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Unit 8: Differential Equations — Online MCQ Test

MATHEMATICS - 2B · CLASS 12 INTERMEDIATE 2 YEAR · Telangana State Board

Practice Unit 8: Differential Equations with a free chapter-wise online MCQ test for Telangana State Board CLASS 12 INTERMEDIATE 2 YEAR MATHEMATICS - 2B. This chapter covers: The final chapter details order degree of differential equations formation of differential equations solutions of variable separable homogeneous and linear first-order differential.... AI-generated questions from basic to board-exam level, with instant results and explanations.

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Unit 8: Differential Equations — Important Questions & Answers (FAQ)

Frequently asked questions from Telangana State Board CLASS 12 INTERMEDIATE 2 YEAR MATHEMATICS - 2B — Unit 8: Differential Equations, with answers and explanations. These are sample questions; the exam has its own separate question set.

What is the order of the differential equation \(\frac{d^2y}{dx^2} + 3\frac{dy}{dx} - 5y = 0\)?
  • A. 1
  • B. 2 ✓
  • C. 3
  • D. 5
Answer: B. 2
The highest derivative present is \(\frac{d^2y}{dx^2}\), so the order is 2.
Which of the following is a differential equation?
  • A. \(y = x^2 + 1\)
  • B. \(\frac{dy}{dx} = x + y\) ✓
  • C. \(x^2 + y^2 = 1\)
  • D. \(y = \sin x\)
Answer: B. \(\frac{dy}{dx} = x + y\)
A differential equation contains derivatives of the dependent variable. Only option B includes a derivative.
Solve the separable differential equation \(\frac{dy}{dx} = xy\).
  • A. \(y = Ce^{x^2/2}\) ✓
  • B. \(y = Ce^{2x}\)
  • C. \(y = Cx^2\)
  • D. \(y = C\ln x\)
Answer: A. \(y = Ce^{x^2/2}\)
Separating variables gives \(\frac{dy}{y} = x\,dx\). Integrating, \(\ln|y| = \frac{x^2}{2} + C\), hence \(y = Ce^{x^2/2}\).
If the differential equation is \(\frac{dy}{dx} = \frac{x+y}{x}\), then after substituting \(y = vx\), the equation becomes
  • A. \(v + x\frac{dv}{dx} = 1 + v\)
  • B. \(x\frac{dv}{dx} = 1\) ✓
  • C. \(x\frac{dv}{dx} = v\)
  • D. \(\frac{dv}{dx} = x+v\)
Answer: B. \(x\frac{dv}{dx} = 1\)
Using \(y=vx\), we get \(\frac{dy}{dx}=v+x\frac{dv}{dx}\). Substituting gives \(v+x\frac{dv}{dx}=1+v\), so \(x\frac{dv}{dx}=1\).
If a first-order differential equation has integrating factor \(e^{\int 2x\,dx}\), then the corresponding coefficient \(P(x)\) is
  • A. x
  • B. 2x ✓
  • C. x^2
  • D. 2
Answer: B. 2x
The integrating factor for \(\frac{dy}{dx} + P(x)y = Q(x)\) is \(e^{\int P(x)dx}\). Hence \(P(x)=2x\).

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