Empowering Students with AI-Powered Assessments & Intelligent Learning
Chapter Exam

Chapter 9: Tangents and Secants to a Circle — Online MCQ Test

MATHS · CLASS 10th · Telangana State Board

Practice Chapter 9: Tangents and Secants to a Circle with a free chapter-wise online MCQ test for Telangana State Board CLASS 10th MATHS. This chapter covers: This chapter investigates lines intersecting or touching a circle. Students prove that a tangent is perpendicular to the radius at the point of contact. AI-generated questions from basic to board-exam level, with instant results and explanations.

10
Questions
20m
Time Limit
3
Attempts Left
  • 10 random questions from this chapter (mixed difficulty)
  • Questions you've seen before won't repeat until the pool resets
  • You have 20 minutes — exam auto-submits when time is up
  • Maximum 3 attempts per chapter
  • Results and explanations shown immediately after submission
Login to Start This Exam →

New here? Register free — includes 3 free chapter exams.

Chapter 9: Tangents and Secants to a Circle — Important Questions & Answers (FAQ)

Frequently asked questions from Telangana State Board CLASS 10th MATHS — Chapter 9: Tangents and Secants to a Circle, with answers and explanations. These are sample questions; the exam has its own separate question set.

A tangent to a circle is a line that touches the circle at exactly _____ point(s).
  • A. one ✓
  • B. two
  • C. three
  • D. infinite
Answer: A. one
By definition, a tangent is a line that intersects a circle at exactly one point, called the point of contact or point of tangency.
The angle between a tangent and the radius at the point of contact is:
  • A. 45°
  • B. 60°
  • C. 90° ✓
  • D. 180°
Answer: C. 90°
A fundamental theorem states that the tangent to a circle is perpendicular to the radius at the point of contact, making the angle 90°.
From an external point P, two tangents are drawn to a circle with center O. If the tangents touch the circle at points A and B, then PA is _____ to PB.
  • A. greater than
  • B. less than
  • C. equal ✓
  • D. perpendicular
Answer: C. equal
The lengths of tangents drawn from an external point to a circle are equal. Therefore, PA = PB.
From an external point P, a tangent PA and a secant PBC are drawn to a circle (where B and C are on the circle). The relationship PA² = PB × PC represents:
  • A. Tangent-Secant Theorem
  • B. Power of a Point Theorem
  • C. Pythagorean Theorem
  • D. Both (a) and (b) ✓
Answer: D. Both (a) and (b)
The Power of a Point Theorem states that for a tangent and secant from the same external point, PA² = PB × PC. This is also known as the Tangent-Secant Theorem.
A circle has radius r. From an external point at distance d from the center (d > r), a tangent is drawn. The length of the tangent is:
  • A. d
  • B. √(d² + r²)
  • C. √(d² - r²) ✓
  • D. d - r
Answer: C. √(d² - r²)
If P is the external point, O is the center, and A is the point of tangency, triangle OAP is right-angled at A. By Pythagoras: PA² = PO² - OA² = d² - r², so PA = √(d² - r²).

Choose Your Plan & Start Practising

All plans cover every subject and chapter of your registered grade.

Free
₹0
3 exams · 1 year
Start Free →
Active
₹350
12 exams · 1 year
Get Active →
Pro
₹899
Unlimited exams · 1 year
Get Pro →
NEET
₹999
Unlimited exams · 1 year
Get NEET →

Compare all plans in detail →