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Chapter 7: Atoms and Molecules — Online MCQ Test

SCIENCE · CLASS 10th · Tamil Nadu State Board

Practice Chapter 7: Atoms and Molecules with a free chapter-wise online MCQ test for Tamil Nadu State Board CLASS 10th SCIENCE. This chapter covers: This chapter covers atomic mass molecular mass Avogadro hypothesis and mole concepts. Students learn relative atomic mass calculation atomicity and gas volume relationships.. AI-generated questions from basic to board-exam level, with instant results and explanations.

10
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20m
Time Limit
3
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  • Questions you've seen before won't repeat until the pool resets
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Chapter 7: Atoms and Molecules — Important Questions & Answers (FAQ)

Frequently asked questions from Tamil Nadu State Board CLASS 10th SCIENCE — Chapter 7: Atoms and Molecules, with answers and explanations. These are sample questions; the exam has its own separate question set.

What is the standard reference used to calculate the relative atomic mass of an element?
  • A. Carbon-12 isotope ✓
  • B. Hydrogen-1
  • C. Oxygen-16
  • D. Nitrogen-14
Answer: A. Carbon-12 isotope
The relative atomic mass is defined as the ratio of the average mass of one atom of an element to 1/12th of the mass of a carbon-12 atom.
The number of atoms present in one molecule of an element is known as its ________.
  • A. Valency
  • B. Atomicity ✓
  • C. Molarity
  • D. Molecular mass
Answer: B. Atomicity
Atomicity is the number of atoms present in one molecule of an element.
Calculate the molecular mass of Water (H2O). (Given: Atomic mass of H=1, O=16)
  • A. 17 amu
  • B. 18 amu ✓
  • C. 32 amu
  • D. 34 amu
Answer: B. 18 amu
Molecular mass = (2 * 1) + (1 * 16) = 18 amu.
How many moles are there in 5.6 liters of Oxygen gas at STP?
  • A. 0.25 moles ✓
  • B. 0.5 moles
  • C. 1 mole
  • D. 2 moles
Answer: A. 0.25 moles
Number of moles = Given volume / 22.4. So, 5.6 / 22.4 = 0.25 moles.
An element X has a vapour density of 14. What is the atomicity of the element if its atomic mass is 7?
  • A. 2
  • B. 3
  • C. 4 ✓
  • D. 1
Answer: C. 4
Molecular mass = 2 * Vapour density = 28. Atomicity = Molecular mass / Atomic mass = 28 / 7 = 4.

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