having zero dipole moment
- D. acquire a dipole moment only in the presence of electric field due to displacement of charges
Correct answer & explanation hidden
Log in to view solution →- A. 0.26 cm
- B. 0.052 cm
- C. 0.52 cm
- D. 0.026 cm
Correct answer & explanation hidden
Log in to view solution →- A. 2/3
- B. 2/(3^2)
- C. 1/2
- D. 1/(2^1.5)
Correct answer & explanation hidden
Log in to view solution →- A. 10^16
- B. 10^15
- C. 10^18
- D. 10^17
Correct answer & explanation hidden
Log in to view solution →- A. 3Mg/2
- B. 2Mg
- C. Mg/2
- D. Mg
Correct answer & explanation hidden
Log in to view solution →- A. 1/2 * ε0 * E^2 * Ad
- B. ε0 * E^2 * Ad
- C. 1/2 * ε0 * E^2
- D. ε0 * E * Ad
Correct answer & explanation hidden
Log in to view solution →- A. 64 cm
- B. 62 cm
- C. 60 cm
- D. 21.6 cm
Correct answer & explanation hidden
Log in to view solution →- A. 64 cm
- B. 62 cm
- C. 60 cm
- D. 21.6 cm
Correct answer & explanation hidden
Log in to view solution →- A. 1 Ω
- B. 4 Ω
- C. 0.25 Ω
- D. 0.5 Ω
Correct answer & explanation hidden
Log in to view solution →- A. 1 Ω
- B. 4 Ω
- C. 0.25 Ω
- D. 0.5 Ω
Correct answer & explanation hidden
Log in to view solution →- A. 4π × 10^-20 N
- B. 8 × 10^-20 N
- C. 4 × 10^-20 N
- D. 8π × 10^-20 N
Correct answer & explanation hidden
Log in to view solution →- A. [ M ] [ L^0 ] [ T^0 ]
- B. [ M^2 ] [ L^-2 ] [ T^-1 ]
- C. [ M^2 ] [ L^-1 ] [ T^0 ]
- D. [ M ] [ L^-1 ] [ T^-1 ]
Correct answer & explanation hidden
Log in to view solution →- A. β^+, α, β^-
- B. β^-, α, β^+
- C. α, β^-, β^+
- D. α, β^+, β^-
Correct answer & explanation hidden
Log in to view solution →- A. 3n
- B. 4n
- C. n
- D. 2n
Correct answer & explanation hidden
Log in to view solution →- A. 3.14 s
- B. 0.628 s
- C. 0.0628 s
- D. 6.28 s
Correct answer & explanation hidden
Log in to view solution →- A. 804 MeV
- B. 216 MeV
- C. 0.9 MeV
- D. 9.4 MeV
Correct answer & explanation hidden
Log in to view solution →- A. a large aperture contributes to the quality and visibility of the images.
- B. a large area of the objective ensures better light gathering power.
- C. a large aperture provides a better resolution.
- D. all of the above.
Correct answer & explanation hidden
Log in to view solution →- A. 50
- B. 30
- C. 25
- D. 15
Correct answer & explanation hidden
Log in to view solution →- A. I_d = (V_0 / ωC) sin(ωt)
- B. I_d = V_0 ωC sin(ωt)
- C. I_d = V_0 ωC cos(ωt)
- D. I_d = (V_0 / ωC) cos(ωt)
Correct answer & explanation hidden
Log in to view solution →- A. (A) is correct and (B) is incorrect.
- B. (A) is incorrect but (B) is correct.
- C. (A) and (B) both are correct.
- D. (A) and (B) both are incorrect.
Correct answer & explanation hidden
Log in to view solution →- A. B is proportional to r for r < R and B is proportional to 1/r for r > R
- B. B is constant for r < R and B is zero for r > R
- C. B is zero for r < R and B is constant for r > R
- D. B is proportional to r^2 for r < R and B is proportional to 1/r^2 for r > R
Correct answer & explanation hidden
Log in to view solution →- A. 10t/13
- B. 5t/13
- C. 13t/10
- D. 13t/5
Correct answer & explanation hidden
Log in to view solution →- A. 10t/13
- B. 5t/13
- C. 13t/10
- D. 13t/5
Correct answer & explanation hidden
Log in to view solution →- A. [F] [A] [T^-1]
- B. [F] [A^-1] [T]
- C. [F] [A] [T]
- D. [F] [A] [T^2]
Correct answer & explanation hidden
Log in to view solution →- A. [F] [A] [T^-1]
- B. [F] [A^-1] [T]
- C. [F] [A] [T]
- D. [F] [A] [T^2]
Correct answer & explanation hidden
Log in to view solution →- A. 12.3 kW
- B. 7.0 kW
- C. 10.2 kW
- D. 8.1 kW
Correct answer & explanation hidden
Log in to view solution →- A. (A)-(Q), (B)-(P), (C)-(S), (D)-(R)
- B. (A)-(R), (B)-(Q), (C)-(P), (D)-(S)
- C. (A)-(R), (B)-(P), (C)-(S), (D)-(Q)
- D. (A)-(Q), (B)-(R), (C)-(S), (D)-(P)
Correct answer & explanation hidden
Log in to view solution →- A. (R1/R2)
- B. (R2/R1)^2
- C. (R1/R2)^2
- D. (R2/R1)
Correct answer & explanation hidden
Log in to view solution →- A. 2 A
- B. 4 A
- C. 0.2 A
- D. 0.4 A
Correct answer & explanation hidden
Log in to view solution →- A. 20√2 m/s, 0
- B. 20√2 m/s, 10 m/s²
- C. 20 m/s, 5 m/s²
- D. 20 m/s, 0
Correct answer & explanation hidden
Log in to view solution →- A. 46 rad/s and 54 rad/s
- B. 42 rad/s and 58 rad/s
- C. 25 rad/s and 75 rad/s
- D. 50 rad/s and 25 rad/s
Correct answer & explanation hidden
Log in to view solution →- A. 1520 V
- B. 1980 V
- C. 660 V
- D. 1320 V
Correct answer & explanation hidden
Log in to view solution →- A. 1520 V
- B. 1980 V
- C. 660 V
- D. 1320 V
Correct answer & explanation hidden
Log in to view solution →- A. 2.1 kg m/s
- B. 1.4 kg m/s
- C. 0 kg m/s
- D. 4.2 kg m/s
Correct answer & explanation hidden
Log in to view solution →- A. 2.1 kg m/s
- B. 1.4 kg m/s
- C. 0 kg m/s
- D. 4.2 kg m/s
Correct answer & explanation hidden
Log in to view solution →- A. 1/6 kg
- B. 1/12 kg
- C. 1/2 kg
- D. 1/3 kg
Correct answer & explanation hidden
Log in to view solution →- A. 3 Ia^2 and 4 Ia^2
- B. 4 Ia^2 and 3 Ia^2
- C. 3 Ia^2 and 3 Ia^2
- D. 3 Ia^2 and Ia^2
Correct answer & explanation hidden
Log in to view solution →- A. R1/R2
- B. R2^2/R1
- C. R1^2/R2
- D. R2/R1
Correct answer & explanation hidden
Log in to view solution →- A. lanthanoid contraction
- B. having similar chemical properties
- C. belonging to same group
- D. diagonal relationship
Correct answer & explanation hidden
Log in to view solution →- A. Starch solution
- B. Urea solution
- C. NaCl solution
- D. Glucose solution
Correct answer & explanation hidden
Log in to view solution →- A. (a)-(iii), (b)-(i), (c)-(iv), (d)-(ii)
- B. (a)-(iv), (b)-(iii), (c)-(ii), (d)-(i)
- C. (a)-(iv), (b)-(iii), (c)-(i), (d)-(ii)
- D. (a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)
Correct answer & explanation hidden
Log in to view solution →- A. 7.75
- B. 6.25
- C. 8.50
- D. 5.50
Correct answer & explanation hidden
Log in to view solution →- A. 7.75
- B. 6.25
- C. 8.50
- D. 5.50
Correct answer & explanation hidden
Log in to view solution →- A. upto 1900 K
- B. upto 5000 K
- C. upto 1200 K
- D. upto 2200 K
Correct answer & explanation hidden
Log in to view solution →- A. Statement I is correct but Statement II is false.
- B. Statement I is incorrect but Statement II is true.
- C. Both Statement I and Statement II are true.
- D. Both Statement I and Statement II are false.
Correct answer & explanation hidden
Log in to view solution →- A. Statement I is correct but Statement II is false.
- B. Statement I is incorrect but Statement II is true.
- C. Both Statement I and Statement II are true.
- D. Both Statement I and Statement II are false.
Correct answer & explanation hidden
Log in to view solution →- A. Novolac
- B. Dacron
- C. Teflon
- D. Nylon-66
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Log in to view solution →- A. Novolac
- B. Dacron
- C. Teflon
- D. Nylon-66
Correct answer & explanation hidden
Log in to view solution →- A. sp2 and 6
- B. sp2 and 8
- C. sp3 and 4
- D. sp3 and 6
Correct answer & explanation hidden
Log in to view solution →- A. sp2 and 6
- B. sp2 and 8
- C. sp3 and 4
- D. sp3 and 6
Correct answer & explanation hidden
Log in to view solution →- A. Fe + 2HCl → FeCl2 + H2
- B. 2Pb(NO3)2 → 2PbO + 4NO2 + O2
- C. 2KClO3 → 2KCl + 3O2
- D. Cr2O3 + 2Al → Al2O3 + 2Cr
Correct answer & explanation hidden
Log in to view solution →- A. Gamma (γ)
- B. Neutron (n)
- C. Beta (β-)
- D. Alpha (α)
Correct answer & explanation hidden
Log in to view solution →- A. CH3
- B. CH4
- C. CH
- D. CH2
Correct answer & explanation hidden
Log in to view solution →- A. 60°
- B. 0°
- C. 120°
- D. 180°
Correct answer & explanation hidden
Log in to view solution →- A. Statement I is correct but Statement II is false.
- B. Statement I is incorrect but Statement II is true.
- C. Both Statement I and Statement II are true.
- D. Both Statement I and Statement II are false.
Correct answer & explanation hidden
Log in to view solution →- A. Vitamin B1
- B. Vitamin B2
- C. Vitamin B12
- D. Vitamin B6
Correct answer & explanation hidden
Log in to view solution →- A. Bidentate ligand with two “N” donor atoms
- B. Tridentate ligand with three “N” donor atoms
- C. Hexadentate ligand with four “O” and two “N” donor atoms
- D. Unidentate ligand
Correct answer & explanation hidden
Log in to view solution →- A. 2192 m
- B. 21.92 cm
- C. 219.3 m
- D. 219.2 m
Correct answer & explanation hidden
Log in to view solution →- A. 698.28 S cm^2 mol^-1
- B. 540.48 S cm^2 mol^-1
- C. 201.28 S cm^2 mol^-1
- D. 390.71 S cm^2 mol^-1
Correct answer & explanation hidden
Log in to view solution →- A. Distillation
- B. Zone refining
- C. Electrolysis
- D. Chromatography
Correct answer & explanation hidden
Log in to view solution →- A. pentan-3-ol
- B. 2-methyl butan-2-ol
- C. 2-methyl propan-2-ol
- D. pentan-2-ol
Correct answer & explanation hidden
Log in to view solution →- A. P2 > P3 > P1
- B. P3 > P1 > P2
- C. P2 > P1 > P3
- D. P1 > P2 > P3
Correct answer & explanation hidden
Log in to view solution →- A. P2 > P3 > P1
- B. P3 > P1 > P2
- C. P2 > P1 > P3
- D. P1 > P2 > P3
Correct answer & explanation hidden
Log in to view solution →- A. C3H6O
- B. C4H10O
- C. C5H12
- D. C3H8O
Correct answer & explanation hidden
Log in to view solution →- A. C3H6O
- B. C4H10O
- C. C5H12
- D. C3H8O
Correct answer & explanation hidden
Log in to view solution →- A. Noble gases have weak dispersion forces.
- B. Noble gases have large positive values of electron gain enthalpy.
- C. Noble gases are sparingly soluble in water.
- D. Noble gases have very high melting and boiling points.
Correct answer & explanation hidden
Log in to view solution →- A. 2, 1
- B. 12, 6
- C. 8, 4
- D. 6, 12
Correct answer & explanation hidden
Log in to view solution →- A. Magnesium chloride
- B. Beryllium chloride
- C. Calcium chloride
- D. Strontium chloride
Correct answer & explanation hidden
Log in to view solution →- A. CP = RCV
- B. CV = RCP
- C. CP / CV = R
- D. CP - CV = R
Correct answer & explanation hidden
Log in to view solution →- A. CH3−F < CH3−Cl > CH3−Br > CH3−I
- B. CH3−Cl > CH3−F > CH3−Br > CH3−I
- C. CH3−F < CH3−Cl < CH3−Br < CH3−I
- D. CH3−F > CH3−Cl > CH3−Br > CH3−I
Correct answer & explanation hidden
Log in to view solution →- A. Hofmann Rule
- B. Huckel’s Rule
- C. Saytzeff’s Rule
- D. Hund’s Rule
Correct answer & explanation hidden
Log in to view solution →- A. 2
- B. 3
- C. 7
- D. 5
Correct answer & explanation hidden
Log in to view solution →- A. Dimer and Linear, respectively
- B. Chain in both
- C. Chain and dimer, respectively
- D. Linear in both
Correct answer & explanation hidden
Log in to view solution →- A. Lanthanoids are good conductors of heat and electricity.
- B. Actinoids are highly reactive metals, especially when finely divided.
- C. Actinoid contraction is greater for element to element than Lanthanoid contraction.
- D. Most of the trivalent Lanthanoid ions are colorless in the solid state.
Correct answer & explanation hidden
Log in to view solution →- A. 336 mm of Hg
- B. 350 mm of Hg
- C. 160 mm of Hg
- D. 168 mm of Hg
Correct answer & explanation hidden
Log in to view solution →- A. CaO
- B. DIBAL-H
- C. B2H6
- D. Red Phosphorus
Correct answer & explanation hidden
Log in to view solution →- A. NH3 < PH3 < AsH3 < SbH3 : Increasing acidic character
- B. CO2 < SiO2 < SnO2 < PbO2 : Increasing oxidizing power
- C. HF < HCl < HBr < HI : Increasing acidic strength
- D. H2O < H2S < H2Se < H2Te : Increasing pKa values
Correct answer & explanation hidden
Log in to view solution →- A. NH3 < PH3 < AsH3 < SbH3 : Increasing acidic character
- B. CO2 < SiO2 < SnO2 < PbO2 : Increasing oxidizing power
- C. HF < HCl < HBr < HI : Increasing acidic strength
- D. H2O < H2S < H2Se < H2Te : Increasing pKa values
Correct answer & explanation hidden
Log in to view solution →- A. SbCl5
- B. NO2
- C. POCl3
- D. CH2O
Correct answer & explanation hidden
Log in to view solution →- A. SbCl5
- B. NO2
- C. POCl3
- D. CH2O
Correct answer & explanation hidden
Log in to view solution →- A. 25.18
- B. 26.02
- C. 2.518
- D. 2.602
Correct answer & explanation hidden
Log in to view solution →- A. (a)-(i), (b)-(iii), (c)-(iv), (d)-(ii)
- B. (a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)
- C. (a)-(iv), (b)-(ii), (c)-(i), (d)-(iii)
- D. (a)-(ii), (b)-(iv), (c)-(iii), (d)-(i)
Correct answer & explanation hidden
Log in to view solution →- A. 166 kJ mol−1
- B. −83 kJ mol−1
- C. 41.5 kJ mol−1
- D. 83.0 kJ mol−1
Correct answer & explanation hidden
Log in to view solution →- A. 1.75×10−5 mol L−1
- B. 2.50×10−5 mol L−1
- C. 1.75×10−4 mol L−1
- D. 2.50×10−4 mol L−1
Correct answer & explanation hidden
Log in to view solution →- A. ΔU=0, ΔStotal ≠ 0
- B. ΔU ≠ 0, ΔStotal=0
- C. ΔU=0, ΔStotal=0
- D. ΔU ≠ 0, ΔStotal ≠ 0
Correct answer & explanation hidden
Log in to view solution →- A. Mn2+, Fe3+
- B. Fe2+, Mn2+
- C. O2−, F−
- D. Na+, Mg2+
Correct answer & explanation hidden
Log in to view solution →- A. Dark red bands
- B. Bright blue bands
- C. Yellow bands
- D. Bright orange bands
Correct answer & explanation hidden
Log in to view solution →- A. Marchantia polymorpha
- B. Cycas circinalis
- C. Carica papaya
- D. Chara
Correct answer & explanation hidden
Log in to view solution →- A. The perinuclear space forms a barrier between the materials present inside the nucleus and that of the cytoplasm.
- B. Nuclear pores act as passages for proteins and RNA molecules in both directions between nucleus and cytoplasm.
- C. Mature sieve tube elements possess a conspicuous nucleus and usual cytoplasmic organelles.
- D. Microbodies are present both in plant and animal cells.
Correct answer & explanation hidden
Log in to view solution →- A. The perinuclear space forms a barrier between the materials present inside the nucleus and that of the cytoplasm.
- B. Nuclear pores act as passages for proteins and RNA molecules in both directions between nucleus and cytoplasm.
- C. Mature sieve tube elements possess a conspicuous nucleus and usual cytoplasmic organelles.
- D. Microbodies are present both in plant and animal cells.
Correct answer & explanation hidden
Log in to view solution →- A. Chasmogamy
- B. Cleistogamy
- C. Xenogamy
- D. Geitonogamy
Correct answer & explanation hidden
Log in to view solution →- A. Chasmogamy
- B. Cleistogamy
- C. Xenogamy
- D. Geitonogamy
Correct answer & explanation hidden
Log in to view solution →- A. Succinic acid
- B. Phosphoglyceric acid
- C. Pyruvic acid
- D. Oxaloacetic acid
Correct answer & explanation hidden
Log in to view solution →- A. Succinic acid
- B. Phosphoglyceric acid
- C. Pyruvic acid
- D. Oxaloacetic acid
Correct answer & explanation hidden
Log in to view solution →- A. Pyramid of energy is always upright.
- B. Pyramid of numbers in a grassland ecosystem is upright.
- C. Pyramid of biomass in sea is generally inverted.
- D. Pyramid of biomass in sea is generally upright.
Correct answer & explanation hidden
Log in to view solution →- A. Pyramid of energy is always upright.
- B. Pyramid of numbers in a grassland ecosystem is upright.
- C. Pyramid of biomass in sea is generally inverted.
- D. Pyramid of biomass in sea is generally upright.
Correct answer & explanation hidden
Log in to view solution →- A. Red algae
- B. Blue-green algae
- C. Green algae
- D. Brown algae
Correct answer & explanation hidden
Log in to view solution →- A. Molecular diagnosis
- B. Safety testing
- C. Biopiracy
- D. Gene therapy
Correct answer & explanation hidden
Log in to view solution →- A. Plasticity
- B. Maturity
- C. Elasticity
- D. Flexibility
Correct answer & explanation hidden
Log in to view solution →- A. Mutualism
- B. Predation
- C. Resource partitioning
- D. Competitive release
Correct answer & explanation hidden
Log in to view solution →- A. 2, 4-D
- B. IBA
- C. IAA
- D. NAA
Correct answer & explanation hidden
Log in to view solution →- A. Mutation
- B. Genetic drift
- C. Natural selection
- D. Genetic recombination
Correct answer & explanation hidden
Log in to view solution →- A. Standing state
- B. Standing crop
- C. Climax
- D. Climax community
Correct answer & explanation hidden
Log in to view solution →- A. Homosporous
- B. Heterosporous
- C. Homosorus
- D. Heterosorus
Correct answer & explanation hidden
Log in to view solution →- A. Anaphase II
- B. Telophase II
- C. Metaphase I
- D. Metaphase II
Correct answer & explanation hidden
Log in to view solution →- A. Some Gymnosperms
- B. Some Liverworts
- C. Mosses
- D. Pteridophytes
Correct answer & explanation hidden
Log in to view solution →- A. Extension, Denaturation, Annealing
- B. Annealing, Denaturation, Extension
- C. Denaturation, Annealing, Extension
- D. Denaturation, Extension, Annealing
Correct answer & explanation hidden
Log in to view solution →- A. (a)-Replication; (b)-Transcription; (c)-Translation; (d)-Protein
- B. (a)-Transduction; (b)-Translation; (c)-Replication; (d)-Protein
- C. (a)-Replication; (b)-Transcription; (c)-Transduction; (d)-Protein
- D. (a)-Translation; (b)-Replication; (c)-Transcription; (d)-Transduction
Correct answer & explanation hidden
Log in to view solution →- A. Pea
- B. China rose and citrus
- C. China rose
- D. Citrus
Correct answer & explanation hidden
Log in to view solution →- A. Pea
- B. China rose and citrus
- C. China rose
- D. Citrus
Correct answer & explanation hidden
Log in to view solution →- A. Species A (-) ; Species B (-)
- B. Species A (-) ; Species B (0)
- C. Species A (+) ; Species B (0)
- D. Species A (-) ; Species B (+)
Correct answer & explanation hidden
Log in to view solution →- A. Species A (−) ; Species B (−)
- B. Species A (+) ; Species B (0)
- C. Species A (−) ; Species B (0)
- D. Species A (+) ; Species B (+)
Correct answer & explanation hidden
Log in to view solution →- A. (1)(iii)(i)(iv)(ii)
- B. (2)(ii)(i)(iv)(iii)
- C. (3)(ii)(iv)(i)(iii)
- D. (4)(iv)(iii)(ii)(i)
Correct answer & explanation hidden
Log in to view solution →- A. Environment factor
- B. Respiration losses
- C. Radiant energy
- D. Retardation factor
Correct answer & explanation hidden
Log in to view solution →- A. Environment factor
- B. Respiration losses
- C. Radiant energy
- D. Retardation factor
Correct answer & explanation hidden
Log in to view solution →- A. Axillary bud
- B. Leaf
- C. Shoot apex
- D. Stem
Correct answer & explanation hidden
Log in to view solution →- A. Purification of isolated protein
- B. Detection of gene mutation
- C. Molecular diagnosis
- D. Gene amplification
Correct answer & explanation hidden
Log in to view solution →- A. Histones
- B. Polysaccharides
- C. RNA
- D. DNA
Correct answer & explanation hidden
Log in to view solution →- A. Volvox
- B. Ulothrix
- C. Ectocarpus
- D. Gracilaria
Correct answer & explanation hidden
Log in to view solution →- A. Gamma rays
- B. Zeatin
- C. Kinetin
- D. Infrared rays
Correct answer & explanation hidden
Log in to view solution →- A. 7-nucleate and 7-celled
- B. 8-nucleate and 8-celled
- C. 8-nucleate and 7-celled
- D. 7-nucleate and 8-celled
Correct answer & explanation hidden
Log in to view solution →- A. Vinblastin, curcumin
- B. Rubber, gums
- C. Morphine, codeine
- D. Amino acids, glucose
Correct answer & explanation hidden
Log in to view solution →- A. Punnett square
- B. Net square
- C. Bullet square
- D. Punch square
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Log in to view solution →- A. Sub-metacentric
- B. Acrocentric
- C. Metacentric
- D. Telocentric
Correct answer & explanation hidden
Log in to view solution →- A. it will lead to lysis of host cell.
- B. it will be able to produce a novel protein with dual ability.
- C. it will not be able to confer ampicillin resistance to the host cell.
- D. the transformed cells will have the ability to resist ampicillin as well as produce β-galactoside.
Correct answer & explanation hidden
Log in to view solution →- A. Transcribes precursor of mRNA
- B. Transcribes only snRNAs
- C. Transcribes rRNAs (28S, 18S and 5.8S)
- D. Transcribes tRNA, 5s rRNA and snRNA
Correct answer & explanation hidden
Log in to view solution →- A. The base of natural logarithms
- B. The base of geometric logarithms
- C. The base of number logarithms
- D. The base of exponential logarithms
Correct answer & explanation hidden
Log in to view solution →- A. Grana lamellae have both PS I and PS II.
- B. Cyclic photophosphorylation involves both PS I and PS II.
- C. Both ATP and NADPH are synthesized during non-cyclic photophosphorylation.
- D. Stroma lamellae have PS I only and lack NADP reductase.
Correct answer & explanation hidden
Log in to view solution →- A. Grana lamellae have both PS I and PS II.
- B. Cyclic photophosphorylation involves both PS I and PS II.
- C. Both ATP and NADPH + H+ are synthesized during non-cyclic photophosphorylation.
- D. Stroma lamellae have PS I only and lack NADP reductase.
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Log in to view solution →- A. (1)(iii)(i)(iv)(ii)
- B. (2)(iv)(iii)(ii)(i)
- C. (3)(ii)(iv)(i)(iii)
- D. (4)(i)(ii)(iii)(iv)
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Log in to view solution →- A. (1)(ii)(i)(iv)(iii)
- B. (2)(iv)(iii)(i)(ii)
- C. (3)(iv)(i)(ii)(iii)
- D. (4)(i)(iv)(iii)(ii)
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Log in to view solution →- A. Organisms that depend on living plants are called saprophytes.
- B. Some of the organisms can fix atmospheric nitrogen in specialized cells called sheath cells.
- C. Fusion of two cells is called Karyogamy.
- D. Fusion of protoplasms between two motile or non-motile gametes is called plasmogamy.
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Log in to view solution →- A. Poaceae ; Solanaceae
- B. Rosaceae ; Leguminosae
- C. Poaceae ; Rosaceae
- D. Poaceae ; Leguminosae
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Log in to view solution →- A. ATP is synthesized through complex V.
- B. Oxidation-reduction reactions produce proton gradient in respiration.
- C. During aerobic respiration, role of oxygen is limited to the terminal stage.
- D. In ETC (Electron Transport Chain), one molecule of NADH+H+ gives rise to 2 ATP molecules, and one FADH2 gives rise to 3 ATP molecules.
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Log in to view solution →- A. (1)(iv)(i)(ii)(iii)
- B. (2)(ii)(iv)(iii)(i)
- C. (3)(iii)(ii)(i)(iv)
- D. (4)(iv)(ii)(iii)(i)
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Log in to view solution →- A. The coding strand in a transcription unit is copied to an mRNA.
- B. Split gene arrangement is characteristic of prokaryotes.
- C. In capping, methyl guanosine triphosphate is added to the 3' end of hnRNA.
- D. RNA polymerase binds with Rho factor to terminate the process of transcription in bacteria.
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Log in to view solution →- A. Single nucleotides
- B. Polymorphic DNA
- C. Satellite DNA
- D. Repetitive DNA
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Log in to view solution →- A. The cells of bone marrow
- B. Juxtaglomerular cells of the kidney
- C. Alpha cells of pancreas
- D. The cells of rostral adenohypophysis
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Log in to view solution →- A. The cells of bone marrow
- B. Juxtaglomerular cells of the kidney
- C. Alpha cells of pancreas
- D. The cells of rostral adenohypophysis
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Log in to view solution →- A. Cockroach
- B. House fly
- C. Fire fly
- D. Grasshopper
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Log in to view solution →- A. (1)(ii)(iii)(iv)(i)
- B. (2)(i)(iv)(iii)(ii)
- C. (3)(iii)(ii)(i)(iv)
- D. (4)(i)(ii)(iii)(iv)
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Log in to view solution →- A. (1) (ii)(iii)(iv)(i)
- B. (2) (i)(iv)(iii)(ii)
- C. (3) (ii)(iii)(i)(iv)
- D. (4) (iv)(i)(iii)(ii)
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Log in to view solution →- A. ELISA Technique
- B. Hybridization Technique
- C. Western Blotting Technique
- D. Southern Blotting Technique
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Log in to view solution →- A. Cu 7
- B. Multiload 375
- C. CuT
- D. LNG 20
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Log in to view solution →- A. Diakinesis
- B. Pachytene
- C. Leptotene
- D. Zygotene
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Log in to view solution →- A. (a), (c) and (d) only
- B. (a) and (d) only
- C. (b) and (d) only
- D. (b) and (c) only
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Log in to view solution →- A. Macropus
- B. Ornithorhynchus
- C. Neophron
- D. Hemidactylus
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Log in to view solution →- A. Presence of antibodies, anti-A and anti-B, on RBCs
- B. Absence of antibodies, anti-A and anti-B, in plasma
- C. Absence of antigens A and B on the surface of RBCs
- D. Absence of antigens A and B in plasma
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Log in to view solution →- A. Epinephrine
- B. Thrombokinase
- C. Thrombin
- D. Renin
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Log in to view solution →- A. Communication among the cells is performed by intercalated discs
- B. These muscles are present in the wall of blood vessels
- C. These muscle have no striations
- D. They are involuntary muscles
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Log in to view solution →- A. (1) (iii)(iv)(ii)(i)
- B. (2) (iv)(i)(ii)(iii)
- C. (3) (iv)(iii)(i)(ii)
- D. (4) (iii)(iv)(i)(ii)
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Log in to view solution →- A. Palindromic Nucleotide sequences
- B. Poly(A) tail sequences
- C. Degenerate primer sequence
- D. Okazaki sequences
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Log in to view solution →- A. DNA Ligase
- B. DNase
- C. DNA dependent DNA polymerase
- D. DNA dependent RNA polymerase
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Log in to view solution →- A. Lectins - Concanavalin A
- B. Drugs - Ricin
- C. Alkaloids - Codeine
- D. Toxin - Abrin
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Log in to view solution →- A. Lectins - Concanavalin A
- B. Drugs - Ricin
- C. Alkaloids - Codeine
- D. Toxin - Abrin
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Log in to view solution →- A. pO2 = 95 and pCO2 = 40
- B. pO2 = 159 and pCO2 = 0.3
- C. pO2 = 104 and pCO2 = 40
- D. pO2 = 40 and pCO2 = 45
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Log in to view solution →- A. pO2 = 95 and pCO2 = 40
- B. pO2 = 159 and pCO2 = 0.3
- C. pO2 = 104 and pCO2 = 40
- D. pO2 = 40 and pCO2 = 45
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Log in to view solution →- A. Golgi complex, Mitochondria, Ribosomes and Lysosomes
- B. Golgi complex, Endoplasmic reticulum, Mitochondria and Lysosomes
- C. Endoplasmic reticulum, Mitochondria, Ribosomes and Lysosomes
- D. Endoplasmic reticulum, Golgi complex, Lysosomes and Vacuoles
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Log in to view solution →- A. Golgi complex, Mitochondria, Ribosomes and Lysosomes
- B. Golgi complex, Endoplasmic reticulum, Mitochondria and Lysosomes
- C. Endoplasmic reticulum, Mitochondria, Ribosomes and Lysosomes
- D. Endoplasmic reticulum, Golgi complex, Lysosomes and Vacuoles
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Log in to view solution →- A. T : 30 ; G : 20 ; C : 20
- B. T : 20 ; G : 25 ; C : 25
- C. T : 20 ; G : 30 ; C : 20
- D. T : 20 ; G : 20 ; C : 30
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Log in to view solution →- A. T : 30 ; G : 20 ; C : 20
- B. T : 20 ; G : 25 ; C : 25
- C. T : 20 ; G : 30 ; C : 20
- D. T : 20 ; G : 20 ; C : 30
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Log in to view solution →- A. Ozone
- B. Troposphere
- C. CFCs
- D. Stratosphere
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Log in to view solution →- A. Ozone
- B. Troposphere
- C. CFCs
- D. Stratosphere
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Log in to view solution →- A. (a), (d) and (e) are correct
- B. (b), (c) and (e) are correct
- C. (c), (d) and (e) are correct
- D. (a), (b) and (c) are correct
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Log in to view solution →- A. Myasthenia gravis
- B. Gout
- C. Arthritis
- D. Muscular dystrophy
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Log in to view solution →- A. (ii)(iv)(iii)(i)
- B. (iii)(i)(iv)(ii)
- C. (iv)(ii)(i)(iii)
- D. (i)(iii)(ii)(iv)
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Log in to view solution →- A. Metaphase
- B. G2 phase
- C. S-phase
- D. Prophase
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Log in to view solution →- A. Perivitelline space
- B. Zona pellucida
- C. Corona radiata
- D. Vitelline membrane
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Log in to view solution →- A. In females, 7th-9th sterna together form a genital pouch.
- B. 10th abdominal segment in both sexes, bears a pair of anal cerci.
- C. A ring of gastric caeca is present at the junction of midgut and hind gut.
- D. Hypopharynx lies within the cavity enclosed by the mouth parts.
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Log in to view solution →- A. (ii)(iii)(i)(iv)
- B. (iv)(ii)(i)(iii)
- C. (iii)(i)(iv)(ii)
- D. (i)(ii)(iii)(iv)
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Log in to view solution →- A. (b) and (c) only
- B. (a) and (c) only
- C. (a), (b) and (c) only
- D. (b), (c) and (d) only
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Log in to view solution →- A. rRNA
- B. siRNA
- C. mRNA
- D. tRNA
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Log in to view solution →- A. High pO2, high pCO2, less H+, higher temperature
- B. Low pO2, low pCO2, more H+, higher temperature
- C. High pO2, low pCO2, less H+, lower temperature
- D. Low pO2, high pCO2, more H+, higher temperature
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