Chapter Exam

Chapter 12: Carbon and Its Compounds — Online MCQ Test

Q: Which property of carbon allows it to form a large number of compounds?

Answer: B. Tetravalency and catenation — Carbon's tetravalency (four valence electrons) and ability to form chains (catenation) enable it to form countless organic compounds.

Q: Which of the following is NOT an allotrope of carbon?

Answer: D. Charcoal oxide — Allotropes are different forms of the same element. Diamond, graphite, and fullerenes are pure carbon allotropes; charcoal oxide is not a pure form of carbon.

Q: Alkenes differ from alkanes in that they contain ______.

Answer: B. A double bond between carbons — Alkenes are unsaturated hydrocarbons characterized by the presence of at least one C=C double bond, distinguishing them from saturated alkanes.

Q: A student observes that a compound has high hardness, high melting point, is insoluble in water, and does not conduct electricity in solid state. Based on these properties, this allotrope of carbon is most likely ______. What additional test could confirm this?

Answer: B. Diamond; testing refractive index and luster — Diamond's tetrahedral structure gives it exceptional hardness and high melting point while being non-conductive as a solid. Testing its high refractive index and brilliant luster would confirm it.

PHYSICAL SCIENCES · CLASS 10th · Telangana State Board

Practice Chapter 12: Carbon and Its Compounds with a free chapter-wise online MCQ test for Telangana State Board CLASS 10th PHYSICAL SCIENCES. This chapter covers: The final chapter explores organic chemistry focusing on carbon's unique ability to form vast arrays of compounds through catenation and tetravalency. Students study allotropes of.... AI-generated questions from basic to board-exam level, with instant results and explanations.

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Chapter 12: Carbon and Its Compounds — Important Questions & Answers (FAQ)

Frequently asked questions from Telangana State Board CLASS 10th PHYSICAL SCIENCES — Chapter 12: Carbon and Its Compounds, with answers and explanations. These are sample questions; the exam has its own separate question set.

Which property of carbon allows it to form a large number of compounds?

A. High atomic number
B. Tetravalency and catenation ✓
C. Metallic nature
D. High electronegativity

Answer: B. Tetravalency and catenation
Carbon's tetravalency (four valence electrons) and ability to form chains (catenation) enable it to form countless organic compounds.

Which of the following is NOT an allotrope of carbon?

A. Diamond
B. Graphite
C. Fullerene
D. Charcoal oxide ✓

Answer: D. Charcoal oxide
Allotropes are different forms of the same element. Diamond, graphite, and fullerenes are pure carbon allotropes; charcoal oxide is not a pure form of carbon.

Alkenes differ from alkanes in that they contain ______.

A. A triple bond between carbons
B. A double bond between carbons ✓
C. An additional oxygen atom
D. A hydroxyl group

Answer: B. A double bond between carbons
Alkenes are unsaturated hydrocarbons characterized by the presence of at least one C=C double bond, distinguishing them from saturated alkanes.

Comparing diamond, graphite, and fullerenes, which statement is true?

A. All three have identical crystal structures but different physical properties
B. They are allotropes of carbon with different atomic arrangements resulting in different properties ✓
C. Fullerenes are not true allotropes of carbon
D. Diamond and graphite cannot form different allotropes

Answer: B. They are allotropes of carbon with different atomic arrangements resulting in different properties
Diamond (tetrahedral), graphite (layered), and fullerenes (spherical/cage-like) are all pure carbon allotropes with different structural arrangements that cause their distinct properties.

A student observes that a compound has high hardness, high melting point, is insoluble in water, and does not conduct electricity in solid state. Based on these properties, this allotrope of carbon is most likely ______. What additional test could confirm this?

A. Graphite; testing electrical conductivity
B. Diamond; testing refractive index and luster ✓
C. Fullerene; testing solubility in organic solvents
D. Charcoal; testing reactivity with oxygen

Answer: B. Diamond; testing refractive index and luster
Diamond's tetrahedral structure gives it exceptional hardness and high melting point while being non-conductive as a solid. Testing its high refractive index and brilliant luster would confirm it.

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