Empowering Students with AI-Powered Assessments & Intelligent Learning
Chapter Exam

Chapter 8: Force and Laws of Motion — Online MCQ Test

SCIENCE · CLASS 9th · Karnataka State Board

Practice Chapter 8: Force and Laws of Motion with a free chapter-wise online MCQ test for Karnataka State Board CLASS 9th SCIENCE. This chapter covers: This chapter details balanced unbalanced forces Newton three laws of motion inertia mass momentum and conservation of momentum principles.. AI-generated questions from basic to board-exam level, with instant results and explanations.

10
Questions
20m
Time Limit
3
Attempts Left
  • 10 random questions from this chapter (mixed difficulty)
  • Questions you've seen before won't repeat until the pool resets
  • You have 20 minutes — exam auto-submits when time is up
  • Maximum 3 attempts per chapter
  • Results and explanations shown immediately after submission
Login to Start This Exam →

New here? Register free — includes 3 free chapter exams.

Chapter 8: Force and Laws of Motion — Important Questions & Answers (FAQ)

Frequently asked questions from Karnataka State Board CLASS 9th SCIENCE — Chapter 8: Force and Laws of Motion, with answers and explanations. These are sample questions; the exam has its own separate question set.

Which of the following is a vector quantity?
  • A. Mass
  • B. Force ✓
  • C. Speed
  • D. Time
Answer: B. Force
Force has both magnitude and direction, so it is a vector quantity. Mass, speed, and time are scalar quantities.
The SI unit of momentum is:
  • A. kg m/s ✓
  • B. N/m
  • C. kg/m
  • D. N s/m
Answer: A. kg m/s
Momentum equals mass × velocity, so its unit is kg × m/s = kg m/s.
A force of 10 N acts on a body of mass 2 kg. The acceleration produced is:
  • A. 2 m/s²
  • B. 5 m/s² ✓
  • C. 8 m/s²
  • D. 20 m/s²
Answer: B. 5 m/s²
Using F = ma, acceleration = F/m = 10/2 = 5 m/s².
A body of mass 4 kg moving with velocity 3 m/s has momentum equal to:
  • A. 7 kg m/s
  • B. 12 kg m/s ✓
  • C. 1.33 kg m/s
  • D. 24 kg m/s
Answer: B. 12 kg m/s
Momentum is mass × velocity = 4 × 3 = 12 kg m/s.
A 2 kg cart moving at 6 m/s collides with a stationary 1 kg cart and they move together after collision. If momentum is conserved, their common velocity is:
  • A. 2 m/s ✓
  • B. 4 m/s
  • C. 6 m/s
  • D. 12 m/s
Answer: A. 2 m/s
Initial momentum = 2 × 6 + 1 × 0 = 12 kg m/s. Combined mass = 3 kg, so velocity = 12/3 = 4 m/s.

Choose Your Plan & Start Practising

All plans cover every subject and chapter of your registered grade.

Free
₹0
3 exams · 1 year
Start Free →
Active
₹350
12 exams · 1 year
Get Active →
Pro
₹899
Unlimited exams · 1 year
Get Pro →
NEET
₹999
Unlimited exams · 1 year
Get NEET →

Compare all plans in detail →