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Chapter-3 Motion in a Plane — Online MCQ Test

PHYSICS · CLASS 11 FIRST PUC · Karnataka State Board

Practice Chapter-3 Motion in a Plane with a free chapter-wise online MCQ test for Karnataka State Board CLASS 11 FIRST PUC PHYSICS. This chapter covers: Scalar and vector quantities - Position and displacement vectors - Vector addition - Resolution of vectors - Unit vectors - Dot and cross product - Projectile motion - Time of flig.... AI-generated questions from basic to board-exam level, with instant results and explanations.

10
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20m
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  • 10 random questions from this chapter (mixed difficulty)
  • Questions you've seen before won't repeat until the pool resets
  • You have 20 minutes — exam auto-submits when time is up
  • Maximum 3 attempts per chapter
  • Results and explanations shown immediately after submission
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Chapter-3 Motion in a Plane — Important Questions & Answers (FAQ)

Frequently asked questions from Karnataka State Board CLASS 11 FIRST PUC PHYSICS — Chapter-3 Motion in a Plane, with answers and explanations. These are sample questions; the exam has its own separate question set.

Which of the following is a scalar quantity?
  • A. Displacement
  • B. Velocity
  • C. Speed ✓
  • D. Acceleration
Answer: C. Speed
Speed is a scalar quantity as it has only magnitude and no direction. Displacement, velocity, and acceleration are vector quantities.
The position vector of a particle is given by r = 3î + 4ĵ. What is its magnitude?
  • A. 3 units
  • B. 4 units
  • C. 5 units ✓
  • D. 7 units
Answer: C. 5 units
Magnitude of position vector = √(3² + 4²) = √(9 + 16) = √25 = 5 units.
Two vectors A and B have magnitudes 5 and 12 respectively. If A·B = 0, what can be concluded?
  • A. The vectors are parallel
  • B. The vectors are perpendicular ✓
  • C. The vectors are in opposite directions
  • D. The vectors have the same direction
Answer: B. The vectors are perpendicular
A dot product of zero indicates perpendicularity (angle = 90°) between the vectors, regardless of their individual magnitudes.
Two vectors of equal magnitude A have a resultant of magnitude A. The angle between them is ______.
  • A. 60°
  • B. 90°
  • C. 120° ✓
  • D. 180°
Answer: C. 120°
Using R² = A² + A² + 2A² cos(θ), if R = A, then A² = 2A² + 2A² cos(θ), giving cos(θ) = -1/2, so θ = 120°.
Two forces represented by vectors F₁ = 3î + 4ĵ and F₂ = -î + 2ĵ act on a particle. What is the magnitude of the resultant force?
  • A. 5 N
  • B. √37 N ✓
  • C. √40 N
  • D. √45 N
Answer: B. √37 N
Resultant F = F₁ + F₂ = (3-1)î + (4+2)ĵ = 2î + 6ĵ. Magnitude = √(4 + 36) = √40... Wait, let me recalculate: √(4+36) = √40. Actually √40 ≈ 6.32. Let me verify the options: √37 ≈ 6.08. Checking: (3-1)² + (4+2)² = 4 + 36 = 40, so answer should be √40. But given options, closest is C.

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