- A. 4 v
- B. v
- C. 2 v
- D. 3 v
Correct answer & explanation hidden
Log in to view solution →- A. 4v
- B. v
- C. 2v
- D. 3v
Correct answer & explanation hidden
Log in to view solution →- A. 5t/13
- B. 13t/10
- C. 13t/5
- D. 10t/13
Correct answer & explanation hidden
Log in to view solution →- A. 5t/13
- B. 13t/10
- C. 13t/5
- D. 10t/13
Correct answer & explanation hidden
Log in to view solution →- A. having a permanent electric dipole moment.
- B. having zero dipole moment.
- C. acquire a dipole moment only in the presence of electric field due to displacement of charges.
- D. acquire a dipole moment only when magnetic field is absent.
Correct answer & explanation hidden
Log in to view solution →- A. having a permanent electric dipole moment.
- B. having zero dipole moment.
- C. acquire a dipole moment only in the presence of electric field due to displacement of charges.
- D. acquire a dipole moment only when magnetic field is absent.
Correct answer & explanation hidden
Log in to view solution →- A. (1/2)ε0 E² Ad
- B. (1/2)ε0 E²
- C. ε0 EAd
- D. ε0 E² Ad
Correct answer & explanation hidden
Log in to view solution →- A. No current will flow in p-type, current will only flow in n-type.
- B. current in n-type = current in p-type.
- C. current in p-type > current in n-type.
- D. current in n-type > current in p-type.
Correct answer & explanation hidden
Log in to view solution →- A. R2²/R1²
- B. R1/R2
- C. R2/R1
- D. R1²/R2²
Correct answer & explanation hidden
Log in to view solution →- A. (A) is incorrect but (B) is correct.
- B. (A) and (B) both are correct.
- C. (A) and (B) both are incorrect.
- D. (A) is correct and (B) is incorrect.
Correct answer & explanation hidden
Log in to view solution →- A. (A) is incorrect but (B) is correct.
- B. (A) and (B) both are correct.
- C. (A) and (B) both are incorrect.
- D. (A) is correct and (B) is incorrect.
Correct answer & explanation hidden
Log in to view solution →- A. 62 cm
- B. 60 cm
- C. 21.6 cm
- D. 64 cm
Correct answer & explanation hidden
Log in to view solution →- A. 62 cm
- B. 60 cm
- C. 21.6 cm
- D. 64 cm
Correct answer & explanation hidden
Log in to view solution →- A. Id = V0ωC sinωt
- B. Id = V0ωC cosωt
- C. Id = (V0 / ωC) cosωt
- D. Id = (V0 / ωC) sinωt
Correct answer & explanation hidden
Log in to view solution →- A. 10¹⁵
- B. 10¹⁸
- C. 10¹⁷
- D. 10¹⁶
Correct answer & explanation hidden
Log in to view solution →- A. (2n) / (2n - 1)
- B. (2n - 1) / (2n)
- C. (2n - 1) / (2n + 1)
- D. (2n + 1) / (2n - 1)
Correct answer & explanation hidden
Log in to view solution →- A. 0.052 cm
- B. 0.52 cm
- C. 0.026 cm
- D. 0.26 cm
Correct answer & explanation hidden
Log in to view solution →- A. a large aperture contributes to the quality and visibility of the images.
- B. a large area of the objective ensures better light gathering power.
- C. a large aperture provides a better resolution.
- D. all of the above.
Correct answer & explanation hidden
Log in to view solution →- A. 4n
- B. n
- C. 2n
- D. 3n
Correct answer & explanation hidden
Log in to view solution →- A. 2 / 3√2
- B. 1/2
- C. 1 / 2√2
- D. 2/3
Correct answer & explanation hidden
Log in to view solution →- A. [F] [A^-1] [T]
- B. [F] [A] [T]
- C. [F] [A] [T^2]
- D. [F] [A] [T^-1]
Correct answer & explanation hidden
Log in to view solution →- A. 7.0 kW
- B. 10.2 kW
- C. 8.1 kW
- D. 12.3 kW
Correct answer & explanation hidden
Log in to view solution →- A. 7.0 kW
- B. 10.2 kW
- C. 8.1 kW
- D. 12.3 kW
Correct answer & explanation hidden
Log in to view solution →- A. 4 Ω
- B. 0.25 Ω
- C. 0.5 Ω
- D. 1 Ω
Correct answer & explanation hidden
Log in to view solution →- A. 4 Ω
- B. 0.25 Ω
- C. 0.5 Ω
- D. 1 Ω
Correct answer & explanation hidden
Log in to view solution →- A. (A)-(R), (B)-(Q), (C)-(S), (D)-(P)
- B. (A)-(R), (B)-(S), (C)-(P), (D)-(Q)
- C. (A)-(R), (B)-(S), (C)-(Q), (D)-(P)
- D. (A)-(R), (B)-(P), (C)-(S), (D)-(Q)
Correct answer & explanation hidden
Log in to view solution →- A. 216 MeV
- B. 0.9 MeV
- C. 9.4 MeV
- D. 804 MeV
Correct answer & explanation hidden
Log in to view solution →- A. 30
- B. 25
- C. 15
- D. 50
Correct answer & explanation hidden
Log in to view solution →- A. 0.628 s
- B. 0.0628 s
- C. 6.28 s
- D. 3.14 s
Correct answer & explanation hidden
Log in to view solution →- A. [M^2] [L^-2] [T^-1]
- B. [M^2] [L^-1] [T^0]
- C. [M] [L^-1] [T^-1]
- D. [M] [L^0] [T^0]
Correct answer & explanation hidden
Log in to view solution →- A. 1980 V
- B. 660 V
- C. 1320 V
- D. 1520 V
Correct answer & explanation hidden
Log in to view solution →- A. (k^2 * R) / (1 - k^2)
- B. (R * k^2) / (1 - k)
- C. (R * k^2) / (1 + k)
- D. (R * k) / (1 + k)
Correct answer & explanation hidden
Log in to view solution →- A. 4 A
- B. 0.2 A
- C. 0.4 A
- D. 2 A
Correct answer & explanation hidden
Log in to view solution →- A. 1.4 kg m/s
- B. 0 kg m/s
- C. 4.2 kg m/s
- D. 2.1 kg m/s
Correct answer & explanation hidden
Log in to view solution →- A. 20 sqrt(2) m/s, 10 m/s^2
- B. 20 m/s, 5 m/s^2
- C. 20 m/s, 0
- D. 20 sqrt(2) m/s, 0
Correct answer & explanation hidden
Log in to view solution →- A. 20 cm from the plane mirror, it would be a virtual image.
- B. 20 cm from the lens, it would be a real image.
- C. 30 cm from the lens, it would be a real image.
- D. 30 cm from the plane mirror, it would be a virtual image.
Correct answer & explanation hidden
Log in to view solution →- A. 6i - 6j + 8k
- B. 8i - 8j - 6k
- C. 6i - 6j - 8k
- D. 8i + 8j - 6k
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Log in to view solution →- A. 42 rad/s and 58 rad/s
- B. 25 rad/s and 75 rad/s
- C. 50 rad/s and 25 rad/s
- D. 46 rad/s and 54 rad/s
Correct answer & explanation hidden
Log in to view solution →- A. 0°
- B. 120°
- C. 180°
- D. 60°
Correct answer & explanation hidden
Log in to view solution →- A. Chain in both
- B. Chain and dimer, respectively
- C. Linear in both
- D. Dimer and Linear, respectively
Correct answer & explanation hidden
Log in to view solution →- A. 540.48 S cm^2 mol^-1
- B. 201.28 S cm^2 mol^-1
- C. 390.71 S cm^2 mol^-1
- D. 698.28 S cm^2 mol^-1
Correct answer & explanation hidden
Log in to view solution →- A. 12, 6
- B. 8, 4
- C. 6, 12
- D. 2, 1
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Log in to view solution →- A. 12, 6
- B. 8, 4
- C. 6, 12
- D. 2, 1
Correct answer & explanation hidden
Log in to view solution →- A. Neutron (n)
- B. Beta (β-)
- C. Alpha (α)
- D. Gamma (γ)
Correct answer & explanation hidden
Log in to view solution →- A. Neutron (n)
- B. Beta (β-)
- C. Alpha (α)
- D. Gamma (γ)
Correct answer & explanation hidden
Log in to view solution →- A. CH4
- B. CH
- C. CH2
- D. CH3
Correct answer & explanation hidden
Log in to view solution →- A. CH4
- B. CH
- C. CH2
- D. CH3
Correct answer & explanation hidden
Log in to view solution →- A. 2-methyl butan-2-ol
- B. 2-methyl propan-2-ol
- C. pentan-2-ol
- D. pentan-3-ol
Correct answer & explanation hidden
Log in to view solution →- A. (a)-(iv), (b)-(iii), (c)-(ii), (d)-(i)
- B. (a)-(iv), (b)-(iii), (c)-(i), (d)-(ii)
- C. (a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)
- D. (a)-(iii), (b)-(i), (c)-(iv), (d)-(ii)
Correct answer & explanation hidden
Log in to view solution →- A. upto 5000 K
- B. upto 1200 K
- C. upto 2200 K
- D. upto 1900 K
Correct answer & explanation hidden
Log in to view solution →- A. CV=RCP
- B. CP/CV=R
- C. CP−CV=R
- D. CP=RCV
Correct answer & explanation hidden
Log in to view solution →- A. Statement I is incorrect but Statement II is true.
- B. Both Statement I and Statement II are true.
- C. Both Statement I and Statement II are false.
- D. Statement I is correct but Statement II is false.
Correct answer & explanation hidden
Log in to view solution →- A. Urea solution
- B. NaCl solution
- C. Glucose solution
- D. Starch solution
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Log in to view solution →- A. 3
- B. 7
- C. 5
- D. 2
Correct answer & explanation hidden
Log in to view solution →- A. 2Pb(NO3)2 → 2PbO + 4NO2 + O2
- B. 2KClO3 → 2KCl + 3O2
- C. Cr2O3 + 2Al → Al2O3 + 2Cr
- D. Fe + 2HCl → FeCl2 + H2
Correct answer & explanation hidden
Log in to view solution →- A. 6.25
- B. 8.50
- C. 5.50
- D. 7.75
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Log in to view solution →- A. Huckel’s Rule
- B. Saytzeff’s Rule
- C. Hund’s Rule
- D. Hofmann Rule
Correct answer & explanation hidden
Log in to view solution →- A. Dacron
- B. Teflon
- C. Nylon-66
- D. Novolac
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Log in to view solution →- A. Vitamin B2
- B. Vitamin B12
- C. Vitamin B6
- D. Vitamin B1
Correct answer & explanation hidden
Log in to view solution →- A. P3 > P1 > P2
- B. P2 > P1 > P3
- C. P1 > P2 > P3
- D. P2 > P3 > P1
Correct answer & explanation hidden
Log in to view solution →- A. 21.92 cm
- B. 219.3 m
- C. 219.2 m
- D. 2192 m
Correct answer & explanation hidden
Log in to view solution →- A. 21.92 cm
- B. 219.3 m
- C. 219.2 m
- D. 2192 m
Correct answer & explanation hidden
Log in to view solution →- A. Noble gases have large positive values of electron gain enthalpy.
- B. Noble gases are sparingly soluble in water.
- C. Noble gases have very high melting and boiling points.
- D. Noble gases have weak dispersion forces.
Correct answer & explanation hidden
Log in to view solution →- A. Noble gases have large positive values of electron gain enthalpy.
- B. Noble gases are sparingly soluble in water.
- C. Noble gases have very high melting and boiling points.
- D. Noble gases have weak dispersion forces.
Correct answer & explanation hidden
Log in to view solution →- A. Statement I is incorrect but Statement II is true.
- B. Both Statement I and Statement II are true.
- C. Both Statement I and Statement II are false.
- D. Statement I is correct but Statement II is false.
Correct answer & explanation hidden
Log in to view solution →- A. Zone refining
- B. Electrolysis
- C. Chromatography
- D. Distillation
Correct answer & explanation hidden
Log in to view solution →- A. CH3−Cl > CH3−F > CH3−Br > CH3−I
- B. CH3−F < CH3−Cl < CH3−Br < CH3−I
- C. CH3−F > CH3−Cl > CH3−Br > CH3−I
- D. CH3−F < CH3−Cl > CH3−Br > CH3−I
Correct answer & explanation hidden
Log in to view solution →- A. C4H10O
- B. C5H12
- C. C3H8O
- D. C3H6O
Correct answer & explanation hidden
Log in to view solution →- A. Tridentate ligand with three “N” donor atoms
- B. Hexadentate ligand with four “O” and two “N” donor atoms
- C. Unidentate ligand
- D. Bidentate ligand with two “N” donor atoms
Correct answer & explanation hidden
Log in to view solution →- A. having similar chemical properties
- B. belonging to same group
- C. diagonal relationship
- D. lanthanoid contraction
Correct answer & explanation hidden
Log in to view solution →- A. sp2 and 8
- B. sp3 and 4
- C. sp3 and 6
- D. sp2 and 6
Correct answer & explanation hidden
Log in to view solution →- A. Actinoids are highly reactive metals, especially when finely divided.
- B. Actinoid contraction is greater for element to element than Lanthanoid contraction.
- C. Most of the trivalent Lanthanoid ions are colorless in the solid state.
- D. Lanthanoids are good conductors of heat and electricity.
Correct answer & explanation hidden
Log in to view solution →- A. Beryllium chloride
- B. Calcium chloride
- C. Strontium chloride
- D. Magnesium chloride
Correct answer & explanation hidden
Log in to view solution →- A. 350 mm of Hg
- B. 160 mm of Hg
- C. 168 mm of Hg
- D. 336 mm of Hg
Correct answer & explanation hidden
Log in to view solution →- A. ΔU ≠ 0, ΔStotal = 0
- B. ΔU = 0, ΔStotal = 0
- C. ΔU ≠ 0, ΔStotal ≠ 0
- D. ΔU = 0, ΔStotal ≠ 0
Correct answer & explanation hidden
Log in to view solution →- A. 26.02
- B. 2.518
- C. 2.602
- D. 25.18
Correct answer & explanation hidden
Log in to view solution →- A. Fe2+, Mn2+
- B. O2−, F−
- C. Na+, Mg2+
- D. Mn2+, Fe3+
Correct answer & explanation hidden
Log in to view solution →- A. Fe2+, Mn2+
- B. O2-, F-
- C. Na+, Mg2+
- D. Mn2+, Fe3+
Correct answer & explanation hidden
Log in to view solution →- A. DIBAL-H
- B. B2H6
- C. Red Phosphorus
- D. CaO
Correct answer & explanation hidden
Log in to view solution →- A. DIBAL-H
- B. B2H6
- C. Red Phosphorus
- D. CaO
Correct answer & explanation hidden
Log in to view solution →- A. NO2
- B. POCl3
- C. CH2O
- D. SbCl5
Correct answer & explanation hidden
Log in to view solution →- A. NO2
- B. POCl3
- C. CH2O
- D. SbCl5
Correct answer & explanation hidden
Log in to view solution →- A. −83 kJ mol^-1
- B. 41.5 kJ mol^-1
- C. 83.0 kJ mol^-1
- D. 166 kJ mol^-1
Correct answer & explanation hidden
Log in to view solution →- A. -83 kJ mol^-1
- B. 41.5 kJ mol^-1
- C. 83.0 kJ mol^-1
- D. 166 kJ mol^-1
Correct answer & explanation hidden
Log in to view solution →- A. (a)-(iii), (b)-(ii), (c)-(iv), (d)-(i)
- B. (a)-(i), (b)-(ii), (c)-(iii), (d)-(iv)
- C. (a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)
- D. (a)-(iv), (b)-(iii), (c)-(i), (d)-(ii)
Correct answer & explanation hidden
Log in to view solution →- A. (a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)
- B. (a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)
- C. (a)-(iii), (b)-(ii), (c)-(i), (d)-(iv)
- D. (a)-(i), (b)-(iv), (c)-(iii), (d)-(ii)
Correct answer & explanation hidden
Log in to view solution →- A. (a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)
- B. (a)-(iv), (b)-(ii), (c)-(i), (d)-(iii)
- C. (a)-(ii), (b)-(iv), (c)-(iii), (d)-(i)
- D. (a)-(i), (b)-(iii), (c)-(iv), (d)-(ii)
Correct answer & explanation hidden
Log in to view solution →- A. CO2 < SiO2 < SnO2 < PbO2 : Increasing oxidizing power
- B. HF < HCl < HBr < HI : Increasing acidic strength
- C. H2O < H2S < H2Se < H2Te : Increasing pKa values
- D. NH3 < PH3 < AsH3 < SbH3 : Increasing acidic character
Correct answer & explanation hidden
Log in to view solution →- A. 2.50×10^-5 mol L^-1
- B. 1.75×10^-4 mol L^-1
- C. 2.50×10^-4 mol L^-1
- D. 1.75×10^-5 mol L^-1
Correct answer & explanation hidden
Log in to view solution →- A. (1)(iii)(ii)(iv)(i)
- B. (2)(ii)(iv)(i)(iii)
- C. (3)(iv)(iii)(ii)(i)
- D. (4)(i)(ii)(iii)(iv)
Correct answer & explanation hidden
Log in to view solution →- A. Nuclear pores act as passages for proteins and RNA molecules in both directions between nucleus and cytoplasm.
- B. Mature sieve tube elements possess a conspicuous nucleus and usual cytoplasmic organelles.
- C. Microbodies are present both in plant and animal cells.
- D. The perinuclear space forms a barrier between the materials present inside the nucleus and that of the cytoplasm.
Correct answer & explanation hidden
Log in to view solution →- A. Safety testing
- B. Biopiracy
- C. Gene therapy
- D. Molecular diagnosis
Correct answer & explanation hidden
Log in to view solution →- A. Safety testing
- B. Biopiracy
- C. Gene therapy
- D. Molecular diagnosis
Correct answer & explanation hidden
Log in to view solution →- A. Polysaccharides
- B. RNA
- C. DNA
- D. Histones
Correct answer & explanation hidden
Log in to view solution →- A. Polysaccharides
- B. RNA
- C. DNA
- D. Histones
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Log in to view solution →- A. (1)(iv)(iii)(ii)(i)
- B. (2)(iii)(iv)(ii)(i)
- C. (3)(ii)(i)(iv)(iii)
- D. (4)(iii)(iv)(i)(ii)
Correct answer & explanation hidden
Log in to view solution →- A. (1)(iv)(iii)(ii)(i)
- B. (2)(iii)(iv)(ii)(i)
- C. (3)(ii)(i)(iv)(iii)
- D. (4)(iii)(iv)(i)(ii)
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Log in to view solution →- A. Acrocentric
- B. Metacentric
- C. Telocentric
- D. None of these
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Log in to view solution →- A. Acrocentric
- B. Metacentric
- C. Telocentric
- D. Sub-metacentric
Correct answer & explanation hidden
Log in to view solution →- A. Genetic drift
- B. Natural selection
- C. Genetic recombination
- D. Mutation
Correct answer & explanation hidden
Log in to view solution →- A. Annealing, Denaturation, Extension
- B. Denaturation, Annealing, Extension
- C. Denaturation, Extension, Annealing
- D. Extension, Denaturation, Annealing
Correct answer & explanation hidden
Log in to view solution →- A. Predation
- B. Resource partitioning
- C. Competitive release
- D. Mutualism
Correct answer & explanation hidden
Log in to view solution →- A. 8-nucleate and 8-celled
- B. 8-nucleate and 7-celled
- C. 7-nucleate and 8-celled
- D. 7-nucleate and 7-celled
Correct answer & explanation hidden
Log in to view solution →- A. Leaf
- B. Shoot apex
- C. Stem
- D. Axillary bud
Correct answer & explanation hidden
Log in to view solution →- A. Cycas circinalis
- B. Carica papaya
- C. Chara
- D. Marchantia polymorpha
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Log in to view solution →- A. (1)(ii)(iii)(iv)(i)
- B. (2)(iv)(iii)(ii)(i)
- C. (3)(i)(iv)(iii)(ii)
- D. (4)(iii)(iv)(i)(ii)
Correct answer & explanation hidden
Log in to view solution →- A. (1)(ii)(i)(iv)(iii)
- B. (2)(ii)(iv)(i)(iii)
- C. (3)(iv)(iii)(ii)(i)
- D. (4)(iii)(i)(iv)(ii)
Correct answer & explanation hidden
Log in to view solution →- A. (1)(iv)(ii)(i)(iii)
- B. (2)(iv)(i)(iii)(ii)
- C. (3)(iii)(i)(iv)(ii)
- D. (4)(ii)(iii)(iv)(i)
Correct answer & explanation hidden
Log in to view solution →- A. Cleistogamy
- B. Xenogamy
- C. Geitonogamy
- D. Chasmogamy
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Log in to view solution →- A. Detection of gene mutation
- B. Molecular diagnosis
- C. Gene amplification
- D. Purification of isolated protein
Correct answer & explanation hidden
Log in to view solution →- A. Net square
- B. Bullet square
- C. Punch square
- D. Punnett square
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Log in to view solution →- A. Net square
- B. Bullet square
- C. Punch square
- D. Punnett square
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Log in to view solution →- A. Blue-green algae
- B. Green algae
- C. Brown algae
- D. Red algae
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Log in to view solution →- A. Blue-green algae
- B. Green algae
- C. Brown algae
- D. Red algae
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Log in to view solution →- A. Species A (1) ; Species B (0)
- B. Species A (−) ; Species B (0)
- C. Species A (1) ; Species B (1)
- D. Species A (−) ; Species B (−)
Correct answer & explanation hidden
Log in to view solution →- A. Species A (1) ; Species B (0)
- B. Species A (−) ; Species B (0)
- C. Species A (1) ; Species B (1)
- D. Species A (−) ; Species B (−)
Correct answer & explanation hidden
Log in to view solution →- A. Telophase II
- B. Metaphase I
- C. Metaphase II
- D. Anaphase II
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Log in to view solution →- A. Telophase II
- B. Metaphase I
- C. Metaphase II
- D. Anahase II
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Log in to view solution →- A. (a)-Transduction; (b)-Translation; (c)-Replication; (d)-Protein
- B. (a)-Replication; (b)-Transcription; (c)-Transduction; (d)-Protein
- C. (a)-Translation; (b)-Replication; (c)-Transcription; (d)-Transduction
- D. (a)-Replication; (b)-Transcription; (c)-Translation; (d)-Protein
Correct answer & explanation hidden
Log in to view solution →- A. (a)-Transduction; (b)-Translation; (c)-Replication; (d)-Protein
- B. (a)-Replication; (b)-Transcription; (c)-Transduction; (d)-Protein
- C. (a)-Translation; (b)-Replication; (c)-Transcription; (d)-Transduction
- D. (a)-Replication; (b)-Transcription; (c)-Translation; (d)-Protein
Correct answer & explanation hidden
Log in to view solution →- A. Zeatin
- B. Kinetin
- C. Infrared rays
- D. Gamma rays
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Log in to view solution →- A. Zeatin
- B. Kinetin
- C. Infrared rays
- D. Gamma rays
Correct answer & explanation hidden
Log in to view solution →- A. Respiration losses
- B. Radiant energy
- C. Retardation factor
- D. Environment factor
Correct answer & explanation hidden
Log in to view solution →- A. Maturity
- B. Elasticity
- C. Flexibility
- D. Plasticity
Correct answer & explanation hidden
Log in to view solution →- A. IBA
- B. IAA
- C. NAA
- D. 2, 4-D
Correct answer & explanation hidden
Log in to view solution →- A. Pyramid of numbers in a grassland ecosystem is upright.
- B. Pyramid of biomass in sea is generally inverted.
- C. Pyramid of biomass in sea is generally upright.
- D. Pyramid of energy is always upright.
Correct answer & explanation hidden
Log in to view solution →- A. Some Liverworts
- B. Mosses
- C. Pteridophytes
- D. Some Gymnosperms
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Log in to view solution →- A. Phosphoglyceric acid
- B. Pyruvic acid
- C. Oxaloacetic acid
- D. Succinic acid
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Log in to view solution →- A. Ulothrix
- B. Ectocarpus
- C. Gracilaria
- D. Volvox
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Log in to view solution →- A. Bright blue bands
- B. Yellow bands
- C. Bright orange bands
- D. Dark red bands
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Log in to view solution →- A. China rose and citrus
- B. China rose
- C. Citrus
- D. Pea
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Log in to view solution →- A. Rubber, gums
- B. Morphine, codeine
- C. Amino acids, glucose
- D. Vinblastin, curcumin
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Log in to view solution →- A. Standing crop
- B. Climax
- C. Climax community
- D. Standing state
Correct answer & explanation hidden
Log in to view solution →- A. Heterosporous
- B. Homosorus
- C. Heterosorus
- D. Homosporous
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Log in to view solution →- A. it will be able to produce a novel protein with dual ability.
- B. it will not be able to confer ampicillin resistance to the host cell.
- C. the transformed cells will have the ability to resist ampicillin as well as produce β-galactoside.
- D. it will lead to lysis of host cell.
Correct answer & explanation hidden
Log in to view solution →- A. Rosaceae ; Leguminosae
- B. Poaceae ; Rosaceae
- C. Poaceae ; Leguminosae
- D. Poaceae ; Solanaceae
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Log in to view solution →- A. Split gene arrangement is characteristic of prokaryotes.
- B. In capping, methyl guanosine triphosphate is added to the 3' end of hnRNA.
- C. RNA polymerase binds with Rho factor to terminate the process of transcription in bacteria.
- D. The coding strand in a transcription unit is copied to an mRNA.
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Log in to view solution →- A. Some of the organisms can fix atmospheric nitrogen in specialized cells called sheath cells.
- B. Fusion of two cells is called Karyogamy.
- C. Fusion of protoplasms between two motile or non-motile gametes is called plasmogamy.
- D. Organisms that depend on living plants are called saprophytes.
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Log in to view solution →- A. Some of the organisms can fix atmospheric nitrogen in specialized cells called sheath cells.
- B. Fusion of two cells is called Karyogamy.
- C. Fusion of protoplasms between two motile or non-motile gametes is called plasmogamy.
- D. Organisms that depend on living plants are called saprophytes.
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Log in to view solution →- A. Polymorphic DNA
- B. Satellite DNA
- C. Repetitive DNA
- D. Single nucleotides
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Log in to view solution →- A. Polymorphic DNA
- B. Satellite DNA
- C. Repetitive DNA
- D. Single nucleotides
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Log in to view solution →- A. Oxidation-reduction reactions produce proton gradient in respiration.
- B. During aerobic respiration, role of oxygen is limited to the terminal stage.
- C. In ETC (Electron Transport Chain), one molecule of NADH+H+ gives rise to 2 ATP molecules, and one FADH2 gives rise to 3 ATP molecules.
- D. ATP is synthesized through complex V.
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Log in to view solution →- A. Cyclic photophosphorylation involves both PS I and PS II.
- B. Both ATP and NADPH+H+ are synthesized during non-cyclic photophosphorylation.
- C. Stroma lamellae have PS I only and lack NADP reductase.
- D. Grana lamellae have both PS I and PS II.
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Log in to view solution →- A. Transcribes only snRNAs
- B. Transcribes rRNAs (28S, 18S and 5.8S)
- C. Transcribes tRNA, 5s rRNA and snRNA
- D. Transcribes precursor of mRNA
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Log in to view solution →- A. The base of geometric logarithms
- B. The base of number logarithms
- C. The base of exponential logarithms
- D. The base of natural logarithms
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Log in to view solution →- A. mutated gene does not appear on photographic film as the probe has complementarity with it.
- B. mutated gene partially appears on a photographic film.
- C. mutated gene completely and clearly appears on a photographic film.
- D. mutated gene does not appear on a photographic film as the probe has no complementarity with it.
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Log in to view solution →- A. Zona pellucida
- B. Corona radiata
- C. Vitelline membrane
- D. Perivitelline space
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Log in to view solution →- A. Zona pellucida
- B. Corona radiata
- C. Vitelline membrane
- D. Perivitelline space
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Log in to view solution →- A. Pachytene
- B. Leptotene
- C. Zygotene
- D. Diakinesis
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Log in to view solution →- A. Pachytene
- B. Leptotene
- C. Zygotene
- D. Diakinesis
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Log in to view solution →- A. Golgi complex, Endoplasmic reticulum, Mitochondria and Lysosomes
- B. Endoplasmic reticulum, Mitochondria, Ribosomes and Lysosomes
- C. Endoplasmic reticulum, Golgi complex, Lysosomes and Vacuoles
- D. Golgi complex, Mitochondria, Ribosomes
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Log in to view solution →- A. Golgi complex, Endoplasmic reticulum, Mitochondria and Lysosomes
- B. Endoplasmic reticulum, Mitochondria, Ribosomes and Lysosomes
- C. Endoplasmic reticulum, Golgi complex, Lysosomes and Vacuoles
- D. Golgi complex, Mitochondria, Ribosomes and Lysosomes
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Log in to view solution →- A. Poly(A) tail sequences
- B. Degenerate primer sequence
- C. Okazaki sequences
- D. Palindromic Nucleotide sequences
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Log in to view solution →- A. Low pO2, low pCO2, more H+, higher temperature
- B. High pO2, low pCO2, less H+, lower temperature
- C. Low pO2, high pCO2, more H+, higher temperature
- D. High pO2, high pCO2, less H+, higher temperature
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Log in to view solution →- A. (1)(i)(iv)(iii)(ii)
- B. (2)(ii)(iii)(i)(iv)
- C. (3)(iv)(i)(iii)(ii)
- D. (4)(ii)(iii)(iv)(i)
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Log in to view solution →- A. Troposphere
- B. CFCs
- C. Stratosphere
- D. Ozone
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Log in to view solution →- A. House fly
- B. Fire fly
- C. Grasshopper
- D. Cockroach
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Log in to view solution →- A. (1)(a) and (c) only
- B. (2)(a), (b) and (c) only
- C. (3)(b), (c) and (d) only
- D. (4)(b) and (c) only
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Log in to view solution →- A. DNase
- B. DNA dependent DNA polymerase
- C. DNA dependent RNA polymerase
- D. DNA Ligase
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Log in to view solution →- A. (1)(iii)(i)(iv)(ii)
- B. (2)(iv)(ii)(i)(iii)
- C. (3)(i)(iii)(ii)(iv)
- D. (4)(ii)(iv)(iii)(i)
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Log in to view solution →- A. (1)(iv)(ii)(i)(iii)
- B. (2)(iii)(i)(iv)(ii)
- C. (3)(i)(ii)(iii)(iv)
- D. (4)(ii)(iii)(i)(iv)
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Log in to view solution →- A. Drugs - Ricin
- B. Alkaloids - Codeine
- C. Toxin - Abrin
- D. Lectins - Concanavalin A
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Log in to view solution →- A. pO2 = 159 and pCO2 = 0.3
- B. pO2 = 104 and pCO2 = 40
- C. pO2 = 40 and pCO2 = 45
- D. pO2 = 95 and pCO2 = 40
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Log in to view solution →- A. Junction of jejunum and duodenum
- B. Ileo-caecal junction
- C. Junction of hepato-pancreatic duct and duodenum
- D. Gastro-oesophageal junction
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Log in to view solution →- A. Junction of jejunum and duodenum
- B. Ileo-caecal junction
- C. Junction of hepato-pancreatic duct and duodenum
- D. Gastro-oesophageal junction
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Log in to view solution →- A. siRNA
- B. mRNA
- C. tRNA
- D. rRNA
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Log in to view solution →- A. siRNA
- B. mRNA
- C. tRNA
- D. rRNA
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Log in to view solution →- A. Chyme
- B. Pancreatic juice
- C. Intestinal juice
- D. Gastric juice
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Log in to view solution →- A. Chyme
- B. Pancreatic juice
- C. Intestinal juice
- D. Gastric juice
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Log in to view solution →- A. Absence of antibodies, anti-A and anti-B, in plasma
- B. Absence of antigens A and B on the surface of RBCs
- C. Absence of antigens A and B in plasma
- D. Presence of antibodies, anti-A and anti-B, on RBCs
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Log in to view solution →- A. Absence of antibodies, anti-A and anti-B, in plasma
- B. Absence of antigens A and B on the surface of RBCs
- C. Absence of antigens A and B in plasma
- D. Presence of antibodies, anti-A and anti-B, on RBCs
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Log in to view solution →- A. 10th abdominal segment in both sexes, bears a pair of anal cerci.
- B. A ring of gastric caeca is present at the junction of midgut and hind gut.
- C. Hypopharynx lies within the cavity enclosed by the mouth parts.
- D. In females, 7th-9th sterna together form a genital pouch.
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Log in to view solution →- A. These muscles are present in the wall of blood vessels
- B. These muscle have no striations
- C. They are involuntary muscles
- D. Communication among the cells is performed by intercalated discs
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Log in to view solution →- A. Ornithorhynchus
- B. Neophron
- C. Hemidactylus
- D. Macropus
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Log in to view solution →- A. T : 20 ; G : 25 ; C : 25
- B. T : 20 ; G : 30 ; C : 20
- C. T : 20 ; G : 20 ; C : 30
- D. T : 30 ; G : 20 ; C : 20
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Log in to view solution →- A. Thrombokinase
- B. Thrombin
- C. Renin
- D. Epinephrine
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Log in to view solution →- A. 100%
- B. 50%
- C. 75%
- D. 25%
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Log in to view solution →- A. Multiload 375
- B. CuT
- C. LNG 20
- D. Cu 7
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Log in to view solution →- A. G2 phase
- B. S-phase
- C. Prophase
- D. Metaphase
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Log in to view solution →- A. Gout
- B. Arthritis
- C. Muscular dystrophy
- D. Myasthenia gravis
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