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Chapter 6: Triangles — Online MCQ Test

MATHS · CLASS 10th · Karnataka State Board

Practice Chapter 6: Triangles with a free chapter-wise online MCQ test for Karnataka State Board CLASS 10th MATHS. This chapter covers: Similar triangles Criteria for similarity Basic proportionality theorem Pythagoras theorem Converse of Pythagoras theorem Triangle proofs Ratio of areas. AI-generated questions from basic to board-exam level, with instant results and explanations.

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Chapter 6: Triangles — Important Questions & Answers (FAQ)

Frequently asked questions from Karnataka State Board CLASS 10th MATHS — Chapter 6: Triangles, with answers and explanations. These are sample questions; the exam has its own separate question set.

Two triangles are said to be similar if their corresponding angles are equal and their corresponding sides are:
  • A. Equal
  • B. Perpendicular
  • C. Proportional ✓
  • D. Parallel
Answer: C. Proportional
Similar triangles have equal corresponding angles and proportional corresponding sides.
Which similarity criterion states that two triangles are similar if their corresponding angles are equal?
  • A. SSS similarity
  • B. AAA similarity ✓
  • C. RHS congruence
  • D. SAS congruence
Answer: B. AAA similarity
By AAA similarity, if all corresponding angles of two triangles are equal, the triangles are similar.
In triangle ABC, D lies on AB and E lies on AC. If DE is parallel to BC, AD = 3 cm, DB = 4 cm and AE = 6 cm, then EC is:
  • A. 6 cm
  • B. 7 cm
  • C. 8 cm ✓
  • D. 10 cm
Answer: C. 8 cm
By BPT, AD/DB = AE/EC. So 3/4 = 6/EC, giving EC = 8 cm.
Two vertical poles cast shadows at the same time. A 6 m pole casts a 4 m shadow. If another pole casts an 18 m shadow, its height is:
  • A. 12 m
  • B. 18 m
  • C. 24 m
  • D. 27 m ✓
Answer: D. 27 m
The pole and its shadow form similar right triangles. Therefore height/shadow = 6/4, so height = 18 × 6/4 = 27 m.
In triangle ABC, P lies on AB and Q lies on AC such that PQ is parallel to BC. If AP:PB = 2:3 and the area of trapezium PBCQ is 84 cm², then the area of triangle APQ is:
  • A. 12 cm²
  • B. 16 cm² ✓
  • C. 20 cm²
  • D. 24 cm²
Answer: B. 16 cm²
AP/AB = 2/5, so ar(APQ)/ar(ABC) = 4/25. The trapezium area is 21/25 of ar(ABC), so ar(ABC) = 100 cm² and ar(APQ) = 16 cm².

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