Chapter Exam

Chapter-5 Number Play — Online MCQ Test

Q: A number is divisible by 2 if its last digit is ______.

Answer: B. even — A number is divisible by 2 if and only if its last digit is even (0, 2, 4, 6, 8).

Q: What is the divisibility test for 5?

Answer: B. The last digit must be 0 or 5 — A number is divisible by 5 if its last digit is either 0 or 5.

Q: If a three-digit number is written as 'abc' in generalized form, its value is ______.

Answer: B. 100a + 10b + c — A three-digit number 'abc' has value 100a + 10b + c, where a is in hundreds place, b in tens place, and c in units place.

Q: If a number 'abc' is divisible by 11, then which condition must be true?

Answer: B. (a - b + c) is divisible by 11 — The divisibility test for 11 for a three-digit number 'abc' is: (a - b + c) must be divisible by 11, or more generally, the alternating sum of digits must be divisible by 11.

Q: If PQ + QR + RP = PQR, where P, Q, R are distinct digits, then what is the value of P?

Answer: A. 1 — PQ + QR + RP = (10P+Q) + (10Q+R) + (10R+P) = 11P + 11Q + 11R = 11(P+Q+R). For this to equal PQR = 100P + 10Q + R, we need 11(P+Q+R) = 100P + 10Q + R. Simplifying: 11P + 11Q + 11R = 100P + 10Q + R gives Q + 10R = 89P, which works when P=1.

MATHS (KANITHA PRAKASH) · CLASS 8th · Karnataka State Board

Practice Chapter-5 Number Play with a free chapter-wise online MCQ test for Karnataka State Board CLASS 8th MATHS (KANITHA PRAKASH). This chapter covers: generalized form - divisibility tests - letters for digits - cryptarithms - number puzzles. AI-generated questions from basic to board-exam level, with instant results and explanations.

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Chapter-5 Number Play — Important Questions & Answers (FAQ)

Frequently asked questions from Karnataka State Board CLASS 8th MATHS (KANITHA PRAKASH) — Chapter-5 Number Play, with answers and explanations. These are sample questions; the exam has its own separate question set.

A number is divisible by 2 if its last digit is ______.

A. odd
B. even ✓
C. prime
D. greater than 5

Answer: B. even
A number is divisible by 2 if and only if its last digit is even (0, 2, 4, 6, 8).

What is the divisibility test for 5?

A. The sum of digits must be divisible by 5
B. The last digit must be 0 or 5 ✓
C. The number must be even
D. All digits must be divisible by 5

Answer: B. The last digit must be 0 or 5
A number is divisible by 5 if its last digit is either 0 or 5.

If a three-digit number is written as 'abc' in generalized form, its value is ______.

A. a + b + c
B. 100a + 10b + c ✓
C. abc
D. 100(a + b + c)

Answer: B. 100a + 10b + c
A three-digit number 'abc' has value 100a + 10b + c, where a is in hundreds place, b in tens place, and c in units place.

If a number 'abc' is divisible by 11, then which condition must be true?

A. a + b + c is divisible by 11
B. (a - b + c) is divisible by 11 ✓
C. a + b + c is even
D. abc must be a three-digit prime

Answer: B. (a - b + c) is divisible by 11
The divisibility test for 11 for a three-digit number 'abc' is: (a - b + c) must be divisible by 11, or more generally, the alternating sum of digits must be divisible by 11.

If PQ + QR + RP = PQR, where P, Q, R are distinct digits, then what is the value of P?

A. 1 ✓
B. 2
C. 3
D. 4

Answer: A. 1
PQ + QR + RP = (10P+Q) + (10Q+R) + (10R+P) = 11P + 11Q + 11R = 11(P+Q+R). For this to equal PQR = 100P + 10Q + R, we need 11(P+Q+R) = 100P + 10Q + R. Simplifying: 11P + 11Q + 11R = 100P + 10Q + R gives Q + 10R = 89P, which works when P=1.