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Chapter 5: Electrostatic Potential and Capacitance — Online MCQ Test

PHYSICS · CLASS 12 INTERMEDIATE 2 YEAR · Telangana State Board

Practice Chapter 5: Electrostatic Potential and Capacitance with a free chapter-wise online MCQ test for Telangana State Board CLASS 12 INTERMEDIATE 2 YEAR PHYSICS. This chapter covers: Focusing on electrostatics this chapter details electric potential potential energy equipotential surfaces conductors dielectrics parallel plate capacitors energy storage and serie.... AI-generated questions from basic to board-exam level, with instant results and explanations.

10
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20m
Time Limit
3
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  • Questions you've seen before won't repeat until the pool resets
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  • Results and explanations shown immediately after submission
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Chapter 5: Electrostatic Potential and Capacitance — Important Questions & Answers (FAQ)

Frequently asked questions from Telangana State Board CLASS 12 INTERMEDIATE 2 YEAR PHYSICS — Chapter 5: Electrostatic Potential and Capacitance, with answers and explanations. These are sample questions; the exam has its own separate question set.

What is the SI unit of electric potential?
  • A. Joule
  • B. Volt ✓
  • C. Newton
  • D. Coulomb
Answer: B. Volt
Electric potential is defined as work done per unit charge, and its SI unit is volt.
The electric potential at a point is defined as the work done in bringing a unit positive test charge from:
  • A. the point to infinity
  • B. infinity to the point ✓
  • C. one point to another point in the same field only
  • D. the origin to the point
Answer: B. infinity to the point
Electric potential at a point is the work done in bringing a unit positive charge from infinity to that point.
A charge q is moved through a potential difference of V. The work done is:
  • A. q/V
  • B. qV ✓
  • C. V/q
  • D. q²V
Answer: B. qV
Work done in moving a charge through a potential difference is given by W = qV.
If the electric potential is constant throughout a region, then the electric field in that region is:
  • A. uniform and non-zero
  • B. zero ✓
  • C. maximum
  • D. depends on the choice of origin
Answer: B. zero
Electric field equals the negative rate of change of potential. If potential is constant, its gradient is zero and hence the electric field is zero.
A parallel plate capacitor is connected to a battery. If the plate separation is increased, which of the following is correct?
  • A. Charge decreases and energy decreases ✓
  • B. Charge increases and energy increases
  • C. Charge remains constant and energy remains constant
  • D. Charge increases and potential decreases
Answer: A. Charge decreases and energy decreases
With battery connected, potential remains constant. Since C decreases when separation increases, the charge decreases and stored energy also decreases.

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