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Chapter 1: Relations and Functions — Online MCQ Test

MATHS · CLASS 10th · Tamil Nadu State Board

Practice Chapter 1: Relations and Functions with a free chapter-wise online MCQ test for Tamil Nadu State Board CLASS 10th MATHS. This chapter covers: Ordered pairs Cartesian product Relations Functions Domain Range Codomain One one function Many one function Onto function Into function Composite function Inverse function Represe.... AI-generated questions from basic to board-exam level, with instant results and explanations.

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Chapter 1: Relations and Functions — Important Questions & Answers (FAQ)

Frequently asked questions from Tamil Nadu State Board CLASS 10th MATHS — Chapter 1: Relations and Functions, with answers and explanations. These are sample questions; the exam has its own separate question set.

If two ordered pairs (a, b) and (c, d) are equal, then which statement is true?
  • A. a = c and b = d ✓
  • B. a = d and b = c
  • C. a + b = c + d only
  • D. a = b and c = d
Answer: A. a = c and b = d
Two ordered pairs are equal only when their corresponding first and second components are equal.
The Cartesian product A × B is the set of all ordered pairs of the form:
  • A. (a, b), where a ∈ A and b ∈ B ✓
  • B. (b, a), where a ∈ A and b ∈ B
  • C. (a, a), where a ∈ A only
  • D. (b, b), where b ∈ B only
Answer: A. (a, b), where a ∈ A and b ∈ B
By definition, A × B contains all ordered pairs whose first element is from A and second element is from B.
If n(A) = 3 and n(B) = 4, then n(A × B) is:
  • A. 7
  • B. 12 ✓
  • C. 1
  • D. 34
Answer: B. 12
The number of elements in A × B is n(A) × n(B) = 3 × 4 = 12.
For the relation R = {(1, 2), (2, 4), (3, 6)}, the domain is:
  • A. {2, 4, 6}
  • B. {1, 2, 3} ✓
  • C. {1, 2, 3, 4, 6}
  • D. {(1, 2), (2, 4), (3, 6)}
Answer: B. {1, 2, 3}
The domain of a relation is the set of all first components of the ordered pairs.
If A = {1, 2} and B = {3, 4, 5}, then A × B is:
  • A. {(1, 3), (1, 4), (1, 5), (2, 3), (2, 4), (2, 5)} ✓
  • B. {(3, 1), (4, 1), (5, 1), (3, 2), (4, 2), (5, 2)}
  • C. {(1, 2), (3, 4), (4, 5)}
  • D. {1, 2, 3, 4, 5}
Answer: A. {(1, 3), (1, 4), (1, 5), (2, 3), (2, 4), (2, 5)}
A × B contains all ordered pairs with first element from A and second element from B.
Let A = {1, 2, 3} and B = {2, 3, 4, 5}. If R = {(x, y) : y = x + 1, x ∈ A, y ∈ B}, then R is:
  • A. {(1, 2), (2, 3), (3, 4)} ✓
  • B. {(2, 1), (3, 2), (4, 3)}
  • C. {(1, 3), (2, 4), (3, 5)}
  • D. {(1, 1), (2, 2), (3, 3)}
Answer: A. {(1, 2), (2, 3), (3, 4)}
Substituting x = 1, 2, 3 gives y = 2, 3, 4 respectively.
For f : R → R defined by f(x) = x², which statement is true?
  • A. f is one-one and onto
  • B. f is one-one but not onto
  • C. f is onto but not one-one
  • D. f is neither one-one nor onto ✓
Answer: D. f is neither one-one nor onto
Since f(1) = f(-1), it is not one-one. Also negative real numbers are not images, so it is not onto R.
For f : Z → Z defined by f(n) = n + 2, the function is:
  • A. one-one and onto ✓
  • B. many-one and onto
  • C. one-one but not onto
  • D. neither one-one nor onto
Answer: A. one-one and onto
Different integers give different images, and every integer k has a preimage k - 2. Hence the function is one-one and onto.
If n(A) = 3 and n(B) = 5, then the number of one-one functions from A to B is:
  • A. 15
  • B. 25
  • C. 60 ✓
  • D. 125
Answer: C. 60
For a one-one function, the 3 elements of A must get distinct images from 5 elements of B. The number is 5 × 4 × 3 = 60.
Let f : R → R be f(x) = ax + b, where a ≠ 0. For which condition is f⁻¹ = f?
  • A. a = 1 and b can be any real number
  • B. a = -1 with any real b, or a = 1 and b = 0 ✓
  • C. a = 0 and b = 1
  • D. a = 2 and b = 0
Answer: B. a = -1 with any real b, or a = 1 and b = 0
For f⁻¹ = f, we need f(f(x)) = x for all x. This gives a² = 1 and b(a + 1) = 0, so a = -1 with any b, or a = 1 and b = 0.

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