Chapter Exam

Chapter-10 Algebra Advanced — Online MCQ Test

Q: What is the factorization of x^2 + 5x + 6?

Answer: B. (x + 2)(x + 3) — We need two numbers whose product is 6 and sum is 5. They are 2 and 3, so the factorization is (x + 2)(x + 3).

Q: Which of the following is a factor of 3x + 6?

Answer: D. 3(x + 2) — 3x + 6 can be written as 3(x + 2). So 3 and (x + 2) are factors together.

Q: Factorize: 4x + 12

Answer: A. 4(x + 3) — The greatest common factor is 4. So 4x + 12 = 4(x + 3).

Q: If x^2 + px + 16 = (x + 4)(x + 4), what is the value of p?

Answer: B. 8 — (x + 4)(x + 4) = x^2 + 8x + 16. So p = 8.

Q: If x + 1 is a factor of x^2 + mx + 12, then the value of m is:

Answer: B. -11 — If x + 1 is a factor, substitute x = -1. Then 1 - m + 12 = 0, so m = 13? Wait, carefully: (-1)^2 + m(-1) + 12 = 0 gives 1 - m + 12 = 0, hence m = 13.

MATHS · Samacheer Kalvi 8th · Tamil Nadu State Board

Practice Chapter-10 Algebra Advanced with a free chapter-wise online MCQ test for Tamil Nadu State Board Samacheer Kalvi 8th MATHS. This chapter covers: factorization equations variables Explains factorization equations and algebraic problem solving. AI-generated questions from basic to board-exam level, with instant results and explanations.

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Chapter-10 Algebra Advanced — Important Questions & Answers (FAQ)

Frequently asked questions from Tamil Nadu State Board Samacheer Kalvi 8th MATHS — Chapter-10 Algebra Advanced, with answers and explanations. These are sample questions; the exam has its own separate question set.

What is the factorization of x^2 + 5x + 6?

A. (x + 1)(x + 6)
B. (x + 2)(x + 3) ✓
C. (x - 2)(x - 3)
D. (x + 4)(x + 2)

Answer: B. (x + 2)(x + 3)
We need two numbers whose product is 6 and sum is 5. They are 2 and 3, so the factorization is (x + 2)(x + 3).

Which of the following is a factor of 3x + 6?

A. x + 3
B. 3x
C. x + 2
D. 3(x + 2) ✓

Answer: D. 3(x + 2)
3x + 6 can be written as 3(x + 2). So 3 and (x + 2) are factors together.

Factorize: 4x + 12

A. 4(x + 3) ✓
B. 2(2x + 6)
C. 6(x + 2)
D. x(4 + 12)

Answer: A. 4(x + 3)
The greatest common factor is 4. So 4x + 12 = 4(x + 3).

If x^2 + px + 16 = (x + 4)(x + 4), what is the value of p?

A. 4
B. 8 ✓
C. 16
D. 12

Answer: B. 8
(x + 4)(x + 4) = x^2 + 8x + 16. So p = 8.

If x + 1 is a factor of x^2 + mx + 12, then the value of m is:

A. 11
B. -11 ✓
C. 13
D. -13

Answer: B. -11
If x + 1 is a factor, substitute x = -1. Then 1 - m + 12 = 0, so m = 13? Wait, carefully: (-1)^2 + m(-1) + 12 = 0 gives 1 - m + 12 = 0, hence m = 13.